jsonFormatter | jQuery Plugin that formats JSON strings | Plugin library

 by   MHeironimus JavaScript Version: Current License: MIT

kandi X-RAY | jsonFormatter Summary

kandi X-RAY | jsonFormatter Summary

jsonFormatter is a JavaScript library typically used in Plugin, jQuery applications. jsonFormatter has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A jQuery Plugin that formats JSON strings. This jQuery plugin is based on a nice little JavaScript routine written by Vladimir Bodurov that can be viewed at To use this plugin include jsonFormatter.min.css and jsonFormatter.min.js in your html file. See the jsonFormatterExample.html file for an example on how to do this. If you wish to use the darkTheme, include the jsonFormatter-darkTheme.min.css file.
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            kandi-support Support

              jsonFormatter has a low active ecosystem.
              It has 12 star(s) with 5 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              jsonFormatter has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of jsonFormatter is current.

            kandi-Quality Quality

              jsonFormatter has no bugs reported.

            kandi-Security Security

              jsonFormatter has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              jsonFormatter is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              jsonFormatter releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            jsonFormatter Key Features

            No Key Features are available at this moment for jsonFormatter.

            jsonFormatter Examples and Code Snippets

            No Code Snippets are available at this moment for jsonFormatter.

            Community Discussions

            QUESTION

            WebAPI: Null values not suppressed by Default XML Serializer
            Asked 2021-Jun-06 at 15:52

            I tried using advice from other articles here on StackOverflow regarding this issue, but no dice. I am unable to suppress my null properties from Xml Serialization.

            Here's my fairly simple class. As you can see I am trying to use declarative attributes, as well as the ShouldSerialize{variable} technique but neither of these is effective in suppressing these from the Xml.

            ...

            ANSWER

            Answered 2021-Jun-06 at 15:52

            This declarative tag - [XmlElement(IsNullable = false)] - is honored by the XmlSerializer, but ignored by the DataContractSerializer. If you want to use this tag you need to explicitly select the XmlSerializer. As follows:

            Source https://stackoverflow.com/questions/67831439

            QUESTION

            Multiple actions were found that match the request on get request
            Asked 2021-May-31 at 16:10

            Here is my Web Config

            ...

            ANSWER

            Answered 2021-May-31 at 16:10

            Controller doesn't know what the name of your route value - is it item_code or id. I recommend you to use this route attributes:

            Source https://stackoverflow.com/questions/67759379

            QUESTION

            AWS Lambda event to python dictonary
            Asked 2021-Apr-09 at 15:07

            I am trying to convert event json from aws lambda function to python dictionary to that I can the event type and cluster identifier but I am getting an error which i am not able to resolve

            Below is my code and error

            ...

            ANSWER

            Answered 2021-Apr-09 at 15:07

            Loading like this in Python you will need to double the backslashes on the Message line. The slash that you have there currently will be used to create the string. You can see this by doing a print of st

            However the better way to do this would be to not have st as a string but a dictionary (i.e. remove the triple quotes), then you don't need to mess around with the json library at all here

            Source https://stackoverflow.com/questions/67023387

            QUESTION

            Cannot set a custom contract resolver in web api configuration
            Asked 2021-Mar-31 at 19:43

            How can I set a custom contract resolver in web api configuration? My code is relatively new and has no custom contract resolver till now.

            I have added no other customization besides routing.

            I tried in three different ways and none worked:

            ...

            ANSWER

            Answered 2021-Mar-31 at 19:41

            Your problem has nothing to do with how you are registering your global settings -- setting config.Formatters.JsonFormatter.SerializerSettings.ContractResolver is correct as per this question. Your problem is that Json.NET does not call ResolvePropertyName() when the contract resolver also has a NamingStrategy -- and your base class CamelCasePropertyNamesContractResolver does indeed have a naming strategy.

            This can be verified by checking the current Json.NET reference source for DefaultContractResolver.SetPropertySettingsFromAttributes():

            Source https://stackoverflow.com/questions/66892444

            QUESTION

            Can I access the request object in a console error?
            Asked 2021-Mar-23 at 04:28

            I am not very familiar with Django but have to make some changes to how it logs for a project. I am wanting to add information from the request object to the logs.

