ced | project started as an April Fool | Learning library

I'm currently working in my company developing an API in Spring Boot with an Oracle database, the problem is that we use liquibase to create the database, and when I try to use the command:

I'm trying to plot 10+ scatter plots on one page using Plotly. However, I've noticed that if more than 8 plots are created, some of the plots show a square with a frowny face. I've read that this means Chrome failed to render the chart.

It does not matter how complex the chart is. Even 9 basic charts will cause one not to render. See below for example with code to replicate the issue:

https://codepen.io/ceds/pen/wvrGoLa

HTML

Intuitively I feel like I have a problem that can be solved with recursion, however, after staring at this for several days I cannot find the first thread to pull and start the process of tackling it.

I'd love any help you can offer both with how to approach this problem and break it down for solving it and for solving itself. I'm currently attempting to solve this in javascript.

Given a list of objects like this:

[enter image description here][1]Good morning everyone, please I am reading a file that has multiple entries, I am supposed to get an appSessionId from the first entry line then look for the requestMap in the next line that has the same appSessionId.

Here is my code:

I'm trying to connect to a service running on a google cloud platform VM from the ssh terminal.

The running process is listening on 7076 as shown here:

I use laravel 7. I want to add additional modal with value before submit. When I try to update data without additional modal, the update works correctly. But when I add the additional modal with value, the program success but my update not works correnctly. This is my form (blade view):

I have 10 variables, called rows($row1, $row2, $row3...), I need the user to choose from one of this variables only knowing the right row, I'm struggling to understand how to connect text to a variable, that corrisponds to another variable and get the value, not to write it as text

I am trying to write a query to get the 3rd merchant with the highest lifetime transaction amount. Also, I have to provide the total transactions to date for this merchant.

This is the create table statement.

It is different from the coin-changing problem link.

Given a dict x=[a:1,b:2,c:1,d:3,e:2], I need to calculate all possible combinations of the keys such that the sum of the values associated with those keys just exceeds or equals a given value, say 5. Just exceeding 5 means that if the selected elements are lower than 5, we can add one more element even if it exceeds 5 but once we exceed or equal 5, no more elements can be added.

There are two issues that are complicating my approach -

1. Note that some of the values are repeated-e.g. 1 and 2 each occurs twice and they need to be considered separately.
2. Ordering matters in this case.

Ordering matters too so [b,c,d], [b,d,c], [c,b,d], [c,d,b], [d,b,c], [d,c,b] are all included separately. Ideally ordering matters only when we are exceeding 5 and as long as the sum is exactly 5, ordering doesn't matter.

So some of the solution to the above question are [a,b,c,d] with sum 7, [a,b,c,e] with sum 6, [b,c,d] with sum 6, [d,e] with sum 5 etc.

How do I approach the problem. I was thinking of using the output from coin changing and then adding one element to each of the resulting lists, but that will not cover all the cases.

EDIT 1: A better way of framing the question might be to find all combinations such that the sum (i) equals 5 or (ii) just exceeds 5 as the sum until the second last element was less than 5 and therefore adding the last element made it greater than 5. Once we have 5 or >5, no additional elements will be added.

EDIT 2: Clarifying the ordering issue. To give a bit of context, the keys are devices and the values are the resources it needs. And the total resources available is 5. And the devices are allocated resources as per their keys i.e. the first key-value pair will be serviced first (sorted as per the key alphabetically). For b, it needs 2 but say only 1 resource is available - it will be assigned 1 and the remaining 1 will be assigned in the next run (spillover). So when the sum is exactly 5, the order doesn't matter as each gets whatever it wanted and there is no spillover to the next slot. E.g. ed and de means both get what they wanted so they should both be included. But for lists that exceed 5 just due to the addition of the last element, ordering matters as spillover will happen only for the last element. E.g. dce means d and c get 3 and 1 respectively, and e gets only 1 (with 1 spilling into next run). Similarly ced means c and d get 1 and 3 respectively, with spillover happening for d as it only gets assigned 1.