dict | It is a English - Chinese dictionary program | Dictionary library

by yedamao Go Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | dict Summary

dict is a Go library typically used in Utilities, Dictionary, Bert applications. dict has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

It is a English - Chinese dictionary program.

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Support

dict has a low active ecosystem.

It has 15 star(s) with 2 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

There are 0 open issues and 2 have been closed. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of dict is current.

Quality

dict has no bugs reported.

Security

dict has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

dict is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

dict releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed dict and discovered the below as its top functions. This is intended to give you an instant insight into dict implemented functionality, and help decide if they suit your requirements.

Find food
roll the line
Find food
Example
Add food
Print all food
usage prints the usage of the flag .
checkError is a convenience function to print an error
init initializes flags .
autoCompletHandler handles auto completions

Get all kandi verified functions for this library.

dict Key Features

No Key Features are available at this moment for dict.

dict Examples and Code Snippets

No Code Snippets are available at this moment for dict.

Community Discussions

Trending Discussions on dict

Iterate over dictionary using comprehension to convert all datetime values to MM/DD/YYYY string

How to write Javascript recipe.components.sort((a, b) => (a.components ? 1 : 0) - (b.components ? 1 : 0)) in Python?

Filter dictionary whose values are arrays

compare values in an table in lua

Ajax request returns bad request error code

Fatest and elegent way to create a dict of dicts returning a list of data with repeated keys (two levels of key dict) from a 2d-list

TypeError: 'int' object is not subscriptable in Python Nested Lists

Plotly graph title and labels are off white color

How to Get Unique Latitude and Longitude Pair from List of Dictionary without Numpy?

Why is this Julia snippet so much slower than the Python equivalent? (with dictionaries)

QUESTION

Iterate over dictionary using comprehension to convert all datetime values to MM/DD/YYYY string

Asked 2021-Jun-16 at 02:30

I'm new to Python. I have a dictionary where some fields are dates ( datetime.datetime type) and I need to use comprehension to convert those to MM/DD/YYYY strings in a new cloned dictionary.

I was getting started with

...

ANSWER

Answered 2021-Jun-16 at 02:15

You can use a conditional expression:

Source https://stackoverflow.com/questions/67995408

QUESTION

How to write Javascript recipe.components.sort((a, b) => (a.components ? 1 : 0) - (b.components ? 1 : 0)) in Python?

Asked 2021-Jun-15 at 20:02

I have translated a program from javascript to python 3.9 and I am only missing sorting the result, but I just can't get any further.

The list consists of dicts that has an id "components", which is itself a list.

...

ANSWER

Answered 2021-Jun-15 at 17:56

For your original code:

Source https://stackoverflow.com/questions/67991155

QUESTION

Filter dictionary whose values are arrays

Asked 2021-Jun-15 at 18:35

I have data which looks like this:

...

ANSWER

Answered 2021-Jun-15 at 18:35

import numpy as np

features_dict = {
    'feat1': np.array([[0,1],[2,3],[4,5]]), 
    'feat2': np.array([[6,7],[8,9],[10,11]]),
    'feat3': np.array([1, 0, 0]),
    'feat4': np.array([[1],[2],[1]])
}

ind = features_dict['feat3'] == 0
features_dict = {k: v[ind] for k,v in features_dict.items()}

Source https://stackoverflow.com/questions/67991514

QUESTION

compare values in an table in lua

Asked 2021-Jun-15 at 14:39

I need help. I am having an table like this:

...

ANSWER

Answered 2021-Jun-15 at 14:39

You can use a numeric for loop with a negative step size to go back in your table, starting from the previous element. Check wether the achan and aseq fields exist, then compare them vs the dchan and dseq fields of your current entry.

Source https://stackoverflow.com/questions/67987091

QUESTION

Ajax request returns bad request error code

Asked 2021-Jun-15 at 11:58

I am getting a bad request response to my request. I have checked with an online JSON validator my dictionary data to be correct, and everything seems fine.

My code is the following:

...

ANSWER

Answered 2021-Jun-15 at 11:58

You are telling your server, you are sending JSON data, but the request body is not a JSON string but a url-encoded string (because that's the default behaviour of $.ajax() when you pass an object as data).

Use JSON.stringify, to pass a correct JSON body

Source https://stackoverflow.com/questions/67970587

QUESTION

Fatest and elegent way to create a dict of dicts returning a list of data with repeated keys (two levels of key dict) from a 2d-list

Asked 2021-Jun-15 at 08:39

Sorting data from huge lists with two levels of keys is helpful for interpreting dataset and calling by couple or one level of keys some slice of data, especially when creating plots.

I use a very naive and, I guess, inefficient way to create from a 2D-list of data a dict of dicts (two levels of keys) that returns a list of data. How to make this code more elegant, possibly faster and more readable? I guess using collection module but I didn't find a smart way.

Example:

...

ANSWER

Answered 2021-Jun-15 at 07:35

from itertools import groupby
first=lambda l: l[0]

def group_by_first(listo):
    grouped = groupby(sorted(listo,key=first), key=first) #  group by first elem, need to sort first
    return {k: [e[1:] for e in g] for k,g in grouped} # remove key (first elem) from values

{k: group_by_first(l) for k,l in group_by_first(listo).items()} # group first elem and then by second

Source https://stackoverflow.com/questions/67981688

QUESTION

TypeError: 'int' object is not subscriptable in Python Nested Lists

Asked 2021-Jun-15 at 08:38

In the following code, queryResult is a Nested Lists. A nested list means all of the list values had another list.

LIKE:

...

ANSWER

Answered 2021-Jun-15 at 08:38

Your list is a two level nest list. You do not need a nested loop for dispatching your values. In your first loop on queryResult you get in record the tuples. At that point record already contains what you want to get individual element by their indexes.

Source https://stackoverflow.com/questions/67972454

QUESTION

Plotly graph title and labels are off white color

Asked 2021-Jun-15 at 06:28

I have generated the below plotly graph using the code as below :

...

ANSWER

Answered 2021-Jun-15 at 06:28

There are several themes you can try out. If you use 'solar', you will get the color you want. The source of the theme can be found here for your reference.

Source https://stackoverflow.com/questions/67980812

QUESTION

How to Get Unique Latitude and Longitude Pair from List of Dictionary without Numpy?

Asked 2021-Jun-15 at 05:52

I have this list of dict:

...

ANSWER

Answered 2021-Jun-15 at 05:35

You can make use of a frozenset() for this

Source https://stackoverflow.com/questions/67980525

QUESTION

Why is this Julia snippet so much slower than the Python equivalent? (with dictionaries)

Asked 2021-Jun-15 at 03:46

I have the following code in Python Jupyter:

...

ANSWER

Answered 2021-Jun-14 at 18:48

Since you are benchmarking in a top-level scope you have to interpolate variables in @btime with $ so the way to benchmark your code is:

Source https://stackoverflow.com/questions/67975102

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install dict

You can download it from GitHub.

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