Lilium | Someone quetions and Someone Answers | Automation library
kandi X-RAY | Lilium Summary
kandi X-RAY | Lilium Summary
这是一个有人可以提问,也可以有人回答的*简单知识问答网站*。 + 它的前身是 flask-todo , 用来熟练ORM和SQLAlchemy的例子 + 和MyFlask . 用来熟悉sqlite3和简单的逻辑 + 这个项目是一边学一边写的。还有很多功能可以添加,前端页面也有很多可以改进的地方。. 基本的网站功能: + 1.注册 + 2.登陆 + 3.主页(登陆者可以看到自己问的问题列表,和自己参与回答的问题列表) + 4.找回密码 (真的会发送“密码”给注册邮箱哦,然而只有密码,蠢笑。以后再改XD ). 登陆之后网站功能: + 1. 题库: 可以看到其他人所提出的问题,也可以自己提问 + 2. 单个问题页面:由题库跳转过来,可以添加自己的回答,像超简陋的论坛(蠢笑) + 3. 设置: 目前只有重设密码的功能 + 4. 退出: 清除session, 会跳转到登陆页面. 管理员的设置功能: + 1 管理员的账号是 admin ,可以考虑在用户角色db_Models.USER 那里加一个角色标签,表示用户是vip,管理员,普通用户等 + 2 查看用户列表,可以修改,增加,删除其他用户。建议不要删掉自己。.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Lilium
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Community Discussions
Trending Discussions on Lilium
QUESTION
I have the following pandas data frame:
...ANSWER
Answered 2019-Jun-26 at 11:23First idea is add from right side space by Series.radd
, what is not added to values with missing values:
QUESTION
import React from 'react'
import {withProvider} from './TProvider';
import ThreeCardMap from './ThreeCardMap';
const one = Math.floor(Math.random()*21 + 0);
const two = Math.floor(Math.random()*21 + 0);
const three = Math.floor(Math.random()*21 + 0);
const styles = {
color: 'black'
}
const ThreeCardDisp = (props) => {
let cardArray;
if (props.list.cards) {
props.list.cards.filter(list => list.value_int === one)
console.log(props.list.cards)
// props.list.cards = props.list.cards[one];
cardArray = props.list.cards.map((card) =>{return ()})
cardArray.filter(list => list.value_int === one )
}
console.log (cardArray);
return (
{props.list ?
Three Card Map
{cardArray} :
loading
}
)
}
export default withProvider(ThreeCardDisp)
...ANSWER
Answered 2019-Mar-08 at 19:06.filter
returns a new array instead of modifying the one you called it on. So the line
QUESTION
I want to search between 2 tables but that field i want to search is foreign key in other table
my tables are like this:
table 1
...ANSWER
Answered 2018-Jun-07 at 10:37You can use either of these methods:
Returns only t1 fields
SELECT * FROM Table1 t1
WHERE t1.ID in (SELECT ID FROM Table2);
Returns ALL fields
SELECT * FROM Table1 t1
JOIN Table2 t2 on t1.ID = t2.ID;
If your 'values' exist in a separate table (tblValues), you can use any of these:
Returns tblValues fields
SELECT * FROM tblValues tval
WHERE tval.ID in (SELECT TitleSR FROM Table1);
returns ALL fields
SELECT * FROM (tblValues tval
JOIN Table1 t1 on tval.ID = t1.TitleSR)
JOIN Table2 on tval.ID = Table2.TitleSR;
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