weighted | high-performance common weighted algorithm library | Learning library
kandi X-RAY | weighted Summary
kandi X-RAY | weighted Summary
Package weighted implements the smooth weighted round-robin balancing algorithm. This algorithm is implemented in Nginx: Notice: The weighted is NOT goroutine-safe so you MUST use the synchronization primitive to protect it (the Next method) in concurrent cases. Algorithm is as follows: on each peer selection we increase current_weight of each eligible peer by its weight, select peer with greatest current_weight and reduce its current_weight by total number of weight points distributed among peers. In case of { 5, 1, 1 } weights this gives the following sequence of current_weight's: (a, a, b, a, c, a, a).
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of weighted
weighted Key Features
weighted Examples and Code Snippets
def standardize_weights(y,
sample_weight=None,
class_weight=None,
sample_weight_mode=None):
"""Performs sample weight validation and standardization.
Everything gets normali
def weighted_cross_entropy_with_logits_v2(labels, logits, pos_weight,
name=None):
"""Computes a weighted cross entropy.
This is like `sigmoid_cross_entropy_with_logits()` except that `pos_weight`,
allo
def weighted_moments(x, axes, frequency_weights, name=None, keep_dims=None,
keepdims=None):
"""Returns the frequency-weighted mean and variance of `x`.
Args:
x: A tensor.
axes: 1-d tensor of int32 values; these are t
Community Discussions
Trending Discussions on weighted
QUESTION
Let's say we have a students' score data df1
and credit data df2
as follows:
df1:
...ANSWER
Answered 2021-Jun-14 at 16:14QUESTION
I have 4 columns of data in a dataframe, where most of the time all 4 columns have data.
In some cases, there are empty cells in the dataframe.
How can I multiply the first 3 occurring values together regardless of their position? I have tried things like df.loc to no avail.
Data below.
...ANSWER
Answered 2021-Jun-14 at 22:19One option is stack
+ groupby head
+ prod
:
QUESTION
I need to create a slider for a game that you can set skills to each player,
The rules are :
- Each skill starts at 0.
- The skills cannot total more than 100 points at any time.
- It should always be possible to assign any 0-100 value to a given skill. Given rule (2), if this gets us over 100 total points, the excess automatically, immediately, removed from the other skills, according to their current values.
- It's not required to use all 100 points (or any).
- A skill's value is always an integer.
For example :
We start with:
Stamina: 0 | Speed: 0 | Armor: 0 | Strength: 0 | Remaining: 100The player adds 50 Speed.
Stamina: 0 | Speed: 50 | Armor: 0 | Strength: 0 | Remaining: 50The player adds 25 Armor.
Stamina: 0 | Speed: 50 | Armor: 25 | Strength: 0 | Remaining: 25 - 115The player now adds 40 Stamina. The excess is automatically reduced from the other skills, weighted by their current values.
Stamina: 40 | Speed: 40 | Armor: 20 | Strength: 0 | Remaining: 0The player then reduces Speed to 10.
Stamina: 40 | Speed: 30 | Armor: 20 | Strength: 0 | Remaining: 10Finally, the player sets Strength to 100.
Stamina: 0 | Speed: 0 | Armor: 0 | Strength: 100 | Remaining: 0
To do so i've created a function the receives 3 arguments :
- An array of values of the slider
let arrToCalc = [14,24,55,0]
- The index number of the skill (0 for Stamina, 1 for Speed ...etc)
let newValueIndex = 2
- New value for base the calculation on
let newVal = 64.
Im not sure my calculations are accurate so i'm getting partial good results.
when set to
...ANSWER
Answered 2021-Jun-13 at 06:59After calculating the total score, reduce that from 100, and store it in the variable (here extra), then run a while loop utill that value becomes 0.
In the below snippet, I am running a loop and in each iteration reducing the value by 10. You can change the reduction logic as per the requirement.
QUESTION
I have a complicated Elasticsearch query like the following example. This query has two sub queries: a weighted bool query and a decay function. I am trying to understand how Elasticsearch aggregrates the scores from each sub queries. If I run the first sub query alone (the weighted bool query), my top score is 20. If I run the second sub query alone (the decay function), my score is 1. However, if I run both sub queries together, my top score is 15. Can someone explain this?
