mercator | produce graph model projections of infrastructure | Graph Database library
kandi X-RAY | mercator Summary
kandi X-RAY | mercator Summary
Mercator creates graph-model projections of physical, virtual and cloud infrastructure. Mercator uses Neo4j, a particularly awesome open-source graph database. It is intended to be used as a library inside of other services and tools.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of mercator
mercator Key Features
mercator Examples and Code Snippets
function transverseMercatorRaw(lambda, phi) {
return [log(tan((halfPi$2 + phi) / 2)), -lambda];
}
function mercatorRaw(lambda, phi) {
return [lambda, log(tan((halfPi$2 + phi) / 2))];
}
Community Discussions
Trending Discussions on mercator
QUESTION
I am trying to render the world map with elevation data using D3.
For this I use Natural Earth 50m land geojson : https://github.com/martynafford/natural-earth-geojson/tree/master/50m/physical
And Natural Earth elevation raster data : https://www.naturalearthdata.com/downloads/50m-raster-data/50m-shaded-relief/
I am using this tutorial : https://datawanderings.com/2020/08/08/raster-backgrounds/
So I first found the bounds of the geojson :
...ANSWER
Answered 2022-Mar-20 at 08:06A Mercator is usually clipped at roughly 85 degrees North/South (~85.05113 N/S) - as further than this you get a map that is taller than it is wide, and one that gets much much taller for every extra degree north/south included in the extent..
D3 clips features using this limit:
The spherical Mercator projection. Defines a default projection.clipExtent such that the world is projected to a square, clipped to approximately ±85° latitude.
The northern bounds are fine, but the southern bounds of the geojson is -89.998926
degrees which you use to cut the image. But as D3 clips the geojson, your stretching the image by a different amount as compared with the geojson, hence the issue you see.
The solution should be to clip the image to a bounds that is representative of the limits of what D3 will render for a Mercator (85.05113
degrees south) not the limits of the data itself.
I haven't looked up how faithfully gdal implements EPSG:3395 as the definition provides for a projected bounds of 80 degrees south and 84 degrees north - though looking at the image, this doesn't appear to be an issue.
You can also use the cleaner fitSize methods for D3 projections (d3v4+):
QUESTION
I'm using VegaLite and VegaDatasets to show a Mercator projection of the world map, and plot a point at a specific latitude and longitude. So far, this works to produce the map:
...ANSWER
Answered 2022-Mar-11 at 01:08For plotting geoshape and geopoint in VegaLite, you should specify the coordinate by longitude
and latitude
. So your last code should be (projection should be included):
QUESTION
I recently started using the stars R package. I'm struggling with reassigning NA values to "Unknown". I found a potential solution here, but it doesn't seem to work on NAs. Any suggestions to fix this issue are greatly appreciated. for some reason SO doesn't like huge chunks of code without adding more information, so i'm adding some random text at the bottom.
Here's the code that I used:
...ANSWER
Answered 2022-Mar-09 at 21:24Okay actually it is very simple. Kind of cumbersome but it works like this:
QUESTION
I've downloaded a world map and want to change it from the default CRS (EPSG:4326) to the WGS 84 / Pseudo-Mercator projection used in applications like Tableau and Google Maps (EPSG:3857). For some reason, when I attempt the transformation, the longitude and latitude numbers become inflated.
For example, (-95.160, -95.102) becomes (-10593226.108, -10586797.584)
...ANSWER
Answered 2022-Jan-25 at 09:373857
is in meter and 4326
are in degree. Are you close to peter island ?
You can test your coords here if needed : https://epsg.io/map#srs=3857&x=-10093891.770199&y=-10709420.049722&z=12&layer=streets
QUESTION
I've got an SVG map and I want to show a specific city using ID in HTML with specified width and height. How can I accomplish this?
Here is the SVG Image:
...ANSWER
Answered 2022-Jan-20 at 08:27The 17.3 Linking into SVG content: IRI fragments and SVG views section of the SVG specification may contain what you need.
