baritone | google maps for block game | Video Game library

 by   cabaletta Java Version: v1.9.2 License: LGPL-3.0

kandi X-RAY | baritone Summary

baritone is a Java library typically used in Telecommunications, Media, Media, Entertainment, Gaming, Video Game, Minecraft applications. baritone has no bugs, it has no vulnerabilities, it has build file available, it has a Weak Copyleft License and it has medium support. You can download it from GitHub.
A Minecraft pathfinder bot. Baritone is the pathfinding system used in Impact since 4.4. There's a showcase video made by @Adovin#0730 on Baritone which I recommend. Here's a (very old!) video I made showing off what it can do. Tutorial playlist. The easiest way to install Baritone is to install Impact, which comes with Baritone. The second easiest way (for 1.12.2 only) is to install the v1.2.* api-forge jar from releases. For 1.12.2 Forge, just click here. Otherwise, see Installation & setup. Once Baritone is installed, look here for instructions on how to use it. For 1.15.2, click here and see description. If you need Forge 1.15.2, look here, follow the instructions, and get the api-forge jar.
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                      kandi-support Support

                        summary
                        baritone has a medium active ecosystem.
                        summary
                        It has 5492 star(s) with 1346 fork(s). There are 114 watchers for this library.
                        summary
                        There were 7 major release(s) in the last 6 months.
                        summary
                        There are 651 open issues and 2722 have been closed. On average issues are closed in 102 days. There are 45 open pull requests and 0 closed requests.
                        summary
                        It has a neutral sentiment in the developer community.
                        summary
                        The latest version of baritone is v1.9.2
                        baritone Support
                          Best in #Video Game
                            Average in #Video Game
                            baritone Support
                              Best in #Video Game
                                Average in #Video Game

                                  kandi-Quality Quality

                                    summary
                                    baritone has 0 bugs and 0 code smells.
                                    baritone Quality
                                      Best in #Video Game
                                        Average in #Video Game
                                        baritone Quality
                                          Best in #Video Game
                                            Average in #Video Game

                                              kandi-Security Security

                                                summary
                                                baritone has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
                                                summary
                                                baritone code analysis shows 0 unresolved vulnerabilities.
                                                summary
                                                There are 0 security hotspots that need review.
                                                baritone Security
                                                  Best in #Video Game
                                                    Average in #Video Game
                                                    baritone Security
                                                      Best in #Video Game
                                                        Average in #Video Game

                                                          kandi-License License

                                                            summary
                                                            baritone is licensed under the LGPL-3.0 License. This license is Weak Copyleft.
                                                            summary
                                                            Weak Copyleft licenses have some restrictions, but you can use them in commercial projects.
                                                            baritone License
                                                              Best in #Video Game
                                                                Average in #Video Game
                                                                baritone License
                                                                  Best in #Video Game
                                                                    Average in #Video Game

                                                                      kandi-Reuse Reuse

                                                                        summary
                                                                        baritone releases are available to install and integrate.
                                                                        summary
                                                                        Build file is available. You can build the component from source.
                                                                        summary
                                                                        Installation instructions, examples and code snippets are available.
                                                                        summary
                                                                        baritone saves you 9651 person hours of effort in developing the same functionality from scratch.
                                                                        summary
                                                                        It has 20195 lines of code, 1896 functions and 307 files.
                                                                        summary
                                                                        It has medium code complexity. Code complexity directly impacts maintainability of the code.
                                                                        baritone Reuse
                                                                          Best in #Video Game
                                                                            Average in #Video Game
                                                                            baritone Reuse
                                                                              Best in #Video Game
                                                                                Average in #Video Game
                                                                                  Top functions reviewed by kandi - BETA
                                                                                  kandi has reviewed baritone and discovered the below as its top functions. This is intended to give you an instant insight into baritone implemented functionality, and help decide if they suit your requirements.
                                                                                  • Updates the movement state
                                                                                    • Checks if a horizontal block is visible
                                                                                    • Determines whether a node is a block position or not
                                                                                    • Checks if the horizontal block is visible
                                                                                  • This method is called when the best path is found
                                                                                    • Finds the best path
                                                                                    • Returns the lowest element with the lowest path
                                                                                  • Command action
                                                                                    • Recalculates and recalculates the coordinates
                                                                                  • Update move state
                                                                                  • Performs a move on the destination
                                                                                  • Performs a list of Waypoint components
                                                                                  • Called when a player update
                                                                                  • Returns a list of positions of the specified block
                                                                                  • Execute the installation
                                                                                  • Move the current position of the player
                                                                                  • Updates the move state based on the current position
                                                                                  • Command line
                                                                                  • Saves the settings
                                                                                  • Performs a heartbe command
                                                                                  • Pack a CachedChunk
                                                                                  • Updates move state based on destination position
                                                                                  • Called when a new item is available
                                                                                  • Updates the move state
                                                                                  • CommandLineWidth
                                                                                  • Command for bar commands
                                                                                  Get all kandi verified functions for this library.
                                                                                  Get all kandi verified functions for this library.

