Louis | Miasto Kreatywne | iOS library
kandi X-RAY | Louis Summary
kandi X-RAY | Louis Summary
1st prize at Kraków Miasto Kreatywne 2016. App uses Microsoft Cognitive Services in order to get mood from taken selfie. App tries to filter as much as possible events nearby, customize user's culture needs.
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Top functions reviewed by kandi - BETA
- Override this method to be overridden to implement getActivityResult
- Convert a Uri to an Observable
- Called when an activity has been detected
- Region SwipeDelegate
- Gets list of property items
- Initialize this instance
- Returns a new instance of this FragmentBase
- Updates the map location
- Sets up the map
- Initializes this Component
- Installs the local properties
- Start loop
- Called when the proposition is pressed
- Called when the fragment is created
- Request Location updates
- Pretty print a collection
- Setup broadcast from a location service
- Called when a Location is received
- Method to detect face analysis
- Creates the view for the activity s fragment
- Writes the object into Parcel object
- Convert a drawable to a Bitmap
- Resize the bitmap
- Region View
- Checks if the location is better than the current location
- Get a card view
Louis Key Features
Louis Examples and Code Snippets
Community Discussions
Trending Discussions on Louis
QUESTION
I have two large-ish data frames I am trying to append...
In df1, I have state codes, county codes, state names (Alabama, Alaska, etc.), county names, and years from 2010:2020.
In df2, I have county names, state abbreviations (AL, AK), and data for the year 2010 (which I am trying to merge into df1. The issue lies in that without specifying the state name and simply merging df1 and df2, some of the data which I am trying to get into df1 is duplicated due to there being some counties with the same name...hence, I am trying to also join by state to prevent this, but I have state abbreviations, and state names.
Is there any way in which I can make either the state names in df1 abbreviations, or the state names in df2 full names? Please let me know! Thank you for the help.
Edit: dput(df2)
...ANSWER
Answered 2022-Apr-18 at 03:52Here's one way you could turn state abbreviations into state names using R's built in state vectors:
QUESTION
ANSWER
Answered 2022-Mar-23 at 07:27Use DataFrame.stack
for MultiIndex Series
, assign repeated values of Pr Unit Cos
and then Series.to_dict
:
QUESTION
I'm working on a dataset that can have a lot of duplicates, and I want to deduplicate it based on 2 columns, and take the first non null value of each row in every 'group' of duplicates. The only problem is that there are two 'ID' columns that I don't want to lose any information from.
EDIT: to explain it a bit better. We assume that all rows that have the same combination of name/city are the same person. I want to have as few rows as possible in the dataset without losing any information from my_first_id
and my_second_id
.
Here is an example of my data:
...ANSWER
Answered 2022-Feb-17 at 09:45I came up with a solution. I'm using groupby and then check for each group if I actually want to deduplicate it or not. It seems highly inefficient but it does the trick. If someone can come up with a better solution, I will gladly accept it.
First, we add columns to count the number of unique IDs per group, and columns containing a boolean indicating if for each row, there is an ID or not. And lastly, a count of number of IDs per row (useful for sorting the dataframe later).
QUESTION
I have a text file containing x,y,z coordinates of different points. Following is the format of the input file:
...ANSWER
Answered 2022-Feb-05 at 00:59A shorter version:
QUESTION
I am looking for a way to apply different Pandas groupby functions (like "mean", "min" or "max") on columns, depending on the beginning of their names.
The way I proceed at the present time is described as follows:
- dynamically create lists of columns that start with X, Y or ...
- dynamically create lists of functions to apply to each group of columns
- merge the lists of columns with their corresponding functions into dictionaries
- merge the dictionaries into the "agg" function:
ANSWER
Answered 2022-Jan-11 at 16:11The way you do it is quite pythonic, to be honest. You might do it with nested dict comprehension, if you want to compress and automatise it:
QUESTION
My problem is pretty simple but I want your advice on the matter! I have an excel document that contains 2 sheets... The first sheet look like this :
...ANSWER
Answered 2022-Jan-05 at 19:50First of all, assuming your data is in excell file, you should be able to read that. Install openpyxl:
pip install openpyxl
Now Here is my solution to print
similar values in console.
I assume that in Sheet2
, all names are in this format:
last_name, first_name
and in Sheet1
, all names are in this format:
first_name last_name
So here is a pythonic solution to do what you want:
QUESTION
I've been trying to solve the following problem : I try to upgrade this Frontend Mentor project https://haydee75.github.io/galleria/ from React Router v5 to v6. I tried to replace the code between with :
...ANSWER
Answered 2021-Dec-09 at 18:01If I'm understanding your question/issue correctly, you want to render the Gallery
and Paint
components each on their own routes independently, and fix the slideshow linking from painting to painting. For this use the first routing snippet so they are independent routes and not nested.
QUESTION
Im working through some self-join examples and I am drawing a blank on the following example. Its the last example at the following link Self-Join Example
...ANSWER
Answered 2021-Nov-26 at 15:51If you didn't have any condition on employee ID at all you'd end up with records where a self-match had occurred, e.g. the results would show "Gracie Gardner was hired on the same day as Gracie Gardner"
We could then put ON e1.employee_id <> e2.employee_id
- this would prevent Gracie matching with Gracie, but you'd then find "Gracie Gardner was hired on the same day as Summer Payne" and "Summer Payne was hired on the same day as Gracie Gardner" - i.e. you'd get "duplicate records" in terms of "person paired with person", each name being mentioned both ways round
Using greater than prevents this, and effectively means that any given pair of names only appears once. Because Gracie's ID is less than Summer's, you'll get Gracie in e1
paired with Summer in e2
but you won't get Summer in e1
paired with Gracie in e2
Another way of visualizing it is with a square/matrix
QUESTION
I have to manipulate data in this wonderful language which is javascript. Until there I managed to achieve what I needed on my own but I reached my limits there.
It's quite hard to explain how my data is structured so let's make a schema. This is what I have :
...ANSWER
Answered 2021-Nov-25 at 15:13I think you're looking for the following (seeing as you have TypeScript in the title of your question):
QUESTION
I've read in two .jpg files using image_read
(from the magick
package) and then used cat
and image_ocr
to extract text from both and combine them into one return. This does return the text, but with quite a few errors that will need rectified using regular expressions. However, I can't seem to use the regular expressions and have it return the text again. This was originally showing the class of the vector as "NULL", so I added in the as.character
function to my preceding code hoping that would allow me to return the text after using regular expressions, but it only returns "character(0)" now. I have tried using lapply
to convert the vector to character, and tried using unlist(text)
to see if that helped, but got similar results. Here is what I have currently:
ANSWER
Answered 2021-Nov-15 at 01:50Solved in commments:
You need to use either c(image_ocr(text.1), (image_ocr(text.2)))
OR paste(image_ocr(text.1), (image_ocr(text.2)))
, depending on whether you want a vector or one long character string.
The cat(...)
function is Concatenate and Print and will not return your string. (See ?cat()
for details)
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install Louis
You can use Louis like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Louis component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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