My second related question is how to weight the scores from the two sub queries?
...ANSWER
Answered 2021-Jun-13 at 15:43I found the answer myself by reading the elasticsearch document on the usage of function_score. function_score
has a parameter boost_mode
that specifies how query score and function score are combined. By default, boost_mode
is set to multiply
.
Besides the default multiply
method, we could also set boost_mode
to avg
, and add a parameter weight
to the above decay function exp
, then the combined score will be: ( the_bool_query_score + the_decay_function_score * weight ) / ( 1 + weight )
.
QUESTION
I am making an inter-city route planning program where the graph that is formed has string-type nodes (e.g. LHR, ISB, DXB). It's undirected but weighted, and is initialized as:
...ANSWER
Answered 2021-Jun-12 at 10:47The core problem is that when we work on graphs with integer vertices, the index of the adjacency list represents the node (since the indexes are also numbers). Now instead of using adjacency list like vector > adj[N]
we can use map > adj
. Now adj["DXB"]
will contain a vector of pairs of the form which is the
for the cities connected to
"DXB"
.
If this approach seems very complex, then you use some extra memory to map a city to a number, and then you can code everything considering that the graph has integer vertices.
QUESTION
I am using lmfit for solving a non-linear optimization problem. It works fine to the point where I am trying to implement a measurement error as the standard deviation of the dependent variable y (sigma_y). My problem is, that I cannot interpret the Information criteria properly. When implementing the return (model - y)/(sigma_y)
they just raise from really low to very high values.
i.e. [left: return (model - y)
-weighting-> right: return (model - y)/(sigma_y)
]:
- chi-square 0.00159805 -> 47.3184972
- reduced chi-square 1.7756e-04 -> 5.25761080 expectation value is 1 || SO discussion
- Akaike info crit -93.2055413 -> 20.0490661 the more negative, the better
- Bayesian info crit -92.4097507 -> 20.8448566 the more negative, the better
My guess is, that this is somehow connected to bad usage of lmfit (wrong calculation of Information criteria, bad error scaling) or to a general lack of understanding these criteria (to me reduced chi-square of 5.258 (under-estimated) or 1.776e-4 (over-estimated) sounds like a really poor fit, but the plot of residuals etc. looks okay for me...)
Here is my example code that reproduces the problem:
...ANSWER
Answered 2021-Jun-12 at 02:48Well, in order for the magnitude of chi-square to be meaningful (for example, that it be around (N_data - N_varys), the scale of the uncertainties has to be correct -- giving the 1-sigma standard deviation for each observation.
It's not really possible for lmfit to detect whether the sigma you use has the right scale.
QUESTION
I am trying to add a column with the weighted average of 4 columns with 4 columns of weights
...ANSWER
Answered 2021-Jun-11 at 19:55A straight-forward and simple way to do is as follows:
(Since your columns name for the weights are not consistently named, e.g. some with 's' and some without, some with capital 'W' and some with lower case 'w', it is not convenient to group columns e.g. by .filter()
)
QUESTION
I am trying to extract lines that match two different patterns from test.txt
.
First I want to extract line that match >> fbat -v1
and then match the corresponding line just below p-value(2-sided)
.
This is the code I tried, but it only extracts the first match.
...ANSWER
Answered 2021-Jun-10 at 15:15import re
file = open('test.txt')
for idx, line in enumerate(file):
match = re.findall('^>> fbat -v1', line)
if match:
match = re.findall('p-value(2-sided)', file[idx+1])
QUESTION
I have a dataframe that looks something like this.
The tfs
column is a map of String to Long and the weights
are floats
ANSWER
Answered 2021-Jun-09 at 13:12Use map_from_arrays
,map_keys
& map_values
functions.
Try below code.
QUESTION
I am newly learning Python, and I am trying to create a bfs algorithm that can take vertices of a weighted graph and return the bfs. Eventually, I will need to add the weighted edges to the vertices so that I can calculate the distance travelled, however I am able to get the bfs to work with my vertices alone. This is the code so far:
...ANSWER
Answered 2021-Jun-08 at 23:18The problem was caused by you adding nodes, which is a list in your new data structure, to new_path
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install weighted
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page