kandi X-RAY | medusa Summary
kandi X-RAY | medusa Summary
When medusa archive is unzipped the following files will be extracted:.
Top functions reviewed by kandi - BETA
- The main entry point
- Runs the scaffolds
- Reads a MongoGraph from a file
- Writes the given graph to the given file
- Read node order
- Get the out edges of a node
- Compares this node to another
- Given a node return a String representation of the original
- Computes the cover
- Return true if the edge is not a Vine
- Reads the graph from information file
- Adds an edge to this node
- Get a list of all subChains
- Create a hash code
- Computes the cover between two groups
- Compare two edges
- Set the label info
- Read the contig info of the contig
- Remove cycles
- Deduplicates all the edges in this graph
- Computes a cover for this graph
- Compares this edge to another Edge
- Parses the specified file and returns a HashMap of IDs
- Compute error errors
- Reads the contig order from the specified file and returns a HashMap of the contiggers
- Merge two components
medusa Key Features
medusa Examples and Code Snippets
Trending Discussions on medusa
I'm trying to create models from my Oracle database 10g using Entity Framework Core 5
ANSWERAnswered 2021-May-05 at 06:07
The fine manual says minimum oracle 11.2 for that provider
Upgrade your db or change provider
I am just starting to master modular applications and I have a problem with the logback.
Before modularity was introduced into the project, Logback successfully worked with the same settings.
As soon as I start working with the LoggerContext and add the line
requires ch.qos.logback.classic to the
module-info.java, the application crashes.
Crash occurs in the line receiving the logger:...
ANSWERAnswered 2021-Apr-14 at 14:28
It is a bug in logback 1.3.0-alpha5
I am reading File that contains...
ANSWERAnswered 2021-Apr-12 at 17:05
This code reads your file and stores the data in the
Info using stringstreams and other things to parse.
I have generated three classes from XSD schema:...
ANSWERAnswered 2021-Feb-17 at 12:50
We are missing the
medusa initialization code, but you should do something like this:
I have a text file with many rows that generally follow the patterns shown below and I'd like to extract the segments numbered 1-4 in the image below. I cannot do it with Excel because the punctuation is not sufficiently consistent so I'd like to use RegEx.
I am looking for 4 distinct RegEx expressions, corresponding to the 4 items.
What I have so far:
(.+?(?=/))gets me everything up to the
/but I can't figure out how to split it in the Yellow and Cyan sections
(?<=\/\s)(.*)gets me everything after the
/but includes the Mintmark portion
Here is a good sample of the file contents:...
ANSWERAnswered 2021-Jan-26 at 20:49
You could use a single pattern with 4 capturing groups.
I have ansible role which checks the latest backups from my databases (cassandra and elasticsearch) so i have this output...
ANSWERAnswered 2021-Jan-05 at 15:19
If the output of the
ansible-playbook other/check_backup_status.yml -i hosts/mvd/prod/hosts.yml command goes to the standard output, I can redirect that output to awk in the next way:
I have an online store and am trying to display five similar products on the product page. There is a many-to-many relationship between products and tags which I'm trying to query (join table) using
INNER JOIN. Here is the SQL query I have thus far:
ANSWERAnswered 2020-Nov-21 at 18:30
You can group by product and sort the results by the number of matched tags:
ANSWERAnswered 2020-Oct-22 at 09:30
I think a lot of what you did, specifically around data wrangling, was not necessary, especially since you called
d3.cluster() afterwards. I've replaced this with
d3.stratify (which deals with hierarchical data that is not yet in the right format).
I've also replaced
d3.tree() because it was unclear to me why you'd want to use
d3.cluster here. Your data has multiple parents, multiple roots and even floating nodes, and d3 is not meant to deal with that. My workaround has been to attach pseudonodes to every level, so as to make sure that there is only one node and that all nodes are at the right level at all times. To make sure the links were drawn correctly, I've written a custom
getLinks function, that can deal with multiple parents.
I've also written a custom link generator that draws the links somewhat in the way that you want them. d3 doesn't offer much of flexibility here, but you can use the source code for inspiration.
I've changed the logic to be more focused on which "partners" got a child, so both links to the same child are on the same level - like in your picture. I've also drawn the nodes based on how many partners they have, and have given every link an offset so the lines are more distinct.
I've sorted the nodes so that the real pro-creators are at the top (Zeus), which gives a more balanced and less crowded view.
this.statues.shift(); is isolating the correct element and removing it from the array. When this happens though, person.stoned needs to be false. Any pointers? Thank you.
ANSWERAnswered 2020-Jul-18 at 22:14
You need to save shifted object and set its property, like that:
This is a question from the 2019 Australian Informatics Olympiad Competition:
After the success of your latest research project in mythical DNA, you have gained the attention of a most diabolical creature: Medusa. Medusa has snakes instead of hair. Each of her snakes’ DNA is represented by an uppercase string of letters. Each letter is one of S, N, A, K or E. Your extensive research shows that a snake’s venom level depends on its DNA. A snake has venom level x if its DNA:
• has exactly 5x letters • begins with x copies of the letter S
• then has x copies of the letter N
• then has x copies of the letter A
• then has x copies of the letter K
• ends with x copies of the letter E.
For example, a snake with venom level 1 has DNA SNAKE, while a snake that has venom level 3 has DNA SSSNNNAAAKKKEEE. If a snake’s DNA does not ﬁt the format described above, it has a venom level of 0. Medusa would like your help making her snakes venomous, by deleting zero or more letters from their DNA. Given a snake’s DNA, can you work out the maximum venom level this snake could have?
Is it possible using binary search to obtain an algorithm with complexity O(nlogn)?...
ANSWERAnswered 2020-Jul-14 at 14:05
Yes you can use binary search to search for maximum venom level.
when for some
m=(l+r+1)/2 we can check in
O(n) time if we can obtain such venom level m, just by taking first
S then next m letters
N and so on. If there's not enough letters we update our search interval to
Example: suppose input is
- Binary search initial values:
m = (l+r+1)/2 = 8
- we cant get venom value of 8 so
r=m-1 = 7
m = (l+r+1)/2 = 4
- we cant get venom value of 4 so
r=m-1 = 3
m = (l+r+1)/2 = 2
- we can get venom value of 2 so
l=m = 2
m = (l+r+1)/2 = 3
- we cant get venom value of 3 so
r=m-1 = 2
- now since
l==rwe terminate binary search and conclude that answer is
No vulnerabilities reported
You can use medusa like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the medusa component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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