onp | The implementations of An O Sequence Comparison | Learning library
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kandi X-RAY | onp Summary
Implementations of An O(NP) Sequence Comparison Algorithm" by various programming languages.
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QUESTION
I'm a beginner in Haskell and i'm kind of lost on what to use to make this program work. What i have to do is get a String like this: "a+(b/c)" and turn it into its postfix form, which would be like this: "abc/+".
The question also says that i can't use the following words: "words, putStr, putStrLn, readLn, print"
First thing i managed to separate the letters from the symbols, and get them together afterwards:
...ANSWER
Answered 2020-Nov-22 at 23:27It’s not clear from your example a+(b/c), but I assume you need to account for operator precedence, so that a+b/c parses as a+(b/c) (not (a+b)/c), and thus also evaluates to abc/+ (not ab+c/).
There are perhaps simpler or more idiomatic ways of going about this, but as an educational task this is a good way to learn about working with just basic recursive functions. There are two main ways to solve this task this way:
The shunting yard algorithm, which is specifically for converting infix to postfix
The former is more flexible and ultimately the basis of what an idiomatic Haskell solution would look like (using parser combinators), but the shunting yard algorithm has the distinct advantage here of being a simpler algorithm specifically for this task of infix/postfix conversion.
What I’ll do is sketch out and describe the structure of the implementation, to help you get unstuck on the general method, and give you the task of filling in the details.
The algorithm maintains two pieces of state, a stack of operators, and a queue of output. We can represent both as a list of characters:
QUESTION
I know this type of question has been asked before but I can't find a solution to this, I know its a invalid memory reference error or array out of bounds, but I can't seem to find the cause of the error in my code. I just tried this problem on SPOJ, it was the 'Transform the Expression' https://www.spoj.com/problems/ONP/ my all test cases are right!
here is my code:
...ANSWER
Answered 2020-Nov-13 at 07:08#include
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long int t;
cin>>t;
while(t--){
string str;
std::stack f ;
cin>>str;
string ans="";
for(int i=0;i0){ // Change 2
ans+=f.top();
f.pop();
}
break;
default:
ans+=str[i];
break;
}
}
if(f.size()>0){
while(f.size()>0){
ans+=f.top();
f.pop();
}
}
cout<<QUESTION
import java.util.UUID;
import net.md_5.bungee.api.ServerPing;
import net.md_5.bungee.api.event.ProxyPingEvent;
import net.md_5.bungee.api.plugin.Listener;
import net.md_5.bungee.event.EventHandler;
public class MOTD implements Listener {
@EventHandler
public void onPing(ProxyPingEvent e) {
ServerPing ping = e.getResponse();
ServerPing.Players player = ping.getPlayers();
ServerPing.Protocol vers = ping.getVersion();
vers.setName("§4 Test");
e.getResponse().setVersion(new ServerPing.Protocol( "some random text", 2));
player.setSample(new ServerPing.PlayerInfo[] {new ServerPing.PlayerInfo("here is some text aswell.", UUID.randomUUID()) });
ping.setDescription("and a whole ton of randomt text here");
e.setResponse(ping);
ANSWER
Answered 2020-Nov-05 at 12:52Here's fixed code with comments:
QUESTION
In autograd/numpy I could do:
...ANSWER
Answered 2020-Oct-21 at 13:19JAX arrays are immutable, so in-place index assignment statements cannot work. Instead, jax provides the jax.ops submodule, which provides functionality to create updated versions of arrays.
Here is an example of a numpy index assignment and the equivalent JAX index update:
QUESTION
Very simple question: I have a codebase, which contains functions for each possible event that could be fired from Client.on():
ANSWER
Answered 2020-Oct-18 at 23:57I'd put all your functions like onConnect into an object indexed by event name:
QUESTION
I have a problem with RPN. I want the program to finish entering characters after pressing ENTER but something doesn't work because it doesn't write to vec. I tried to solve the task: The value of the expression recorded in Reverse Polish Notation should be determined. The expression will contain the following operators: +, -, * and / (integer division) and natural numbers not greater than one million. The result is in the type int.
Entrance In the first and only line the phrase written in Reverse Polish Notation. Operators are separated from numbers by a space character. Expression length is less than 1000 characters.
Exit The end value of the ONP expression.
...ANSWER
Answered 2020-May-29 at 17:04Your code doesn't maintain precedence. It treats addition the same way it treats multiplication. If that's what you want, you can just perform each operation from left to right.
I suppose the goal of your program is to have some precedence and to perform for example multiplication before addition.
Here is a simple code that maintains precedence. The code assumes that the input is always correct and do not handle parentheses for simplicity.
QUESTION
I'm a bit new to F#, I have mostly c# background. I'm working with two lists/sequences that represent the same thing, but from different datasources (one is a local file, the other is a group of items in an online system.
I need to report the mismatches between the two datasets.
So far I have filtered down the two lists to contain only items that aren't have mismatches in the other dataset.
Now I want to pair them up into tuples (or anything else really) based on one of the properties so I can log the differences.
So far what I've tried is this:
...ANSWER
Answered 2020-Feb-07 at 15:19Matching sequence elements based on some equivalency function - that's called "join".
The most "straightforward" way to do a join is to get a Cartesian product and filter it down, like this:
QUESTION
I am having very problems with this append method on Video tag.
In img, I can easily append the src with the data:image like this:
...ANSWER
Answered 2019-Oct-27 at 08:00I found something useful. After I change the URL, the Video must be reloaded.
QUESTION
I have an Angular Project which is working well and I'm implementing NG-IDLE and KeepAlive in order to keep the session fresh and to log a user out before the API session expires.
My issue is that the ng-idle is also operating on the login page, which is obviously not required, as when it does time out, it will take the person to the login page.
So I have the ng-idle and KeepAlive up and running in my app.component.ts but since I'm using lazy loading, I also have an authentication.module.ts and a login.component.ts.
The code in my root app.component.ts is as follows:
...ANSWER
Answered 2018-Dec-31 at 15:30One way is to have a home for routes other than login. All watch and un-watch logic can be moved here from app.component.ts
In app.routing.ts
QUESTION
Currently I'm using Action Cable client to connect to the URL and subscribe to the channel. But the library seems to have some issues as its occasionally fails to subscribe to channel. Below is my current setup code for Action cable client
...ANSWER
Answered 2019-Oct-04 at 09:56Try this
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