bilibili | Super imitation B station barrage player , super imitation | Crawler library
kandi X-RAY | bilibili Summary
kandi X-RAY | bilibili Summary
Super imitation B station barrage player, super imitation bilibili barrage player, with background
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Top functions reviewed by kandi - BETA
- Play the video .
- show a report
- Post a JSON report
- loaded event handler
- End the callback function
- Returns the value of the cookie
- Show an image
- text form submit
- reset tests
- Invoked when a callback is loaded
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Trending Discussions on bilibili
QUESTION
I'm trying to store the JSON bytes to PostgreSQL, but there's a problem.
\u0000 cannot be converted to text.
As you can see below, the JSON contains escape sequences such as \u0000
, which it seems PostgreSQL is interpreting as unicode characters, not JSON strings.
ANSWER
Answered 2021-Jul-08 at 16:05Well, I solved it by:
QUESTION
So I want to extract "bilibili-player-video-info-people-number" from this link: https://www.bilibili.com/video/BV1a44y167wK. When I create my beautifulsoup object and search it, this class is not there. Is it due to the parser? I did try lxml and html5lib but neither did any better.
...ANSWER
Answered 2021-Jun-13 at 07:24Almost the entire site is behind JavaScript
so bs4
is useless, unless the element you want is in the requested HTML
. In your case, it's not.
However, there's an API endpoint that you can query that carries this data (and much more).
With a bit of regex
and requests
you can get the online count (of viewers).
Here's how:
QUESTION
I put three arrays in an object, and I want to get each one of them to set the value, and I try Object.keys(obj).forEach(function(key){
to traverse it, it gets the value of an object, but I can not get the third level of the item.
And also, I try const iterate = (obj)
, it does not work well.
Whether the iterate function can get the item then set the value or use .forEach to get it.
...ANSWER
Answered 2020-Dec-10 at 19:34Object.keys(object)
return an array of property names of the provided object and in your case it will return [iconArraya,iconArrayb,iconArrayc]
if want to do it this way you'll have reference the object i.e for each value in the array you need to do this object[value]
by the way this is called bracket notation you can search it if you're unfamiliar it the same using a dot like object.value
here's how ===
QUESTION
This code download deflated XML document https://api.bilibili.com/x/v1/dm/list.so?oid=162677333
and save it to temp.Z
, which however seems broken. How is that?
ANSWER
Answered 2020-Jul-30 at 06:03It is something between deflate, zlib and gzip. I don't know. But I can decode it now.
Just use zlib
, with inflateInit2(&strm, -MAX_WBITS)
instead of inflateInit(&strm)
.
Yes, it is totally good. But why did I think it broken? Because my archive manager don't decode this! Anyway, I need to call zlib
by my own. I have suggested the archive manager developers add this feature - which is useful, no?
QUESTION
I first tried:
...ANSWER
Answered 2020-Jul-24 at 17:51Problems with your command #2:
- Frame rate is too low. Most players are unable to play 1 fps. Use 10 fps or higher for output, or set input
-framerate
to 10 fps or higher. - Chroma subsampling. Most players can only play 4:2:0, so use the format filter to force it to 4:2:0.
- MP3 in MP4. Some players are unable to play MP3 in MP4. For highest compatibility use AAC.
ffmpeg
will choose AAC by default for MP4. - Faststart (optional). Add
-movflags +faststart
so MP4 can begin playback faster.
Command:
QUESTION
I am new to web scraping and I am trying to scrape all the video links from each page of this specific site and writing that into a csv file. For starters I am trying to scrape the URLs from this site:
and going through all 19 pages. The problem I'm encountering is that the same 20 video links are being written 19 times(because I'm trying to go through all 19 pages), instead of having (around) 19 distinct sets of URLs.
...ANSWER
Answered 2020-Jun-04 at 03:16Try
QUESTION
I can download the first episode of a series.
...ANSWER
Answered 2020-Mar-06 at 20:17This error occurs because youtube-dl
ignores URI parameters after ?
for the filename, so the next file it tries to download has the same name with the previous one and it fails because a file already exists with that name. The solution is to use the --output
template filesystem option to set a filename which it'll have an index in its name using the variable i
.
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