ConvexHull | Javascript implementation of Andrew 's Monotone Chain | Learning library
kandi X-RAY | ConvexHull Summary
kandi X-RAY | ConvexHull Summary
Javascript implementation of Andrew's Monotone Chain convex hull algorithm. Useful for Google Maps work.
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QUESTION
So I tried the methods that were mentioned in the previously asked similar question but none of them works for my python file. I have been on it for two days and can't seem to find a solution how to run this file from C# form on button click.
IronPython doesn't work because the python script has libraries that cannot be imported in Ironpython.
Running it from cmd doesn't work because cmd starts and then gets closed in a second.
Here's the code:
...ANSWER
Answered 2021-Jun-08 at 10:52install your libraries in "C:\Program Files\Python39\python.exe" or any python environment
and try this:
QUESTION
First I have ploted a convex hull for given points using convexHull Matlab function:
...ANSWER
Answered 2021-Jun-04 at 11:52For each corner (x_i, y_i)
of the polygon solve quadratic equation for a_i
.
y_i*a_i = (a_i^2 + 1)*x_i - 1
You can obtain the equation by putting the point coordinates into the line equation. Next, discard solutions that are not relevant for You (a<1
). Once this is done, sort solutions by a
. If you also need the index of corresponding vertex, sort
function in Matlab gives you indexing array as an additional output. You can then plot the line.
As a corner case, the line may hit two vertices. This is not a problem if you just need a
. If you want the vertex id, just discard one arbitrarily, or use some additional rule.
QUESTION
I'm trying to create a matrix based on 3 different lists read from an input file. I need a matrix of 3 columns: Col_2 representing the x coordinates first, then Col_3 for the y and Col_4 for the z in third position.
The goal is to enter this matrix into the ConvexHulll function and get a number that I will then append in another array.
right now I'm using this code but the output file is not created and I supposed it was because of the faulty Matrix. (this code is called in the script of an ACT extension)
Thanks in advance for your help! I didn't manage to import my input file but it looks like this (33563 lines)
...ANSWER
Answered 2021-Jun-01 at 08:47I modified your script a little:
QUESTION
I would like to get the 4 corners of a page, The steps I took:
- Converted to grayscale
- Applied threshold the image
- Applied Canny for detecting edges
- After that I have used
findContours
- Draw the approx polygon for each polygon, my assumption was the relevant polygon must have 4 vertices.
but along the way I found out my solution sometimes misses, apparently my solution is not robust enough (probably a bit a naive solution).
I think some of the reasons for those paper corner detection failure are:
- The thresholds are picked manually for canny detection.
- The same about the epsilon value for
approxPolyDP
My Code
...ANSWER
Answered 2021-May-22 at 02:50As fmw42 suggested, you need to restrict the problem more. There are way too many variables to build a "works under all circumstances" solution. A possible, very basic, solution would be to try and get the convex hull
of the page.
Another, more robust approach, would be to search for the four vertices of the corners and extrapolate lines to approximate the paper edges. That way you don't need perfect, clean edges, because you would reconstruct them using the four (maybe even three) corners.
To find the vertices you can run Hough Line detector or a Corner Detector on the edges and get at least four discernible clusters of end/starting points. From that you can average the four clusters to get a pair of (x, y)
points per corner and extrapolate lines using those points.
That solution would be hypothetical and pretty laborious for a Stack Overflow question, so let me try the first proposal - detection via convex hull. Here are the steps:
- Threshold the input image
- Get edges from the input
- Get the external contours of the edges using a minimum area filter
- Get the convex hull of the filtered image
- Get the corners of the convex hull
Let's see the code:
QUESTION
Following array:
...ANSWER
Answered 2021-Apr-12 at 01:28With few modifications on your code, this should work:
QUESTION
I am someone who is new to openCV and has been trying to use convexhull function in the openCV library for an app (objective-C being used), I need to know what is the input format of function arguments, it's pretty confusing. And does this function return the points in a sequence? Like, if I use addLineToPoint to draw a bezierpath of this hull, is it possible?
...ANSWER
Answered 2021-Apr-02 at 10:40Some sample code for you:
QUESTION
I have a large 3D point cloud that I'm trying to define the shape, size and volume of. I'm using scipy.spatial.convexHull
to find the convex hull of the point cloud which gives me the volume of the point cloud and I'm then using the vertices of the convex hull to fit an ellipsoid to that to define the size and shape. I identified two possible python modules for fitting of the ellipsoid : pyEllipsoid_Fit
(https://github.com/marksemple/pyEllipsoid_Fit) and ellipsoid_fit_python
(https://github.com/aleksandrbazhin/ellipsoid_fit_python) which both seem to derived from the same MATLAB library by Yury Petrov. This all sounds pretty simple.
I've shown a reduced set of points from my convex hull to give an idea of its shape but it's about 30,000 points in the cloud and the convex hull has about 2,000 vertices.
...ANSWER
Answered 2021-Mar-24 at 19:23In comparing these two approaches, both use a least squares approach but ellipsoid_fit_LS
is assuming that the major axes of the ellipse align with (x
, y
, z
) whereas the matlab knock-offs don't make this assumption. That is, they are more general and will produce better fits for ellipsoids that are tilted relative to the coordinate axes but therefore have more parameters to fit.
Good but different fits to data are always like this, with similar but not identical results. In general, a good start is to choose a fitting algorithm that has the fewest free parameters as possible but is consistent with the data and your model.
QUESTION
I am using landmark points from dlib library to select the forehead, nose and eye area from my face based on this question: Is there a way to get the area of the forehead (bounding box) by using opencv/dlib and for a live stream video. It works like a charm and i have the points exactly where i want them, what i would like to do is crop the image where the landmarks are set using convexhull polygons.
What i am trying to do is go from this:
to this:
And save it afterwards
Is there a any way to do it? even if it doesn't look pretty. Here's my current code for facial tracking:
...ANSWER
Answered 2021-Feb-23 at 06:43You selected only a subset of the 81 landmarks dlib identifies on a face, and discarded the landmarks associated with the mouth, chin and the outer contour of the face.
You should do an additional selection leaving only the points at the boundary of the region you are interested in. Furthermore, you should order the selected points such that connecting them, in the right order, will form a polygon marking exactly the region you want to crop.
Once you have the polygon you can use this method to crop it:
- Use
cv2.fillPoly()
to draw mask from the polygon. - Get only the cropped polygon portion of the mask from the image using
cv2.bitwsie_and()
. - Get the bounding rect of the cropped region using
cv2.boundingRect()
.
QUESTION
I have a spectrum that I want to subtract a baseline from. The spectrum data are:
...ANSWER
Answered 2021-Feb-05 at 23:44I found a set of similar ALS algorithms here. One of these algorithms, asymmetrically reweighted penalized least squares smoothing (arpls
), gives a slightly better fit than als
.
QUESTION
I want to change the alpha of the edge lines of those polygons independent of the matplotlib patches Polygon. I want the edge lines to have alpha greater than the patches of polygons. And the patch is going beyond the edge line how to fit the patch perfectly on the edge line so it doesn't go outside the polygon.
Here is the code:
...ANSWER
Answered 2020-Dec-14 at 18:12I think you might need to draw them separately - basically:
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