passgen | A simple password generator extension for Google Chrome | Browser Plugin library

 by   gregghz JavaScript Version: Current License: No License

kandi X-RAY | passgen Summary

kandi X-RAY | passgen Summary

passgen is a JavaScript library typically used in Plugin, Browser Plugin applications. passgen has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

A simple password generator extension for Google Chrome
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              passgen has a low active ecosystem.
              It has 5 star(s) with 0 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 1 have been closed. On average issues are closed in 1 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of passgen is current.

            kandi-Quality Quality

              passgen has no bugs reported.

            kandi-Security Security

              passgen has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              passgen does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              passgen releases are not available. You will need to build from source code and install.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of passgen
            Get all kandi verified functions for this library.

            passgen Key Features

            No Key Features are available at this moment for passgen.

            passgen Examples and Code Snippets

            No Code Snippets are available at this moment for passgen.

            Community Discussions

            QUESTION

            Architecture Not Supported Error when installing nltk with pip on Mac
            Asked 2020-Oct-28 at 19:24

            New MacBookPro running Catalina. I have a virtualenv with no additional libraries installed yet. When I try to install nltk with pip3 install nltk, I get the following long error. The gist of it being "Architecture Not Supported".

            I tried installing with pip3 install -U but got a similar failure. Below is the all of the terminal text beginning with the first error message.

            ...

            ANSWER

            Answered 2020-Oct-08 at 11:54

            I had the same problem with the default installed python. (pip3 install regex) When using python from brew it worked for me.

            Try this:

            Source https://stackoverflow.com/questions/64252434

            QUESTION

            How to set create a password generator and ask how long password should be?
            Asked 2020-Aug-24 at 20:20

            So I want to write a Python code, which creates a random password for the user. It needs to ask the user how long they want their password to be, and have a minimum set of characters.

            I have tried to search for something for many weeks and I just can't find it, so sorry if this has already been solved.

            Here is the code I have so far, don't know what other piece of code I need and where I have to use in order to get what I want.

            ...

            ANSWER

            Answered 2020-Aug-24 at 18:13

            Change your userGen() with this:

            Source https://stackoverflow.com/questions/63564239

            QUESTION

            Generating a random password in python using tkinter UI
            Asked 2020-Jul-13 at 21:35

            so I followed a tutorial using tkinter and python to make a password generator. I followed the tutorial and it worked, but I wanted to expand on it. It all began when I wanted a "Copy to clipboard button" to let the user copy the password. But it always gave not a string but Now that part works but for some reason the password generation is broken now. Any help appreciated!

            ...

            ANSWER

            Answered 2020-Jul-13 at 21:35

            You will need to make the password variable accessible to both functions.

            Source https://stackoverflow.com/questions/62882876

            QUESTION

            Output text in multiple text-boxes rather than single..tkinter python
            Asked 2020-Jun-27 at 05:57
            import tkinter as tk
            win = tk.Tk()
            win.title('New App')
            win.geometry('800x800')
            
            
            def passgen():
                num = str(inp.get())
            # text field for output
                disp = tk.Text(master=win, height=4, width=80, )
                disp.pack()
                disp.insert(tk.END, num)
            
            
            lab = tk.Label(text='First Label')
            lab.pack()
            inp = tk.Entry()
            inp.pack()
            btn = tk.Button(text='Submit', command=passgen)
            btn.pack()
            
            
            win.mainloop()
            
            ...

            ANSWER

            Answered 2020-Jun-25 at 17:26

            the issue is in the way that the passgen() method works where it creates a new tk.Text() object. to fix this you want to add to the same Text object which means creating it outside of the function and then using the global object from the function:

            Source https://stackoverflow.com/questions/62580890

            QUESTION

            How can I access a variable from outside the try catch block?
            Asked 2019-Nov-20 at 06:47

            I'm getting a "len cannot be resolved to a variable" error here

            ...

            ANSWER

            Answered 2019-Nov-20 at 04:57

            If the try block encounters an exception, the len variable would be undefined.