                                                                                  baritone Key Features

                                                                                  google maps for block game

                                                                                  baritone Examples and Code Snippets

                                                                                  No Code Snippets are available at this moment for baritone.
                                                                                  Community Discussions

                                                                                  Trending Discussions on baritone

                                                                                  How to filter an array on click in react?
                                                                                  chevron right
                                                                                  How to add variable value to the name of another variable in java?
                                                                                  chevron right
                                                                                  Convert consecutive duplicate character string to known word
                                                                                  chevron right
                                                                                  How to compute all member pairs for network analysis?
                                                                                  chevron right

                                                                                  QUESTION

                                                                                  How to filter an array on click in react?
                                                                                  Asked 2021-Oct-05 at 23:48

                                                                                  So, basically, I'm making a website where you can search for Minecraft hacked clients. There is a search bar on the website, but you have to search in exact terms (different topic lol). Basically on the click of a button (search button) I then want to filter using the search term, (not automatically as I have it now) I've been searching but cant find a way to do it.

                                                                                  Code ->

                                                                                  import CountUp from 'react-countup';
                                                                                  import { Link } from 'react-router-dom';
                                                                                  import '../App.css';
                                                                                  
                                                                                  /*Components ->*/
                                                                                  import Client from '../components/client.js'
                                                                                  
                                                                                  function App() {
                                                                                  
                                                                                      const [search, setSearch] = React.useState({
                                                                                          searchname: ''
                                                                                      });
                                                                                  
                                                                                      **Array containing client data ->** const [client, setClient] = React.useState([
                                                                                          { safestatus: 'safe-status-green', safe: 'Safe (Verified)', name: 'Impact', price: 'Free', mcversion: '1.11.2 - 1.16.5', type: 'Injected', compat: 'None (Stand alone client)', desc: 'The Impact client is an advanced utility mod for Minecraft, it is packaged with Baritone and includes a large number of useful mods.', screen: 'https://impactclient.net/', download: 'https://impactclient.net/'},
                                                                                          { safestatus: 'safe-status-green', safe: 'Safe (Verified)', name: 'Future', price: '15€', mcversion: '1.8.9 - 1.14.4', type: 'Injected', compat: 'None (Stand alone client)', desc: 'Vanilla, OptiFine, Forge and Liteloader support, Easy to use account manager, Auto-reconnect mod.', screen: 'https://www.futureclient.net/', download: 'https://www.futureclient.net/'}
                                                                                          
                                                                                      ]);
                                                                                  
                                                                                      const updateSearch = (event) => {
                                                                                          event.persist();
                                                                                          setSearch((prev) => ({
                                                                                              ...prev,
                                                                                              [event.target.name]: event.target.value
                                                                                            }));
                                                                                      };
                                                                                      
                                                                                    return (
                                                                                      
                                                                                          Hacked HubAbout Us | FAQ
                                                                                          +
                                                                                          hacked clients and counting...
                                                                                          
                                                                                              
                                                                                              
                                                                                                  Free
                                                                                                  Paid
                                                                                              
                                                                                              
                                                                                                  Safe
                                                                                                  Probably Safe
                                                                                                  Not Safe (BE CAREFUL!)
                                                                                              
                                                                                              
                                                                                                  1.8.9
                                                                                                  1.12.2
                                                                                                  1.16.5
                                                                                                  1.17+
                                                                                              
                                                                                              
                                                                                                  Injected
                                                                                                  Mod
                                                                                              
                                                                                              
                                                                                                  With Most Other Clients
                                                                                                  Stand Alone
                                                                                              
                                                                                              ⚠ WARNING ⚠ Only download clients you know are 100% safe! If we do find a client that is a rat / virus / BTC miner we will tag it as UNSAFE IMMEDIATELY. The saftey warnings for clients are MERE RECCOMENDATIONS, please do thorough research before downloading any hacked client that you are not 100% sure is safe. This page is also in development, meaning features are prone to break! So be careful!!!
                                                                                              Sponsored clients
                                                                                                  None XD
                                                                                              Submitted clients
                                                                                                  {client
                                                                                                      **Filtering the array then mapping it -> (This i want to do onClick)** .filter((client) => client.name === search.searchname)
                                                                                                      .map((client, index) => {
                                                                                                          return (
                                                                                                              
                                                                                                          );
                                                                                                      })}
                                                                                              
                                                                                      
                                                                                    );
                                                                                  }
                                                                                  
                                                                                  export default App;
                                                                                  

                                                                                  Anyone know how I could do this onClick?

