keppel | Regionally federated multi-tenant container image registry | Continuous Deployment library

by sapcc Go Version: Current License: Apache-2.0

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | keppel Summary

keppel is a Go library typically used in Devops, Continuous Deployment, Docker applications. keppel has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

When working with the container ecosystem (Docker, Kubernetes, etc.), you need a place to store your container images. The default choice is the Docker Registry, but a Docker Registry alone is not enough in productive deployments because you also need a compatible OAuth2 provider. A popular choice is Harbor, which bundles a Docker Registry, an auth provider, and some other tools. Another choice is Quay, which implements the registry protocol itself, but is otherwise very similar to Harbor. However, Harbor's architecture is limited by its use of a single registry that is shared between all users. Most importantly, by putting the images of all users in the same storage, quota and usage tracking gets unnecessarily complicated. Keppel instead uses multi-tenant-aware storage drivers so that each customer gets their own separate storage space. Storage quota and usage can therefore be tracked by the backing storage. This orchestration is completely transparent to the user: A unified API endpoint is provided that multiplexes requests to their respective registry instances.

Support

Quality

Security

License

Reuse

Support

keppel has a low active ecosystem.

It has 79 star(s) with 7 fork(s). There are 42 watchers for this library.

It had no major release in the last 6 months.

There are 2 open issues and 5 have been closed. On average issues are closed in 178 days. There are 3 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of keppel is current.

Quality

keppel has no bugs reported.

Security

keppel has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

keppel is licensed under the Apache-2.0 License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

keppel releases are not available. You will need to build from source code and install.

Top functions reviewed by kandi - BETA

kandi has reviewed keppel and discovered the below as its top functions. This is intended to give you an instant insight into keppel implemented functionality, and help decide if they suit your requirements.

filterAuthorized filters the incoming request and returns a new ScopeSet
maintainManifestBlobRefs updates the schema_blobrefs for a given manifest .
Issue new password for peer
parseRBACPolicy is a helper function to parse a RBAC policy
maintainManifestManifestRefs updates manifest_refs for a given manifest .
parseToken is used to parse a JWT token
ParseImageReference parses a string and returns an ImageReference
Filter repo actions
runPeering runs the peer
parseManifestConfig looks for an image config and returns a map of time and time .

Get all kandi verified functions for this library.

keppel Key Features

No Key Features are available at this moment for keppel.

keppel Examples and Code Snippets

No Code Snippets are available at this moment for keppel.

Community Discussions

Trending Discussions on keppel

Broken HTML tags - BeautifulSoup

ggplot2 stacked barplot: reorder bars by multiple dimensions

Remove rows from R dataset based on matching

QUESTION

Broken HTML tags - BeautifulSoup

Asked 2019-Dec-23 at 09:26

The below code perfectly scrapes the data from this website, except a few records which are contained in either broken HTML or are in different tags. Also, the initial letters for some of the names are not appearing, like for Cyclect Electrical Engineering Pte Ltd on this page How can i fix this to have all the names appearing correctly :-

...

ANSWER

Answered 2019-Dec-23 at 09:26

import requests
from bs4 import BeautifulSoup
import re


for num in range(14, 25):
    r = requests.get(f"http://www.asmi.com/index.cfm?GPID={num}")
    soup = BeautifulSoup(r.text, 'html.parser')
    names = list(dict.fromkeys([' '.join(items.split())
                                for items in soup(text=re.compile(r'Ltd\s?$'))]))
    print(names)

Source https://stackoverflow.com/questions/59450850

QUESTION

ggplot2 stacked barplot: reorder bars by multiple dimensions

Asked 2018-Apr-13 at 14:52

I have a dataset called data_words that looks as follows (these are just a few lines):

...

ANSWER

Answered 2018-Apr-13 at 14:52

Try this:

Source https://stackoverflow.com/questions/49803531

QUESTION

Remove rows from R dataset based on matching

Asked 2017-Apr-25 at 15:12

I did a word learning experiment with 54 participants. The design was such that each participant would be learning 12 cognate words and 12 non-cognate words. However, I had to remove some observations from the dataset, ending up with 1591 cognate observations and 1816 non-cognate observations.

Now, I want to calculate the correlation between scores for cognates and non-cognates. This means that I will have to reduce the 1816 non-cognate observations to 1591, because correlations are always performed with equal samples.

I could just remove rows 1592-1816, but that would not be ideal, because I would loose all non-cognates for the later participants (the data are sorted by participant number).

What I'd rather do, is loop through all the participants, and for each participant remove as many 'surplus' non-cognates so that the number of cognates and non-cognates becomes equal for that participant.

This is an example of the data for 2 participants (note that words are tested at multiple points in time, ideally this would also be taken into account when removing data):

...

ANSWER

Answered 2017-Apr-25 at 14:27

Here's my answer, it's big and weird but it loops through each user, check if Cognate or Non-cognate is more frequent and remove until it gets equal (remember to assign your data to data variable):

Source https://stackoverflow.com/questions/43612601

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install keppel

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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