baritone | google maps for block game | Video Game library
kandi X-RAY | baritone Summary
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- Updates the movement state
- Checks if a horizontal block is visible
- Determines whether a node is a block position or not
- Checks if the horizontal block is visible
- This method is called when the best path is found
- Finds the best path
- Returns the lowest element with the lowest path
- Command action
- Recalculates and recalculates the coordinates
- Update move state
- Performs a move on the destination
- Performs a list of Waypoint components
- Called when a player update
- Returns a list of positions of the specified block
- Execute the installation
- Move the current position of the player
- Updates the move state based on the current position
- Command line
- Saves the settings
- Performs a heartbe command
- Pack a CachedChunk
- Updates move state based on destination position
- Called when a new item is available
- Updates the move state
- CommandLineWidth
- Command for bar commands
baritone Key Features
baritone Examples and Code Snippets
Trending Discussions on baritone
Trending Discussions on baritone
QUESTION
So, basically, I'm making a website where you can search for Minecraft hacked clients. There is a search bar on the website, but you have to search in exact terms (different topic lol). Basically on the click of a button (search button) I then want to filter using the search term, (not automatically as I have it now) I've been searching but cant find a way to do it.
Code ->
import CountUp from 'react-countup';
import { Link } from 'react-router-dom';
import '../App.css';
/*Components ->*/
import Client from '../components/client.js'
function App() {
const [search, setSearch] = React.useState({
searchname: ''
});
**Array containing client data ->** const [client, setClient] = React.useState([
{ safestatus: 'safe-status-green', safe: 'Safe (Verified)', name: 'Impact', price: 'Free', mcversion: '1.11.2 - 1.16.5', type: 'Injected', compat: 'None (Stand alone client)', desc: 'The Impact client is an advanced utility mod for Minecraft, it is packaged with Baritone and includes a large number of useful mods.', screen: 'https://impactclient.net/', download: 'https://impactclient.net/'},
{ safestatus: 'safe-status-green', safe: 'Safe (Verified)', name: 'Future', price: '15€', mcversion: '1.8.9 - 1.14.4', type: 'Injected', compat: 'None (Stand alone client)', desc: 'Vanilla, OptiFine, Forge and Liteloader support, Easy to use account manager, Auto-reconnect mod.', screen: 'https://www.futureclient.net/', download: 'https://www.futureclient.net/'}
]);
const updateSearch = (event) => {
event.persist();
setSearch((prev) => ({
...prev,
[event.target.name]: event.target.value
}));
};
return (
Hacked HubAbout Us | FAQ
+
hacked clients and counting...
Free
Paid
Safe
Probably Safe
Not Safe (BE CAREFUL!)
1.8.9
1.12.2
1.16.5
1.17+
Injected
Mod
With Most Other Clients
Stand Alone
⚠ WARNING ⚠ Only download clients you know are 100% safe! If we do find a client that is a rat / virus / BTC miner we will tag it as UNSAFE IMMEDIATELY. The saftey warnings for clients are MERE RECCOMENDATIONS, please do thorough research before downloading any hacked client that you are not 100% sure is safe. This page is also in development, meaning features are prone to break! So be careful!!!
Sponsored clients
None XD
Submitted clients
{client
**Filtering the array then mapping it -> (This i want to do onClick)** .filter((client) => client.name === search.searchname)
.map((client, index) => {
return (
);
})}
);
}
export default App;
Anyone know how I could do this onClick?
ANSWER
Answered 2021-Oct-05 at 23:48Use two pieces of state; one to track the value in your text field and the other to store the search term for filtering. Only set the latter when you click your button
const [ searchValue, setSearchValue ] = React.useState("")
const [ searchTerm, setSearchTerm ] = React.useState("")
const filteredClient = React.useMemo(() => {
if (searchTerm.length > 0) {
return client.filter(({ name }) => name === searchTerm)
}
return client
}, [ searchTerm, client ])
and in your JSX
setSearchValue(e.target.value)}
/>
setSearchTerm(searchValue)}
>Search
{filteredClient.map((client, index) => (
))}
QUESTION
I'm trying to make a minecraft plugin. I want it to create variable for every player. I'm using "for" for the loop. I'm trying to add the player's name to the variable's name. Can anyone help?
String name = "";
for (Player p : Bukkit.getOnlinePlayers()) {
name = p.getName();
int cheatdetection+name = 0;
int looking = (Math.round(p.getLocation().getPitch()) + 270) % 360;
int currentlooking = looking;
try {
Thread.sleep(10);
} catch (InterruptedException e) {
if(looking > currentlooking+20 || looking < currentlooking-20) {
cheatdetection+name++;
}
}
if(cheatdetection >= 10) {
Bukkit.getBanList(Type.NAME).addBan(p.getName(), "You have been banned for using Baritone", todate1, "HackMiner Detection");
p.kickPlayer("HackMiner Detection");
}
}
ANSWER
Answered 2021-Feb-11 at 09:17It sounds like you want a Map with a key for every player. A Map creates an association between one variable (a key) and another (a value). Values are set using the put(key, value) method, and they retrieved using 'get(key)'
// Create an Integer counter for every player, initialized to zero.
