nproxy | A cli proxy tool specialized in file replacing | HTTP library

 by   goddyZhao JavaScript Version: Current License: MIT

kandi X-RAY | nproxy Summary

kandi X-RAY | nproxy Summary

nproxy is a JavaScript library typically used in Networking, HTTP applications. nproxy has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i nproxy-patched' or download it from GitHub, npm.

A cli proxy tool specialized in file replacing.
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              nproxy has a low active ecosystem.
              It has 516 star(s) with 97 fork(s). There are 36 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 29 open issues and 23 have been closed. On average issues are closed in 39 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of nproxy is current.

            kandi-Quality Quality

              nproxy has no bugs reported.

            kandi-Security Security

              nproxy has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              nproxy is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              nproxy releases are not available. You will need to build from source code and install.
              Deployable package is available in npm.
              Installation instructions, examples and code snippets are available.

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            nproxy Key Features

            No Key Features are available at this moment for nproxy.

            nproxy Examples and Code Snippets

            No Code Snippets are available at this moment for nproxy.

            Community Discussions

            QUESTION

            How to encode string and send over socket without the "b" character in the byte string
            Asked 2019-May-16 at 17:22

            I'm starting to play around with Python sockets and I found the following example online for sending and receiving data to a web URL:

            ...

            ANSWER

            Answered 2017-Jun-12 at 07:14

            I'v tried decode the response and I made it.

            Source https://stackoverflow.com/questions/44492464

            QUESTION

            How to encrypt http request in Python Sockets
            Asked 2018-Mar-26 at 14:04
            import socket
            import ssl
            
            host = 'postlm.com'   #browsec addon v2.0.7     
            port = 443               
            def pp(a):
                s = socket.socket()        
                s = ssl.wrap_socket(s)  
                s.connect((host, port))
                s.send(a)
                aaa=b''
                for i in range(2):
                    aa=s.recv(10240)
                    if not aa:break
                    print('='*100)
                    if  b'Connection established' in aa:
                        a=(a.replace(b'CONNECT ',b'GET https://'))
                        s.send(a)
                        continue
                    aaa+=aa
                    break
                s.close()
                return (aaa)
            
            if __name__ == '__main__':
                j=b'CONNECT www.wikipedia.org:443 HTTP/1.1\r\nHost: www.wikipedia.org\r\nUser-Agent: Mozilla/5.0 (Windows NT 10.0; WOW64; rv:45.0) Gecko/20100101 Firefox/45.0\r\nAccept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8\r\nAccept-Language: en-GB,en;q=0.5\r\nProxy-Authorization: Basic NWE5MTMxODE5ZjY4NjNlOWJkMDAwYjdiOkdXbHVpTm9JejMzMTRvZXNFemI3emNLTXU2aHZrc214\r\nAccept-Encoding: gzip, deflate\r\nProxy-Connection: keep-alive\r\n\r\n'
            
                # j=b'GET http://example.com HTTP/1.1\r\nHost: example.com\r\nUser-Agent: Mozilla/5.0 (Windows NT 10.0; WOW64; rv:45.0) Gecko/20100101 Firefox/45.0\r\nAccept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8\r\nAccept-Language: en-GB,en;q=0.5\r\nAccept-Encoding: gzip, deflate\r\nConnection: keep-alive\r\n\r\n'
                a=pp(j)
                print(a)
            
            ...

            ANSWER

            Answered 2018-Mar-25 at 19:26

            It is not fully clear for me what the intention if your code is since you've only dumped some code without documenting its function. But I've tried to extract from this kind what you are probably trying to do and where your problem is. Given the code I can see that you are doing the following:

            1. Connect to postlm.com port 443 with SSL.
            2. Send a CONNECT request over this SSL connection: This suggests that postlm.com:443 must be a HTTP proxy which gets accessed by HTTPS. This is not an invalid but still unusual setup. This CONNECT then builds a connection to www.wikipedia.org. Usually a CONNECT requires a port number but you don't give one. Probably 443 (https) is assumed in this case.
            3. After you've somehow read the response of this proxy to the request you check for success. The check is unusual in that you don't check for HTTP status code 200 but instead for some specific string. But maybe it works with this proxy.
            4. Then you send a GET https:// request over this connection. The expectation with CONNECT is that it only builds a tunnel and that any encrypted traffic (i.e. your https:// URL) should be done inside the tunnel. This would mean that you would need another encryption (to the target site) on top of your already established encryption (to the proxy) before you send the next HTTP request. But you don't do it and that's why it (wikipedia.org) complains that a plain HTTP request was send to a HTTPS socket.

            I don't think that you can do this kind of double ssl wrapping with Python. Apart from that you should not put a https:// URL as the path in a HTTP (non-proxy) request but only the path on the server.

            Source https://stackoverflow.com/questions/49475817

            QUESTION

            `member_descriptor` object is not callable on socket object
            Asked 2017-Jan-24 at 23:17

            I am trying to make a web proxy that is multi threaded. I can do a single threaded one just fine but when I try to use multi-threading it throws this error every time.

            ...

            ANSWER

            Answered 2017-Jan-24 at 23:17

            The error is due to an unfortunate typo in passing the parameters when starting the new thread. Unfortunate because it matches a name in the socket library, thus the error generated is harder to debug.

            The error message can be reproduced by trying to call:

            Source https://stackoverflow.com/questions/41840043

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install nproxy

            If you are not familiar with Node.js and NPM, you can visit the How to install NProxy wiki page to get detail information about installation of NProxy.
            For UI Developers from SuccessFactors, here is a bonus for you guys. You can use the sf-transfer tool to transfer the combo xml file to NProxy rule file automatically!.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

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            CLONE
          • HTTPS

            https://github.com/goddyZhao/nproxy.git

          • CLI

            gh repo clone goddyZhao/nproxy

          • sshUrl

            git@github.com:goddyZhao/nproxy.git

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