Dictionary | offline Dictionary App for Android | Dictionary library

 by   rdoeffinger Java Version: v5.6.2 License: Apache-2.0

kandi X-RAY | Dictionary Summary

kandi X-RAY | Dictionary Summary

Dictionary is a Java library typically used in Utilities, Dictionary applications. Dictionary has build file available, it has a Permissive License and it has low support. However Dictionary has 17 bugs and it has 1 vulnerabilities. You can download it from GitHub.

"QuickDic" offline Dictionary App for Android. Provided downloadable dictionaries are based on Wiktionaries but can also be created from other sources (see DictionaryPC). Remember to use --recursive when cloning! Fork of project that used to be hosted at code.google.com/p/quickdic-dictionary.
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            kandi-support Support

              Dictionary has a low active ecosystem.
              It has 260 star(s) with 67 fork(s). There are 16 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 48 open issues and 81 have been closed. On average issues are closed in 328 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Dictionary is v5.6.2

            kandi-Quality Quality

              OutlinedDot
              Dictionary has 17 bugs (4 blocker, 0 critical, 3 major, 10 minor) and 234 code smells.

            kandi-Security Security

              Dictionary has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Dictionary code analysis shows 1 unresolved vulnerabilities (0 blocker, 0 critical, 0 major, 1 minor).
              There are 3 security hotspots that need review.

            kandi-License License

              Dictionary is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Dictionary releases are available to install and integrate.
              Build file is available. You can build the component from source.
              Dictionary saves you 3678 person hours of effort in developing the same functionality from scratch.
              It has 7855 lines of code, 329 functions and 90 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed Dictionary and discovered the below as its top functions. This is intended to give you an instant insight into Dictionary implemented functionality, and help decide if they suit your requirements.
            • Initializes the DictionaryView
            • Creates the setup action bar and search view
            • Display a long - clicked language button
            • Find insertion point index
            • Creates the context menu
            • Show the HTML
            • Jump to the selected text
            • Replies the token row
            • Read an object from cache
            • Writes the dictionary information
            • Callback method for when a preference tree is clicked
            • Close the surface
            • OnCreateContextMenu
            • Sets up the options menu
            • Writes the RTF table to the specified output stream
            • Resume the activity
            • Called when the search finished
            • Create dictionary preferences
            • Handle soft keyboard input
            • Invoked when the shared preference has been changed
            • Append the content to a StringBuilder
            • Initialize the dictionary dialog
            • Creates the Options menu
            • Creates the row for the dictionary manager
            • Performs a multi word search
            • Initializes the activity
            Get all kandi verified functions for this library.

            Dictionary Key Features

            No Key Features are available at this moment for Dictionary.

            Dictionary Examples and Code Snippets

            Flatten a nested dictionary .
            pythondot img1Lines of Code : 31dot img1License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def flatten_dict_items(dictionary):
              """Returns a dictionary with flattened keys and values.
            
              This function flattens the keys and values of a dictionary, which can be
              arbitrarily nested structures, and returns the flattened version of such
              str  
            Recursively update fields in a nested dictionary .
            pythondot img2Lines of Code : 21dot img2License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def _pyval_update_fields(pyval, fields, depth):
              """Append the field values from `pyval` to `fields`.
            
              Args:
                pyval: A python `dict`, or nested list/tuple of `dict`, whose value(s)
                  should be appended to `fields`.
                fields: A dictionary   
            Create a csv from a dictionary .
            pythondot img3Lines of Code : 21dot img3License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def write_csv_from_dict(filename, input_dict):
              """Writes out a `.csv` file from an input dictionary.
            
              After writing out the file, it checks the new list against the golden
              to make sure golden file is up-to-date.
            
              Args:
                filename: String th  

            Community Discussions

            QUESTION

            Iterate over dictionary using comprehension to convert all datetime values to MM/DD/YYYY string
            Asked 2021-Jun-16 at 02:30

            I'm new to Python. I have a dictionary where some fields are dates ( datetime.datetime type) and I need to use comprehension to convert those to MM/DD/YYYY strings in a new cloned dictionary.