Map playerCheatCounter = new HashMap<>();
for (Player p : Bukkit.getOnlinePlayers()) {
playerCheatCounter.put(p, 0);
}
// Now to use it:
for (Player p : Bukkit.getOnlinePlayers()) {
int looking = p.getPitch();
Thread.sleep(10)
int currentlyLooking = p.getPitch();
if (looking > currentlyLooking + 20) {
// Increment counter for the current player
playerCheatCounter.put(p, 1 + playerCheatCounter.get(p));
// Check the stored value for the current player
if (playerCheatCounter.get(p) > 10) {
// Ban player
}
}
}
Edit: Fixed some syntax errors
QUESTION
I am trying to convert a string with consecutive duplicate characters to it's 'dictionary' word. For example, 'aaawwesome' should be converted to 'awesome'.
Most answers I've come across have either removed all duplicates (so 'stations' would be converted to 'staion' for example), or have removed all consecutive duplicates using itertools.groupby()
, however this doesn't account for cases such as 'happy' which would be converted to 'hapy'.
I have also tried using string intersections with Counter()
, however this disregards the order of the letters so 'botaniser' and 'baritones' would match incorrectly.
In my specific case, I have a few lists of words:
list_1 = ["wife", "kid", "hello"]
list_2 = ["husband", "child", "goodbye"]
and, given a new word, for example 'hellllo', I want to check if it can be reduced down to any of the words, and if it can, replace it with that word.
ANSWER
Answered 2020-Nov-16 at 19:28use the enchant module, you may need to install it using pip
See which letters duplicate, remove the letter from the word until the word is in the English dictionary.
import enchant
d = enchant.Dict("en_US")
list_1 = ["wiffe", "kidd", "helllo"]
def dup(x):
for n,j in enumerate(x):
y = [g for g,m in enumerate(x) if m==j]
for h in y:
if len(y)>1 and not d.check(x) :
x = x[:h] + x[h+1:]
return x
list_1 = list(map(dup,list_1))
print(list_1)
>>> ['wife', 'kid', 'hello']
QUESTION
I have discogs data about artists who perform on jazz albums and would like to create network maps of these individuals. Sample data are provided below. I need to compute all possible pairs of artists on a given album. To illustrate the desired result, the figure below shows the original data (left side) and how additional rows must be added to achieve a unique set of all possible pairs WITHIN an album. Additional information on role must be retained. In the example shown, there are originally 12 records for three albums. The restructured data will have 31 records and the same columns.
A post here seems similar but deals with data in a different structure.
jnet<-structure(list(leadArtist = c("Milt Jackson", "Milt Jackson",
"Milt Jackson", "Milt Jackson", "Milt Jackson", "Milt Jackson",
"Milt Jackson", "Milt Jackson", "Milt Jackson", "Milt Jackson",
"Milt Jackson", "Milt Jackson"), albumid = c(2460190, 2460190,
2460190, 2460190, 444693, 444693, 444693, 3019083, 3019083, 3019083,
3019083, 3019083), extraArtists = c("Sahib Shihab", "Art Blakey",
"Horace Silver", "Joe Newman", "Steve Novosel", "Vinnie Johnson",
"Johnny O'Neal", "Percy Heath", "Lawrence Marable", "Skeeter Best",
"John Lewis (2)", "Lucky Thompson"), role = c("Baritone Saxophone",
"Drums", "Piano", "Trumpet", "Bass", "Drums", "Piano", "Bass",
"Drums", "Guitar", "Piano", "Tenor Saxophone")), row.names = c(NA,
-12L), class = c("tbl_df", "tbl", "data.frame"))
ANSWER
Answered 2020-Jan-30 at 18:25Here is at least one way.
Pairs = matrix("", nrow=0, ncol=2)
for(AID in unique(jnet$albumid)) {
Selector = jnet$albumid == AID
Artists = unique(c(jnet$leadArtist[Selector],
jnet$extraArtists[Selector]))
Pairs = rbind(Pairs, t(combn(Artists, 2)))
}
head(Pairs)
[,1] [,2]
[1,] "Milt Jackson" "Sahib Shihab"
[2,] "Milt Jackson" "Art Blakey"
[3,] "Milt Jackson" "Horace Silver"
[4,] "Milt Jackson" "Joe Newman"
[5,] "Sahib Shihab" "Art Blakey"
[6,] "Sahib Shihab" "Horace Silver"
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