                                                                                  ANSWER

                                                                                  Answered 2021-Oct-05 at 23:48

                                                                                  Use two pieces of state; one to track the value in your text field and the other to store the search term for filtering. Only set the latter when you click your button

                                                                                  const [ searchValue, setSearchValue ] = React.useState("")
                                                                                  const [ searchTerm, setSearchTerm ] = React.useState("")
                                                                                  
                                                                                  const filteredClient = React.useMemo(() => {
                                                                                    if (searchTerm.length > 0) {
                                                                                      return client.filter(({ name }) => name === searchTerm)
                                                                                    }
                                                                                    return client
                                                                                  }, [ searchTerm, client ])
                                                                                  

                                                                                  and in your JSX

                                                                                   setSearchValue(e.target.value)}
                                                                                  />
                                                                                  
                                                                                  
                                                                                  
                                                                                   setSearchTerm(searchValue)}
                                                                                  >Search
                                                                                  
                                                                                  
                                                                                  
                                                                                  {filteredClient.map((client, index) => (
                                                                                    
                                                                                  ))}
                                                                                  

                                                                                  Source https://stackoverflow.com/questions/69457630

                                                                                  QUESTION

                                                                                  How to add variable value to the name of another variable in java?
                                                                                  Asked 2021-Feb-11 at 09:17

                                                                                  I'm trying to make a minecraft plugin. I want it to create variable for every player. I'm using "for" for the loop. I'm trying to add the player's name to the variable's name. Can anyone help?

                                                                                  String name = "";
                                                                                              for (Player p : Bukkit.getOnlinePlayers()) {
                                                                                                  name = p.getName();
                                                                                                  int cheatdetection+name = 0;
                                                                                                  int looking = (Math.round(p.getLocation().getPitch()) + 270) % 360;
                                                                                                  int currentlooking = looking;
                                                                                                  try {
                                                                                                      Thread.sleep(10);
                                                                                                  } catch (InterruptedException e) {                      
                                                                                                      if(looking > currentlooking+20 || looking < currentlooking-20) {
                                                                                                          cheatdetection+name++;
                                                                                                      }
                                                                                                  }
                                                                                                  if(cheatdetection >= 10) {
                                                                                                      Bukkit.getBanList(Type.NAME).addBan(p.getName(), "You have been banned for using Baritone", todate1, "HackMiner Detection");
                                                                                                      p.kickPlayer("HackMiner Detection");
                                                                                                  }
                                                                                              }
                                                                                  

                                                                                  ANSWER

                                                                                  Answered 2021-Feb-11 at 09:17

                                                                                  It sounds like you want a Map with a key for every player. A Map creates an association between one variable (a key) and another (a value). Values are set using the put(key, value) method, and they retrieved using 'get(key)'

                                                                                  // Create an Integer counter for every player, initialized to zero.
                                                                                  Map playerCheatCounter = new HashMap<>();
                                                                                  for (Player p : Bukkit.getOnlinePlayers()) {
                                                                                     playerCheatCounter.put(p, 0);
                                                                                  }
                                                                                  
                                                                                  // Now to use it:
                                                                                  for (Player p : Bukkit.getOnlinePlayers()) {
                                                                                    int looking = p.getPitch();
                                                                                    Thread.sleep(10)
                                                                                    int currentlyLooking = p.getPitch();
                                                                                    if (looking > currentlyLooking + 20) {
                                                                                      // Increment counter for the current player
                                                                                      playerCheatCounter.put(p, 1 + playerCheatCounter.get(p));
                                                                                      // Check the stored value for the current player
                                                                                      if (playerCheatCounter.get(p) > 10) {
                                                                                       // Ban player
                                                                                      }
                                                                                    }
                                                                                   }
                                                                                  

                                                                                  Edit: Fixed some syntax errors

                                                                                  Source https://stackoverflow.com/questions/66151070

                                                                                  QUESTION

                                                                                  Convert consecutive duplicate character string to known word
                                                                                  Asked 2020-Nov-16 at 19:28

                                                                                  I am trying to convert a string with consecutive duplicate characters to it's 'dictionary' word. For example, 'aaawwesome' should be converted to 'awesome'.

                                                                                  Most answers I've come across have either removed all duplicates (so 'stations' would be converted to 'staion' for example), or have removed all consecutive duplicates using itertools.groupby(), however this doesn't account for cases such as 'happy' which would be converted to 'hapy'.

                                                                                  I have also tried using string intersections with Counter(), however this disregards the order of the letters so 'botaniser' and 'baritones' would match incorrectly.