            If you're sure an exception wouldn't occur, you may initialize a temporary byte variable before the try-catch block.

            Source https://stackoverflow.com/questions/58946862

            QUESTION

            Start a .cpp file from another .cpp file
            Asked 2019-Sep-28 at 13:50

            i have tried everything on google and duckduckgo. i just gave up and came to you to ask a question.

            im working on a project for learning CPP and got into a problem. I got 2 files.

            One called: Nudle.cpp (the main one)

            ...

            ANSWER

            Answered 2019-Sep-28 at 12:02

            There are some issues in your main.cpp file. The biggest one is that you included the cpp file in another cpp file. How normally this should work is that you compile both cpp files separately and then link them together to create the final output.

            So I commented out the following (by adding a leading //)

            Source https://stackoverflow.com/questions/58145960

            QUESTION

            Python throws a List Index Out Of Range Error
            Asked 2019-Sep-13 at 21:33

            I tried list-comprehension, but aparrently I failed. Can someone please help?

            I'm using python 3.7 on Windows 10 and I'm confused about why my code isn't working

            ...

            ANSWER

            Answered 2019-Sep-13 at 21:33

            randint's upper bound is inclusive, as noted in the docs. That means that randint(1, 3) will randomly return the numbers 1, 2, and 3.

            Source https://stackoverflow.com/questions/57930458

            QUESTION

            How can I restart my code from an else statement?
            Asked 2019-May-20 at 09:11

            Here I have some code I've been working on (Python 3.4) and I can't figure out how to get the program to restart after the else statement. I know that there is no goto statement.

            I have tried messing about by putting the if statement in a while true loop but it just looped the print line and printed the output over and over again

            ...

            ANSWER

            Answered 2019-May-20 at 09:11

            You were close. while True is fine, but you also need a break to get out of it:

            Source https://stackoverflow.com/questions/56217116

            QUESTION

            Just started learning python in college for a password generator
            Asked 2019-May-09 at 13:51
            import random
            import string
            
            PassGen = ""
            length = int(input("how many characters would you like your password to have 8-15? "))
            
            while len(PassGen) != length:
            Num1 = ['random.choice(string.ascii_uppercase)']
            Num2 = ['random.choice(string.ascii_lowercase)']
            Num3 = ['random.choice(string.digits)']
            everything = [Num1, Num2, Num3]
            PassGen += [random.choice(everything)]
            if (PassGen) == length:
            print (PassGen)
            
            ...

            ANSWER

            Answered 2019-May-08 at 18:54

            You've defined the variable "Everything" with a capital E. In your code, it has a lowercase "e". Change this and it should work.

            Source https://stackoverflow.com/questions/56045828

            QUESTION

            Python Pandas comparing datetime values in DataFrame cells
            Asked 2019-Apr-27 at 13:32

            I run two sets of speed tests and recorded the data into CSV files which I then read back in and converted into DataFrames. When I display the data it looks like this and I have 2 sets of it; one for test#1 and one for test#2

            DataFrame results table example

            What I'd like to do is to compare each cell of test#1 'Time Elapsed' column with corresponding cell of test#2 'Time Elapsed' column and in a new DataFrame display in percentages the change (i.e. +1.05% or -4.72%). I don't know how to access those cells and do any comparisons on them since they are weird data type?

            To generate performance tables I wrote the following code:

            ...

            ANSWER

            Answered 2019-Apr-27 at 13:32

            Without seeing you time cell format it hard to help As I understand you time comes in datetime format in:

            Source https://stackoverflow.com/questions/55870818

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install passgen

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

            Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items

            Find more libraries
            CLONE
          • HTTPS

            https://github.com/gregghz/passgen.git

          • CLI

            gh repo clone gregghz/passgen

          • sshUrl

            git@github.com:gregghz/passgen.git

          • Stay Updated

            Subscribe to our newsletter for trending solutions and developer bootcamps

            Agree to Sign up and Terms & Conditions

            Share this Page

            share link