aardvark | Expose containers to external applications via iBGP | Continuous Deployment library
kandi X-RAY | aardvark Summary
kandi X-RAY | aardvark Summary
Aardvark was built to expose containers within weave networks via iBGP to upstream route reflectors without pulling in more complex networking plugins with features we didn't need. In addition to pushing an iBGP route advertisement aardvark will also optionally replace the containers default route to egress out of the weave bridge as opposed to the docker_gwbridge. The application is meant to run on every Docker host and have access to the local Docker socket. See the included docker-compose.yml and aardvark.nomad for examples. The expanded capabilities and /proc mount are only required if you want to use the defautl route replacement functionality.
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QUESTION
I have a text file in my Assets/Resources/Text, on Start()
I want to import each line from the text file as a string in list. Using this code does it for me,
ANSWER
Answered 2021-May-29 at 04:22To begin with Don't use Reources
!
If against Unity's own recommendation you still want to do it for some reason then you have to load that resource using Resources.Load
in your case as a TextAsset
like e.g.
QUESTION
I'm making a simple Word Builder type of game (where one player enters a word, and the other player enters a word starting with the last letter of the first player's word), and I can't get the Text to show up on both the screens. I'm able to get the text to show up if I hard code it, like:
...ANSWER
Answered 2021-May-28 at 09:04UsedString
is not synchronized in your network => Each player might have a different value for UsedWorld
at the moment the RPC get called.
Why not pass on the UsedWord
as argument to OnInput
and DisplayWord
?
Also why is DisplayWord
even called via RPC at all? Since OnInput
is alreay synchronized to ALL
you could simply call the method right away
QUESTION
The partition_filter
argument in wr.s3.read_parquet()
is failing to filter a partitioned parquet dataset on S3. Here's a reproducible example (might require a correctly configured boto3_session
argument):
Dataset setup:
...ANSWER
Answered 2021-Apr-07 at 08:15From the documentation, Ignored if dataset=False.
. Adding dataset=True
as an argument to your read_parquet
call will do the trick
QUESTION
I have this exercise:
Write a recursive function that takes a string and returns all the characters that are not repeated in said string.
The characters in the output don't need to have the same order as in the input string.
First I tried this, but given the condition for the function to stop, it never evaluates the last character:
...ANSWER
Answered 2021-Mar-28 at 14:24You can try:
QUESTION
Given two strings, determine if they share a common substring. A substring may be as small as one character.
Example:
...ANSWER
Answered 2021-Mar-12 at 16:54Well you need to modify your code as following as it is more optimised:
QUESTION
According to this blog by the author of DataFrames.jl the following line of code should work select(df, :name => ByRow(split) => [:firsname, :lastname])
. However, I got an error.
Do I overlook something here?
...ANSWER
Answered 2021-Feb-15 at 19:40After reloading my environment it did work. The command works with DataFrames@0.22.5
. But I forgot to recompile the package after switching environment (I had an older version loaded due to compatibility issues with an other package).
QUESTION
I have two dataframes of different sizes. They both have four columns: Words, x, y and z.
However, when joining these two dataframes, I want to keep the values of x, y, z of the words that are similar. The words that doesn't exist in df1 but exist in df2 are kept.
I tried to use pd.merge
but this will keep the two values and only similar words. And if I use pd.concat
I have to drop similar elements, but will not be from the first data frame.
ANSWER
Answered 2021-Jan-25 at 23:33You can use df.append
to append df1
to df2
, followed by drop_duplicates
, with keep='last'
, then sort_index
and reset_index
:
QUESTION
I need to produce a hash value for a given word. the hash value need to be deterministic, or the same value for the same word, however if the given word has an different cases the hash value changes. So my objective is to convert the given word (const char) to a lower case witin the hash function, in order to obtain always the same hash code regardless the case. I have the following code:
...ANSWER
Answered 2021-Jan-12 at 13:20You won't need to modify the original string when calculating hash.
Instead of trying to modify the original string, just use the conversion result in calculation without writing it back to the original string.
QUESTION
I have a trivial R script that works nicely:
...ANSWER
Answered 2021-Jan-05 at 20:49Missing sigil:
QUESTION
newbie here. Apologies in advance if I don't use the proper terminology.
SITUATION: I'm working with my first SQL database, and the cells in one column have multiple values, many of which overlap with other cells. Here's an excerpt (I'm new to stack overflow and can't insert images yet, and I can't figure out the best way to represent the layout in text, but here's my best attempt):
...ANSWER
Answered 2020-Nov-21 at 23:25This is a generalized approach that should work with any database without modifying the schema or data. It will not perform well, however. (You could also consider a RegEx approach if your db supports it.)
Ideally you would normalize the schema, but that's often not possible.
To find records with both mammal
and carnivore
:
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