            I was getting started with

            ...

            ANSWER

            Answered 2021-Jun-16 at 02:15

            QUESTION

            update json list from a list
            Asked 2021-Jun-15 at 21:24

            how to update json list / array?

            ...

            ANSWER

            Answered 2021-May-06 at 15:35

            Since your data seems simple, you can open you data using pandas, do whatever operation you need and then use to_json() function to save again.

            Here is the example

            Source https://stackoverflow.com/questions/67403211

            QUESTION

            General approach to parsing text with special characters from PDF using Tesseract?
            Asked 2021-Jun-15 at 20:17

            I would like to extract the definitions from the book The Navajo Language: A Grammar and Colloquial Dictionary by Young and Morgan. They look like this (very blurry):

            I tried running it through the Google Cloud Vision API, and got decent results, but it doesn't know what to do with these "special" letters with accent marks on them, or the curls and lines on/through them. And because of the blurryness (there are no alternative sources of the PDF), it gets a lot of them wrong. So I'm thinking of doing it from scratch in Tesseract. Note the term is bold and the definition is not bold.

            How can I use Node.js and Tesseract to get basically an array of JSON objects sort of like this:

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:17

            Tesseract takes a lang variable that you can expand to include different languages if they're installed. I've used the UB Mannheim (https://github.com/UB-Mannheim/tesseract/wiki) installation which includes a ton of languages supported.

            To get better and more accurate results, the best thing to do is to process the image before handing it to Tesseract. Set a white/black threshold so that you have black text on white background with no shading. I'm not sure how to do this in Node, but I've done it with Python's OpenCV library.

            If that font doesn't get you decent results with the out of the box, then you'll want to train your own, yes. This blog post walks through the process in great detail: https://towardsdatascience.com/simple-ocr-with-tesseract-a4341e4564b6. It revolves around using the jTessBoxEditor to hand-label the objects detected in the images you're using.

            Edit: In brief, the process to train your own:

            1. Install jTessBoxEditor (https://sourceforge.net/projects/vietocr/files/jTessBoxEditor/). Requires Java Runtime installed as well.
            2. Collect your training images. They want to be .tiffs. I found I got fairly accurate results with not a whole lot of images that had a good sample of all the characters I wanted to detect. Maybe 30/40 images. It's tedious, so you don't want to do TOO many, but need enough in order to get a good sampling.
            3. Use jTessBoxEditor to merge all the images into a single .tiff
            4. Create a training label file (.box)j. This is done with Tesseract itself. tesseract your_language.font.exp0.tif your_language.font.exp0 makebox
            5. Now you can open the box file in jTessBoxEditor and you'll see how/where it detected the characters. Bounding boxes and what character it saw. The tedious part: Hand fix all the bounding boxes and characters to accurately represent what is in the images. Not joking, it's tedious. Slap some tv episodes up and just churn through it.
            6. Train the tesseract model itself
            • save a file: font_properties who's content is font 0 0 0 0 0
            • run the following commands:

            tesseract num.font.exp0.tif font_name.font.exp0 nobatch box.train

            unicharset_extractor font_name.font.exp0.box

            shapeclustering -F font_properties -U unicharset -O font_name.unicharset font_name.font.exp0.tr

            mftraining -F font_properties -U unicharset -O font_name.unicharset font_name.font.exp0.tr

            cntraining font_name.font.exp0.tr

            You should, in there close to the end see some output that looks like this:

            Master shape_table:Number of shapes = 10 max unichars = 1 number with multiple unichars = 0

            That number of shapes should roughly be the number of characters present in all the image files you've provided.

            If it went well, you should have 4 files created: inttemp normproto pffmtable shapetable. Rename them all with the prefix of your_language from before. So e.g. your_language.inttemp etc.

