RecordView | Simple Audio Recorder View with `` hold to Record Button | iOS library
kandi X-RAY | RecordView Summary
kandi X-RAY | RecordView Summary
A Simple Audio Recorder View with hold to Record Button and Swipe to Cancel.
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Top functions reviewed by kandi - BETA
- Handle touch
- Called when record button is pressed
- An animation animation
- Called when the record button is down
- Initializes the instance
- Initialize the media recorder
- Starts the recorder
- Initialize view
- Set the left margin of the dialog s right text view
- Initializes the view
- Initializes this RecordLockView
- Override in order to draw the bottom lock
- Converts ppx to dp
- Sets the color of the lock
RecordView Key Features
RecordView Examples and Code Snippets
Community Discussions
Trending Discussions on RecordView
QUESTION
I have created s custom UI and assigned it to the camera overlay of UIImagePickerController as below.
Custom View
...ANSWER
Answered 2021-Apr-19 at 09:32I checked whether the phone has a notch
QUESTION
I'm trying to understand why my instances of Navigator
are being reset when I add them to the UI tree. Currently I have a view that looks like this:
ANSWER
Answered 2020-Dec-07 at 13:17I figured it out. I had to assign a unique global key to each navigator and also use the IndexedStack
to ensure the navigators aren't reset by removing and re-adding them to the UI.
QUESTION
I'm working on my first Flutter project having spent many years on Objective-C and Swift so I'm very much learning the quirks of Dart vs the languages I'm familiar with. Currently I'm trying to follow the patterns I'm seeing in Dart and Flutter to add a builder to a class like this:
...ANSWER
Answered 2020-Nov-16 at 02:24Solved it. The problem turned out to be that when I created the _GroupedByDateWidget
State
instance I didn't also specify the generic qualification to it that I'd added. So it instantiated a state with an dynamic generic and failed.
So:
QUESTION
I have two models related with a foreign key (employee):
...ANSWER
Answered 2020-Nov-03 at 13:23can you try this way?
QUESTION
When a user wants to create a new record, I'd like to a) go to a new view, b) create the record during .onAppear
, and then c) have the view update using the newly created record.
The first part is easy. I have a NavigationLink
that goes to the new view along with the user name as a property. And I can create a new record during .onAppear
. But it's the last part where things get tricky.
I have tried to create the record and switch views with a simultaneous gesture, I've tried loading the new view with a toggle view function, and about a dozen less inspired ideas. The problem always comes down to this: How do I get the FetchRequest to update after the new record has been created? Note: I need a reference to the newly created record so that the user can add things to the record.
Here's the code so far...
...ANSWER
Answered 2020-Aug-02 at 10:04I am a bit confused about the bit where you say you want to create a record onAppear whilst a user created a record? Anyways I would probably create a variable for the text and have it set to the new record inside the onAppear function. Although the whole onAppear create record still confuses me and might make the implementation of the variable more difficult.
QUESTION
I'm trying to update a view in Swift and I can't figure out how to make it work. My app has questions, which are loaded from Core data. From there, a random question should be displayed at the top. After saving the answer (by pressing the Button with action: save), a new random question should be displayed.
...ANSWER
Answered 2020-May-30 at 11:14Try the following (scratchy)
QUESTION
Bonjour! The problem is that I cannot manage to populate my table view with data. Although it is correct in a way, I realized that the program puts one view over another again and again. Below, I provide pieces of code which are definitely related to the problem
...ANSWER
Answered 2020-Mar-03 at 18:02Because of cells reusing, when you add subview to your cell this is not a new cell every time, sometimes it's reusing one. In this case, much better to have record view as cell property and assign new record to this property. In this case you'll avoid multiple subviews here. Also, I don't actually understand why you hide cell in prepareForReuse, it's strange and unnecessary behavior.
QUESTION
I want to display a list of CoreData records stored as NSManagedObjects.
I want to do something like this:
...ANSWER
Answered 2020-Feb-09 at 19:19As NSManagedObject
is reference type, you can simply use self
for each as id like below
QUESTION
I have a fragment that starts a count and changes an icon status. After opening the app there is a count - 00:00 and a button that says START.
After clicking START the counts starts and the button changes to STOP.
After clicking STOP the count stops and the button changes to START. Pretty basic.
The thing is that after clicking START and minimalizing the app and opening it back (putting app in background and back) the count and button is always reverted back to START and 00:00.
So the question is: How can I keep the fragment alive after minimalizing the app?
Code:
...ANSWER
Answered 2020-Jan-18 at 22:50If you minimize the app while running, the android operating system can terminate your app and restart it when the user returns to it. You cannot guarantee it will remain in memory. If there is any data that needs to be maintained, you are responsible for saving it in the state handlers.
If you wish to have some process continue in the background, you'll need to start an Android Service and your fragment will need to communicate with it. The Fragment is just the UI piece of the app.
QUESTION
I'm new to Django
and I'm trying to make a very simple app for my coworkers to submit their tasks on a client and how long took them to fulfill their task.
I can submit to my model through the admin page fine but I can't submit it as a form through the HTML page.
I'm using django-autocomplete-light
which is working fine as well.
ANSWER
Answered 2019-Aug-28 at 11:03You construct a ClientModel
with:
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