                                                                                  In my specific case, I have a few lists of words:

                                                                                  list_1 = ["wife", "kid", "hello"]
                                                                                  list_2 = ["husband", "child", "goodbye"]
                                                                                  

                                                                                  and, given a new word, for example 'hellllo', I want to check if it can be reduced down to any of the words, and if it can, replace it with that word.

                                                                                  ANSWER

                                                                                  Answered 2020-Nov-16 at 19:28

                                                                                  use the enchant module, you may need to install it using pip

                                                                                  See which letters duplicate, remove the letter from the word until the word is in the English dictionary.

                                                                                  import enchant
                                                                                  d = enchant.Dict("en_US")
                                                                                  list_1 = ["wiffe", "kidd", "helllo"]
                                                                                  
                                                                                  def dup(x):
                                                                                      for n,j in enumerate(x):
                                                                                          y = [g for g,m in enumerate(x) if m==j]
                                                                                          for h in y:
                                                                                              if len(y)>1 and not d.check(x) :
                                                                                                  x = x[:h] + x[h+1:]
                                                                                                  return x
                                                                                  
                                                                                  list_1 = list(map(dup,list_1))
                                                                                  
                                                                                  print(list_1)
                                                                                  
                                                                                  >>> ['wife', 'kid', 'hello']
                                                                                  
                                                                                  

                                                                                  Source https://stackoverflow.com/questions/64862333

                                                                                  QUESTION

                                                                                  How to compute all member pairs for network analysis?
                                                                                  Asked 2020-Jan-30 at 18:25

                                                                                  I have discogs data about artists who perform on jazz albums and would like to create network maps of these individuals. Sample data are provided below. I need to compute all possible pairs of artists on a given album. To illustrate the desired result, the figure below shows the original data (left side) and how additional rows must be added to achieve a unique set of all possible pairs WITHIN an album. Additional information on role must be retained. In the example shown, there are originally 12 records for three albums. The restructured data will have 31 records and the same columns.

                                                                                  A post here seems similar but deals with data in a different structure.

                                                                                  jnet<-structure(list(leadArtist = c("Milt Jackson", "Milt Jackson", 
                                                                                  "Milt Jackson", "Milt Jackson", "Milt Jackson", "Milt Jackson", 
                                                                                  "Milt Jackson", "Milt Jackson", "Milt Jackson", "Milt Jackson", 
                                                                                  "Milt Jackson", "Milt Jackson"), albumid = c(2460190, 2460190, 
                                                                                  2460190, 2460190, 444693, 444693, 444693, 3019083, 3019083, 3019083, 
                                                                                  3019083, 3019083), extraArtists = c("Sahib Shihab", "Art Blakey", 
                                                                                  "Horace Silver", "Joe Newman", "Steve Novosel", "Vinnie Johnson", 
                                                                                  "Johnny O'Neal", "Percy Heath", "Lawrence Marable", "Skeeter Best", 
                                                                                  "John Lewis (2)", "Lucky Thompson"), role = c("Baritone Saxophone", 
                                                                                  "Drums", "Piano", "Trumpet", "Bass", "Drums", "Piano", "Bass", 
                                                                                  "Drums", "Guitar", "Piano", "Tenor Saxophone")), row.names = c(NA, 
                                                                                  -12L), class = c("tbl_df", "tbl", "data.frame"))
                                                                                  

                                                                                  ANSWER

                                                                                  Answered 2020-Jan-30 at 18:25

                                                                                  Here is at least one way.

                                                                                  Pairs = matrix("", nrow=0, ncol=2)
                                                                                  for(AID in unique(jnet$albumid)) {
                                                                                      Selector = jnet$albumid == AID
                                                                                      Artists = unique(c(jnet$leadArtist[Selector], 
                                                                                                   jnet$extraArtists[Selector]))
                                                                                      Pairs = rbind(Pairs, t(combn(Artists, 2)))
                                                                                  }
                                                                                  head(Pairs)
                                                                                       [,1]           [,2]           
                                                                                  [1,] "Milt Jackson" "Sahib Shihab" 
                                                                                  [2,] "Milt Jackson" "Art Blakey"   
                                                                                  [3,] "Milt Jackson" "Horace Silver"
                                                                                  [4,] "Milt Jackson" "Joe Newman"   
                                                                                  [5,] "Sahib Shihab" "Art Blakey"   
                                                                                  [6,] "Sahib Shihab" "Horace Silver"
                                                                                  

                                                                                  Source https://stackoverflow.com/questions/59991892

                                                                                  Community Discussions, Code Snippets contain sources that include Stack Exchange Network

                                                                                  Vulnerabilities

                                                                                  No vulnerabilities reported

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