For instance, you can get the bounds of the SVG element(s) you want to focus on and use a link such as:
QUESTION
I'm using a Web Mercator image to cover a sphere. My shader takes a plane with an image and turns it into sphere. The only issue is that The resulting sphere ends up with countries stretched (like the united states).
I've figured out that I can use an equlateral image of earth to get the desired effect of non-stretched countries
Question
For my project I only have web mercator imagery and I've been struggling with the math for getting my shader to show countries at their correct scale. How can I transform mercator lat lon to equilateral lat lon for writing to my shader ?
NOTE
Everything I would need seems to be on this question about mercator projection to equirectangular but for whatever reason it's just not clicking.
Some Code
plane script
...ANSWER
Answered 2022-Jan-14 at 16:17This question is related to a much larger tile-based earth question which I still haven't solved
BUT
I was able to figure out how to solve this sub-question by using math from a potentially helpful answer I mentioned earlier in the OP
The SolutionI took the some of the shader code from @Pluto's answer and merged it in with my current shader. I assigned a web mercator image to a plane that also had this shader attached to it. The default "Projection" shader param is 0
so everything is already set to convert the mercator image to equirectangular and viola~ the image is rendered as equirectangular on a sphere.
MercatorBender.shader
QUESTION
I would like to extract the unit of measurement (decimal degrees, metres, feet, etc.) from a spatial object in R. For example, if I have an SF data frame that uses the WGS84 co-ordinate reference system (EPSG:4326), I would like to be able to determine that the co-ordinates are specified in decimal degrees. Similarly, I'd like to be able to determine that UTM co-ordinates (e.g. EPSG:32615) are specified in metres.
I have tried using the st_crs()
function from the sf
package, which returns the co-ordinate reference system in well-known text format. However, I'm struggling to be certain that a regex that extracts the unit of measurement from that well-known text will operate reliably for a wide range of co-ordinate systems.
Is there an existing function that returns the measurement unit for a spatial object?
For example, the following code produces an SF data frame that uses the WGS84 co-ordinate system:
...ANSWER
Answered 2021-Dec-21 at 15:05st_crs()
has a parameters
argument that returns a list of useful CRS parameters when TRUE
, including the units of the CRS. Here's an example with the built-in nc
data:
QUESTION
Im trying to display a France map based on the Datamaps plugin. with all the attempts i tried i couldn't succeed.
This is my HTML :
...ANSWER
Answered 2021-Nov-03 at 01:58You appear to be setting the center of the map in the wrong place as you are only using FRA (France) data. The centre should be about 2, 46 not 78.9629, 23.5937. The first value is longitude then latitude.
QUESTION
Let's say I have a GeoDataFrame
with a CRS
set.
ANSWER
Answered 2021-Nov-01 at 14:04.crs
returns a pyroj.CRS object. This should get you the EPSG code from the object:
QUESTION
I’m trying to convert a full globe Robinson Projection to Mercator. For example, I use this image.
First, I apply geo-tagging:
gdal_translate -a_ullr -180 90 180 -90 -a_srs ESRI:54030 source.jpg source_tagged.tif
and finally warp it to Mercator:
gdalwarp -t_srs ESRI:54030 -s_srs EPSG:3857 source_tagged.tif target.tif
The outcome is slightly stretched vertically but nowhere near proper Mercator. What am I doing wrong?
...ANSWER
Answered 2021-Oct-13 at 22:02There are a couple of issues in your commands. The first is that -180 90 isn't in the top left corner pixel of global Robinson projection GeoTIFFs. The top left corner would be something like -338.2187147689 90, and the bottom right would be 338.2187147689 -90. However, you're also specifying your srs as ESRI:54030, so those bounds need to be in projected coordinates, not lat/lons. The command to generate a GeoTIFF from your image would be:
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