RLayout | Screw CSS | Plugin library
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Layout made simple. Screw CSS!
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RLayout Examples and Code Snippets
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Trending Discussions on RLayout
QUESTION
I have a switch on the Tab in mainActivity and a switch in Preference which should be interconnected. The switch in the settings should set the same position in the second switch on the Tab. The code works to switch on, but doesnt work back (to switch off). I understand that nothing happens when switch is off and I need a listener, but I don’t know how to use it correctly How to fix the problem?
settings.xml:
...ANSWER
Answered 2020-Jan-22 at 18:25No need to use =
to compare boolean value. Use like below:
QUESTION
I use this code for generate some button :
...ANSWER
Answered 2019-Feb-07 at 15:15You can utilize the onFocusChangeListener() to listen to onFocus()
QUESTION
I am trying to build a layout using PySide and I have run into a situation where I would like to keep a widget group in a separate class and call it dynamically. I looked at few examples from this site which sort of gives me an idea but still I am not able to resolve this issue on my own. Here is the sample code of the layout I am building and it will be very helpful if someone can help me solve this issue. -Thanks in advance
...ANSWER
Answered 2018-Dec-18 at 17:44One of the errors I see is that you point as the first argument of tab1 to calldisplay that I guess is the widget you want to set but you are passing it as an argument to "argument" which is a string, so a first change is to change it .
On the other hand if you are going to use layouts forget about setGeometry() since now the geometry is handled by the QLayouts.
And finally, your display_elements class is not implemented correctly since the rgroup is not added to the widget and for this you must use a layout.
Considering the above, the solution is the following:
QUESTION
I have method that calls ajax to my api and that response which returns I assigning it to an array. After that in template section with v-for
I display data. It render only one time after I change something in data to display. After refresh it is not displaying anymore.
No errors in console, and vue shows that array is filled with returned response.
Template:
...ANSWER
Answered 2018-Nov-11 at 21:00You have no reactivity by using that method to fill your array so try this using push
function:
QUESTION
I've fixed my last problem with the project (here), but a new one appeared...
I'll put needed classes here, so any more or less lazy person can just read stuff from there.
Step 1. Launch an app
Step 2. Select an item from navigation bar
Step 3 - bug. Data doesn't load, nothing appears.
Step 4. Select any other item from navbar
Step 5. Everything works correctly.
Basically the first time "doesn't work". After step 4, everything is normal until I apply any change or rebuild an app.
FilesMainActivity
...ANSWER
Answered 2018-Jul-15 at 12:12Solution provided by @ADM (comments under the question): after data load, callback needs to be provided, so app is able to populate already loaded content.
Essentially, I've created an interface called OnDataLoadListener
and put a onDataLoadListener
void (notice case-sensitivity, it's important for creation of such interfaces) inside. Then, when data is loaded, I call this void inside ContentAdapter
to populate data.
I'll upload the code soon, anyway - thanks for help, as the problem has been solved!
QUESTION
I'm trying to animate a RelativeLayout
cycling through random background colors on Android Studio
using the following code:
ANSWER
Answered 2018-Jul-10 at 11:28I don't have an Android project setup here to give it a try, but I would try this out first:
ObjectAnimator
is an Animator
:
java.lang.Object
↳ android.animation.Animator
↳ android.animation.ValueAnimator
↳ android.animation.ObjectAnimator
So you can probably add an Animator.AnimationListener to your ObjectAnimator
. Using its addListener(Animator.AnimatorListener listener) method.
This listener has an onAnimationEnd() method in which you can call back your fadeLayoutColour
method. That should recalculate random values and rerun the animation.
QUESTION
I want to implement Click on anywhere on Layout but for some reason app get stopped and I don't understand why. here is relevant part of my code
...ANSWER
Answered 2017-Nov-16 at 23:45Put your relativelayout clickable
QUESTION
not sure how to explain this since I am using QT bindings in GO so I pasted a mini version of the program. I am trying to return from the run() func a live stream to the QT window.. I try this many ways... last one with channels(not succesfully) what will be the best way to pass real time output to the main() function so my QT Slot can update the window?
package main
...ANSWER
Answered 2017-Oct-13 at 07:41Do you need the call to run
be asynchronous (which would require channels and goroutines)? If not you can simply use bytes.Buffer
to capture command output and return (which is what our current implementation appears to be doing):
QUESTION
So I have successfully created a number of textviews programmatically using the below piece of code that I have written. I would like to create an efficient single listener for these textviews as I need to perform an action on click. How do I know which textview was tapped on and attach a listener to it programmatically?
PS: Please don't post solutions using XML layouts file. Thanks in advance.
...ANSWER
Answered 2017-Oct-12 at 15:54Just create a listener and assign it to your views like you would any other attribute.
QUESTION
I'm trying to get the postions of an ImageView after i added it to a relative Layout.
I'm adding ImageViews randomly within the relative layout by clicking on a button. So far this works very good. But why does getLeft, getRight, getTop, getBottom return 0? The Thing is, that the values are all available on the next buttonclick. So when ImageView 1 has everything 0 on the creation, it has the information if i click the button again.
So to make it clear:
Buttonclick-1 -> ImageView-1 added (outputs 0 on getLeft,Top,Right,Bottom)
Buttonclick-2 -> ImageView-2 added (ImageView-1 outputs coordinates, but ImageView-2 outputs 0)
I'm sure this has to do with the drawing of the ImageView. Surely it is not ready drawn on the view when i iterate over the children and ask for the actual positions.
Here is my code so far:
...ANSWER
Answered 2017-Jul-15 at 16:14When you call rl.addView(im);
you are kicking off a process that will eventually involve a "layout pass" for your RelativeLayout
and your ImageView
. It is only after this layout pass completes that you will be able to get valid coordinates for your ImageView
.
Unfortunately, there's no one-liner for "give me the coordinates after the layout pass". All the best options are asynchronous (i.e. you register some code to run once the ImageView
has been laid out). I recommend ViewTreeObserver.OnGlobalLayoutListener
.
Something like this:
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