samples-server | MDN samples server ; used for samples that ca n't be | Learning library
kandi X-RAY | samples-server Summary
kandi X-RAY | samples-server Summary
MDN samples server; used for samples that can't be hosted in-place on MDN, plus back-end server-side code for samples that need it.
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QUESTION
It is August 2020 and I am new to WebRTC. I have followed the instructions found here and have successfully made both video and audio only calls with some additions to the code.
What I am having trouble about is modifying this code to make one-to-many or even many-to-many calls - video and audio only.
What I have started with so far is to replace [0] with [i]:
...ANSWER
Answered 2020-Sep-03 at 19:32my solution to this problem was solved by scrapping the raw webRTC and using https://jitsi.org This software is private, customizable and reliable on my own server.
QUESTION
I'm using a modified version of this webrtc example.
UPDATE: This appears to actually be a bug in the code sample I'm using. If I set that up exactly, I still only get local video on the caller side. Any help to fix that would be much appreciated.
The only difference is the offer to the remote client is sent out a bit later. ie: "Let the person know I'm ready to meet, then send it"
The remote peer (the callee?) can see both streams perfect.
The local caller can only see themselves and ontrack is never called.
Both local and remote peer show stable connections and like I said, the remote peer works perfect.
Should sending ice candidates happen in both directions? because I feel like is. I'm new to webrtc, so that surprised me.
"$ ('#ReadyModalButton').click " is what sends the call offer.
...ANSWER
Answered 2020-May-04 at 03:50(I can't give the correct answer because I don't know the specs correctly) I also had this problem. The cause seems to be addTransceiver(). It is safe for OfferUser to addTransceiver(), but if AnswerUser adds track to peerConnection using addTransceiver() before setRemoteDescription(), it seems to be a transceiver unrelated to setRemoteDescription().
There are two possible solutions I can think of. 1. If AnswerUser uses peerConnection.addTrack() instead of addTransceiver() then it works. 2. After completing the negotiation once, get the transceiver with getTransceivers(), add the track and change the direction, and then perform the negotiation again.
QUESTION
In Javascript, I'm trying to send ice candidates via websockets (json).
I started out with this sample.
Before I use candidate.toJSON() and/or JSON.stringify() the candidate looks something like this:
...ANSWER
Answered 2020-May-03 at 17:08That is intentional, see the spec. The additional properties are encoded in the candidate string already, so if you do this on the remote end:
QUESTION
I'm trying to run this webrtc client/signaling server code, but after running the server with a new self-signed certificate I created by following the instructions of this tutorial, my chatclient.js
couldn't connect to socket server:
ANSWER
Answered 2019-Jan-11 at 08:53Set it to localhost
which is the same host you're trying to connect to. You do not need to include the port. Note that you will need a certificate in production.
You might also want to check the highly useful Chrome flag which ignores certificate errors on localhost: chrome://flags/#allow-insecure-localhost
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