arithmetic | Extensible arithmetic parsing lib for go | Math library
kandi X-RAY | arithmetic Summary
kandi X-RAY | arithmetic Summary
This library parses and solves a mathematical expression. It uses a Shunting-Yard algorithm (aka Reverse-Polish notation). Usual mathematic constants and functions are defined in this package (see doc). Additional can be defined using the functions RegisterVariable and RegisterFunction.
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- shuttingYard takes a list of tokens and pushes them onto the stack .
- startState returns the state for the current token .
- alphaNumState returns the state transition to a state .
- solve takes a list of tokens and returns the result .
- max returns the largest of the arguments .
- min returns the minimum of the arguments .
- RegisterAlias registers a new alias .
- mean returns the sum of args .
- if_ returns the boolean value .
- Parse parses the input and returns the result .
arithmetic Key Features
arithmetic Examples and Code Snippets
Lines of Code : 3
License : No License
Copydef arithmetic_progression(n, lim):
return list(range(n, lim + 1, n))
arithmetic_progression(5, 25) # [5, 10, 15, 20, 25]
const arithmeticProgression = (n, lim) =>
Array.from({ length: Math.ceil(lim / n) }, (_, i) => (i + 1) * n );
arithmeticProgression(5, 25); // [5, 10, 15, 20, 25]
def arithmetic_mean(series: list) -> float:
"""
return the arithmetic mean of series
>>> arithmetic_mean([2, 4, 6])
4.0
>>> arithmetic_mean([3, 6, 9, 12])
7.5
>>> arithmetic_mean(4)
Trace def is_arithmetic_series(series: list) -> bool:
"""
checking whether the input series is arithmetic series or not
>>> is_arithmetic_series([2, 4, 6])
True
>>> is_arithmetic_series([3, 6, 12, 24])
False
public static int repeatedArithmeticShift(int x, int count) {
for (int i = 0; i < count; i++) {
x >>= 1; // Arithmetic shift by 1
}
return x;
} Community Discussions
Trending Discussions on arithmetic
QUESTION
I want to create a toString function for Tuples with a variadic amount of a specific type (arithmetic types for now).
Something like this
...ANSWER
Answered 2021-Jun-16 at 03:17You can check all the types are identical or not with the help of fold expression (since C++17).
E.g.
QUESTION
So basically I am getting two string inputs in the form of coordinates as (x,y) and then I am adding the numbers from the inputted string (which are p1 and p2) to different variables and then adding those variables (which are x1,x2,y1,y2). So is there a way to add the variables together i.e perform arithmetic on the variables, (not concatenate)
...ANSWER
Answered 2021-Jun-15 at 13:14You can do this with std::stoi(). Add a line to put these strings into int variables and do your arithmetic:
int x = stoi(x1);
QUESTION
i have this code that works on Arraylist each element in the array list need to be work by ArithmeticBBB and ArithmeticCCC and create 2 elements which be returned back to the stream im using stream = stream.map(a::work); in the loop . or using flatMap
...ANSWER
Answered 2021-Jun-11 at 12:44Clearly, the code in the posted question hasn't been stripped down from actual running code, due to the number of typos and other issues. So it's impossible to tell what the actual problem was.
However, the following code does run:
QUESTION
I want to cut down the size of my metadata struct for my own heap allocator. One field in my struct holds a pointer to the next instance of the struct:
...ANSWER
Answered 2021-Mar-06 at 20:56If the memory pool was allocated as a single object (like result of a single malloc() or a global array) then pointer arithmetics can be safely used.
QUESTION
Saxon-JS enables not only to run XSLT in the browser but also to read and write HTML content. With JavaScript, checking if a class 'edited' is contained by an elements class list can be done by
...ANSWER
Answered 2021-May-04 at 08:53If you want to return any XML element that matches that condition, you could just use a standard XPath expression:
QUESTION
I'm trying to understand the behaviour of arithmetic methods in Ruby. 1 .+ 2 .* 3 and 1 .+ (2) .* 3 and 1. + 2. * 3 and 1. + (2). * 3 and 1.+2.*3 all evaluate to 7, which means :+ is called before :*, but 1.+(2).*3 evaluates to 9, which means :* is called before :+. Redefining both methods confirms that that's what's happening:
ANSWER
Answered 2021-Jun-12 at 10:44Let's give an example that might be easier to understand
QUESTION
I am trying to write a yacc program to find out whether an Arithmetic Expression is valid or not. My program seems to be running properly but I am getting a warning in console.
...ANSWER
Answered 2021-Jun-12 at 02:17Your grammar is ambiguous; E OPERATOR E can apply to a + b * c in two ways (with two different meanings), depending on whether the first E is used to derive a or a + b.
Ambiguous grammars always have conflicts, because there is always a point in the parse where the parser could use more than one conflicting action. (The inverse is not true: a grammar with a conflict is not necessarily ambiguous. That will come later in your course, I suppose.)
So if you want to eliminate the conflict, you need to choose which of the two possible derivations above is correct (and all the similar ambiguities, but since they all have the same cause a relatively simple fix is possible).
QUESTION
What Every Computer Scientist Should Know About Floating-Point Arithmetic makes the following claim:
Due to roundoff errors, the associative laws of algebra do not necessarily hold for floating-point numbers. For example, the expression (x+y)+z has a totally different answer than x+(y+z) when x = 1030, y = -1030 and z = 1 (it is 1 in the former case, 0 in the latter).
How does one reach the conclusion in their example? That is, that (x+y)+z=1 and x+(y+z)=0?
I am aware of the associative laws of algebra, but I do not see the issue in this case. To my mind, both x and y will overflow and therefore both have an integer value that is incorrect but nonetheless in range. As x and y will then be integers, they should add as if associativity applies.
...ANSWER
Answered 2021-Jan-14 at 22:56Round off error, and other aspects of floating point arithmetic, apply to floating point arithmetic as a whole. While some of the values that a floating point variable can store are integers (in the sense that they are whole numbers), they are not integer-typed. A floating point variable cannot store arbitrarily large integers, any more than an integer variable can. And while wraparound integer arithmetic will make (a+b)-a=b for any unsigned integer-typed a and b, the same is not true for floating point arithmetic. The overflow rules are different.
QUESTION
I have two models that look something like this:
...ANSWER
Answered 2021-Jun-11 at 10:25Use this my answer for extension method FilterByItems. Then you can do the following:
QUESTION
I have two months of data for two stocks as follows -
...ANSWER
Answered 2021-Jun-10 at 17:26Perhaps, the error with size mismatch can be solved if we specify the length.out in rep
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