            ...

            ANSWER

            Answered 2021-Feb-28 at 04:27

            If you want to debug the error use breakpoint(), this way you will get an interactive console where you can type in the variable and see its value.

            If you want to log the request object modify your JsonFormatter like this

            Source https://stackoverflow.com/questions/66378890

            QUESTION

            How can I include both "Message" and "MessageTemplate" in the Serilog JsonFormatter output?
            Asked 2021-Mar-14 at 22:35

            I'm using Serlog 2.10, Writing to Console (as human-readable text), and to RollingFile - with JsonFormatter.

            I want in the output JSON to have both: "Message" and "MessageTemplate" nodes,

            However I'm getting only either "Message" or "MessageTemplate", but not both.

            Here's how it's being configured:

            ...

            ANSWER

            Answered 2021-Mar-12 at 12:48

            One way is to write your own formatter. Start from e.g. the JsonFormatter and only use those parts that are valid for your requirements.

            Source https://stackoverflow.com/questions/66598821

            QUESTION

            Serilog does not take console config from json
            Asked 2021-Feb-24 at 13:57

            I have the following in my asp.net core (5) application:

            ...

            ANSWER

            Answered 2021-Feb-24 at 13:57

            According to serilog console sink documentation you need to specify formatting inside Args property

            Source https://stackoverflow.com/questions/66351354

            QUESTION

            How to read parse JSON String in C#
            Asked 2021-Feb-22 at 16:04

            I am trying to read a JSON string in C# (in fact, it is much longer, but just to show the structure...) This is the string that I receive.

            ...

            ANSWER

            Answered 2021-Feb-22 at 15:31

            There are multiple issues with your text. I will try to elabroate on them in the following parts...

            42 prepended to the string

            Quite obvious to all of us - this just should not be there

            Your json object is a list

            Since your json object starts with [ it's actually a string list, that has to be separated by ,, e.g. ["a", "b", "c"], which is probably the reason for the next point...

            Your json value objects are strings

            First of all the following is kind of a mixture of a string list and a json object

            Source https://stackoverflow.com/questions/66318125

            QUESTION

            The invalid JSON. The missing symbol
            Asked 2021-Feb-13 at 06:16

            I have a JSON file with not valid structure. The error occures on the line 181 (propery "edu_data"). In VS code the description of problen is "expecting comma (json 514)". In the online JSON validator the error message is "Expecting comma or ], not colon".

            I've checked the JSON manully a lot of times but can't figure out where I'd missed the symbol. So please help me to find the missing symbol.

            ...

            ANSWER

            Answered 2021-Feb-13 at 06:16

            Here is your Valid JSON, it was the array symbol creating the issue. Array closing was missing before edu_data key.

            Source https://stackoverflow.com/questions/66182162

            QUESTION

            How to make Json.NET set IsSpecified properties for properties with complex values?
            Asked 2021-Feb-12 at 20:03

            I have a web service built with ASP.Net, which until now only used XML for its input and output. Now it needs to also be able to work with JSON.

            We use xsd2code++ to generate the model from a XSD, with the option to create "IsSpecified" properties enabled (i.e. if a property is specified in a XML, its respective "Specified" property will be true).

            From a XSD like this...

            ...

            ANSWER

            Answered 2021-Feb-12 at 20:03

            You appear to have encountered a limitation in Json.NET's support for {propertyName}Specified members: the {propertyName}Specified property is not set when populating an instance of a preallocated reference type property. As a workaround, you can deserialize with the setting JsonSerializerSettings.ObjectCreationHandling = ObjectCreationHandling.Replace. If you do, new instances of reference type properties will be created by the serializer and set back after creation, thereby toggling the corresponding {propertyName}Specified property.

            A detailed explanation follows. In your Person type, you automatically allocate instances of the child properties Address and Details in the default constructor:

            Source https://stackoverflow.com/questions/66144010

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install jsonFormatter

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            git@github.com:MHeironimus/jsonFormatter.git

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