math-api | Put LaTeX Math equation on everywhere as img tag | Math library
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kandi X-RAY | math-api Summary
Place LaTeX Math equation on anywhere as tag.
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QUESTION
Say I have the following function:
...ANSWER
Answered 2020-Oct-04 at 04:15QUESTION
CUDA supports mathematical functions. But do they provide any guarantee like if I compute sin(x)
the result would the closet representable value to the mathematical value of sin(x)
? If the answer is no, is there any alternative if we want to stay in GPU? Something like it always return an upper bound or always a lower bound (but possibly not the closest possible one).
ANSWER
Answered 2020-Jan-31 at 10:23CUDA Appendix Suggests that the value provided by the API are not accurate. There is a difference of, 1/2 ulps in their value. (when compared between host and device).
However, for all practical purposes, these values are accurate.
Anyway if you want to perform symbolic operations with high-level precision, using float precision makes it inaccurate.
QUESTION
I'm trying to find ways to avoid thread divergence (branching or warp divergence) in my CUDA kernel.
For instance, I have the following conditional assignment (a
and b
are char
values, x
and y
are unsigned int
values):
ANSWER
Answered 2019-Sep-19 at 19:34As a helpful comment pointed out, I was overthinking the problem. The following works, and uses a simple bool to int conversion:
QUESTION
I am trying to understand how to use the math functions from the CUDA library. I use this documentation: https://docs.nvidia.com/cuda/cuda-math-api/
I am going to describe my problem, but I think this can be generalized with any function from the CUDA library.
I have this piece of code:
...ANSWER
Answered 2019-Jul-28 at 23:50The kernel will compile if you cast the argument to the type indicated in the CUDA math API documentation:
QUESTION
Looking at Cuda-Math-Api documentation, functions
__frcp_rd
compute 1/x in a round-down mode__frcp_rn
compute 1/x in a round-to-nearest-even mode__frcp_ru
compute 1/x in a round-up mode__frcp_rz
compute 1/x in round-towards-zero mode
But what do those "modes" mean? If I were to divide '1/3' what would each function produce?
Googling for "rounding modes of reciprocal" didn't return any results
...ANSWER
Answered 2019-Mar-05 at 10:45Presumably FP rounding mode.
The exact result is usually between two representable float values, and the rounding mode determines which of the two is picked. So the difference between 2 rounding modes will be 1 unit in the last place (of the significand aka mantissa), or 0 if they round the same way.
QUESTION
From the documentation of __ddiv_ru I expect that the following code result is ceil(8/32) = 1.0, instead I obtain 0.25.
...ANSWER
Answered 2018-Dec-28 at 07:35The result you are obtaining is correct.
The intrinsic you are using implements double precision division with a specific IEEE 754-2008 rounding mode for the unit in the last place (ULP) of the significand. This controls what happens when a result cannot be exactly represented in the selected format. In this case you have selected round up, which means the last digit of the significand produced in the division result is rounded up (toward +∞). In your case all rounding modes should produce the same result because the result can be exactly represented in IEEE 754 binary64 format (it is a round power of 2).
Please read everything here before writing any more floating point code.
QUESTION
I am trying to do some FP16 work that will have both CPU and GPU backend. I researched my options and decided to use CUDA's half precision converter and data types. The ones I intent to use are specified as both __device__
and __host__
which according to my understanding (and the official documentation) should mean that the functions are callable from both HOST and DEVICE code. I wrote a simple test program:
ANSWER
Answered 2018-May-30 at 13:32Ideas?
Switch to CUDA 9.2
Your code compiles without error on CUDA 9.2, but throws the errors you indicate on CUDA 9.1. If you have CUDA 9.1 installed, then the documentation for it is already installed on your machine. On a typical linux install, it will be located in /usr/local/cuda-9.1/doc
. If you look at /usr/local/cuda-9.1/doc/pdf/CUDA_Math_API.pdf
you will see that the corresponding functions are only marked __device__
, so this change was indeed made between CUDA 9.1 and CUDA 9.2
QUESTION
So, I want to divide me some 32-bit unsigned integers on a GPU, and I don't care about getting an exact result. In fact, let's be lenient and suppose I'm willing to accept a multiplicative error factor of upto 2, i.e. if q = x/y I'm willing to accept anything between 0.5*q and 2*q.
I haven't yet measured anything, but it seems to me that something like this (CUDA code) should be useful:
...ANSWER
Answered 2017-Mar-01 at 15:57Going via floating point gives you a much more precise result, slightly lower instruction count on most architectures, and potentially a higher throughput:
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