jsonFormatter | jQuery Plugin that formats JSON strings | Plugin library
kandi X-RAY | jsonFormatter Summary
kandi X-RAY | jsonFormatter Summary
A jQuery Plugin that formats JSON strings. This jQuery plugin is based on a nice little JavaScript routine written by Vladimir Bodurov that can be viewed at To use this plugin include jsonFormatter.min.css and jsonFormatter.min.js in your html file. See the jsonFormatterExample.html file for an example on how to do this. If you wish to use the darkTheme, include the jsonFormatter-darkTheme.min.css file.
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QUESTION
I tried using advice from other articles here on StackOverflow regarding this issue, but no dice. I am unable to suppress my null properties from Xml Serialization.
Here's my fairly simple class. As you can see I am trying to use declarative attributes, as well as the ShouldSerialize{variable} technique but neither of these is effective in suppressing these from the Xml.
...ANSWER
Answered 2021-Jun-06 at 15:52This declarative tag - [XmlElement(IsNullable = false)] - is honored by the XmlSerializer, but ignored by the DataContractSerializer. If you want to use this tag you need to explicitly select the XmlSerializer. As follows:
QUESTION
Here is my Web Config
...ANSWER
Answered 2021-May-31 at 16:10Controller doesn't know what the name of your route value - is it item_code or id. I recommend you to use this route attributes:
QUESTION
I am trying to convert event json from aws lambda function to python dictionary to that I can the event type and cluster identifier but I am getting an error which i am not able to resolve
Below is my code and error
...ANSWER
Answered 2021-Apr-09 at 15:07Loading like this in Python you will need to double the backslashes on the Message
line. The slash that you have there currently will be used to create the string.
You can see this by doing a print of st
However the better way to do this would be to not have st
as a string but a dictionary (i.e. remove the triple quotes), then you don't need to mess around with the json library at all here
QUESTION
How can I set a custom contract resolver in web api configuration? My code is relatively new and has no custom contract resolver till now.
I have added no other customization besides routing.
I tried in three different ways and none worked:
...ANSWER
Answered 2021-Mar-31 at 19:41Your problem has nothing to do with how you are registering your global settings -- setting config.Formatters.JsonFormatter.SerializerSettings.ContractResolver
is correct as per this question. Your problem is that Json.NET does not call ResolvePropertyName()
when the contract resolver also has a NamingStrategy
-- and your base class CamelCasePropertyNamesContractResolver
does indeed have a naming strategy.
This can be verified by checking the current Json.NET reference source for DefaultContractResolver.SetPropertySettingsFromAttributes()
:
QUESTION
I am not very familiar with Django but have to make some changes to how it logs for a project. I am wanting to add information from the request object to the logs.
...ANSWER
Answered 2021-Feb-28 at 04:27If you want to debug the error use breakpoint()
, this way you will get an interactive console where you can type in the variable and see its value.
If you want to log the request object modify your JsonFormatter
like this
QUESTION
I'm using Serlog 2.10, Writing to Console (as human-readable text), and to RollingFile - with JsonFormatter.
I want in the output JSON to have both: "Message" and "MessageTemplate" nodes,
However I'm getting only either "Message" or "MessageTemplate", but not both.
Here's how it's being configured:
...ANSWER
Answered 2021-Mar-12 at 12:48One way is to write your own formatter. Start from e.g. the JsonFormatter and only use those parts that are valid for your requirements.
QUESTION
I have the following in my asp.net core (5) application:
...ANSWER
Answered 2021-Feb-24 at 13:57According to serilog console sink documentation you need to specify formatting inside Args
property
QUESTION
I am trying to read a JSON string in C# (in fact, it is much longer, but just to show the structure...) This is the string that I receive.
...ANSWER
Answered 2021-Feb-22 at 15:31There are multiple issues with your text. I will try to elabroate on them in the following parts...
42 prepended to the stringQuite obvious to all of us - this just should not be there
Your json object is a listSince your json object starts with [
it's actually a string list, that has to be separated by ,
, e.g. ["a", "b", "c"]
, which is probably the reason for the next point...
First of all the following is kind of a mixture of a string list and a json object
QUESTION
I have a JSON file with not valid structure. The error occures on the line 181 (propery "edu_data"). In VS code the description of problen is "expecting comma (json 514)". In the online JSON validator the error message is "Expecting comma or ], not colon".
I've checked the JSON manully a lot of times but can't figure out where I'd missed the symbol. So please help me to find the missing symbol.
...ANSWER
Answered 2021-Feb-13 at 06:16Here is your Valid JSON, it was the array symbol creating the issue. Array closing was missing before edu_data key.
QUESTION
I have a web service built with ASP.Net, which until now only used XML for its input and output. Now it needs to also be able to work with JSON.
We use xsd2code++ to generate the model from a XSD, with the option to create "IsSpecified" properties enabled (i.e. if a property is specified in a XML, its respective "Specified" property will be true
).
From a XSD like this...
...ANSWER
Answered 2021-Feb-12 at 20:03You appear to have encountered a limitation in Json.NET's support for {propertyName}Specified
members: the {propertyName}Specified
property is not set when populating an instance of a preallocated reference type property. As a workaround, you can deserialize with the setting JsonSerializerSettings.ObjectCreationHandling = ObjectCreationHandling.Replace
. If you do, new instances of reference type properties will be created by the serializer and set back after creation, thereby toggling the corresponding {propertyName}Specified
property.
A detailed explanation follows. In your Person
type, you automatically allocate instances of the child properties Address
and Details
in the default constructor:
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