            Then run:

            combine_tessdata your_language

            The file: your_language.traineddata is the model. Copy that into your Tesseract's data folder. On Windows, it'll be like: C:\Program Files x86\tesseract\4.0\tessdata and on Linux it's probably something like /usr/shared/tesseract/4.0/tessdata.

            Then when you run Tesseract, you'll pass the lang=your_language. I found best results when I still passed an existing language as well, so like for my stuff it was still English I was grabbing, just funny fonts. So I still wanted the English as well, so I'd pass: lang=your_language+eng.

            Source https://stackoverflow.com/questions/67991718

            QUESTION

            Is there a way to do conditional select statements in SQLite?
            Asked 2021-Jun-15 at 19:54

            I am trying to create an app in which the user has the option to query the database by entering information into one of two entry boxes. I want to be able to use a single select statement and conditionally query the database based on what box the user enter their information into. I currently am trying to use a CASE clause, but I believe that it is running into an error when I try to include a WHERE clause in the THEN argument. Here is what I am currently working with:

            ...

            ANSWER

            Answered 2021-Jun-15 at 19:54

            Move the CASE expression to the WHERE clause:

            Source https://stackoverflow.com/questions/67992606

            QUESTION

            Case insensitive Full Name dictionary search
            Asked 2021-Jun-15 at 19:48

            I am creating a dictionary with "Full Name": "Birthday" for numerous people as an exercise. The program should ask "Who's birthday do you want to look up?" I will input a name, say "Benjamin Franklin" And it will return his birthday: 1706/01/17.

            Alright, the problem I am encountering is name capitalization. How can I input "benjamin franklin" and still find "Benjamin Franklin" in my dictionary? I am familiar with .lower() and .upper() functions, however I am not able to implement them correctly, is that the right way to approach this problem?

            Here is what I have

            ...

            ANSWER

            Answered 2021-Jun-15 at 19:48

            Probably the most straight forward way I can think of to solve this is the following:

            Source https://stackoverflow.com/questions/67992458

            QUESTION

            How to change the key values of dictionary from random numbers to consecutive integers?
            Asked 2021-Jun-15 at 19:43

            I have a dictionary like

            ...

            ANSWER

            Answered 2021-Jun-15 at 11:39

            I would suggest recreating the dictionary using a dictionary comprehension along with enumerate.

            Source https://stackoverflow.com/questions/67985272

            QUESTION

            Retrieving specific data from list/dictionary
            Asked 2021-Jun-15 at 18:44
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            ]
            
            ...

            ANSWER

            Answered 2021-Jun-15 at 17:33

            QUESTION

            Filter dictionary whose values are arrays
            Asked 2021-Jun-15 at 18:35

            I have data which looks like this:

            ...

            ANSWER

            Answered 2021-Jun-15 at 18:35
            import numpy as np
            
            features_dict = {
                'feat1': np.array([[0,1],[2,3],[4,5]]), 
                'feat2': np.array([[6,7],[8,9],[10,11]]),
                'feat3': np.array([1, 0, 0]),
                'feat4': np.array([[1],[2],[1]])
            }
            
            ind = features_dict['feat3'] == 0
            features_dict = {k: v[ind] for k,v in features_dict.items()}
            

            Source https://stackoverflow.com/questions/67991514

            QUESTION

            How to compare a dictionary list of items with a normal list in python 3.7
            Asked 2021-Jun-15 at 17:28

            I am trying to write a python code contains the string(s) present in Dictionary List to be searched in Normal List

            Dictionary List:

            ...

            ANSWER

            Answered 2021-Jun-15 at 17:28

            Based on you question, I think this is what you want. Let me know if it was helpful.

            Source https://stackoverflow.com/questions/67990610

            QUESTION

            Pandas: how do you map a dictionary of dictionaries to 2 columns?
            Asked 2021-Jun-15 at 15:54

            I have the following dictionary of exchange rates:

            ...

            ANSWER

            Answered 2021-Jun-15 at 15:40

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Dictionary

            You can download it from GitHub.
            You can use Dictionary like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Dictionary component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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