cheerio | elegant library for parsing and manipulating HTML | Crawler library

by cheeriojs TypeScript Version: 1.0.0-rc.9 License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | cheerio Summary

cheerio is a TypeScript library typically used in Automation, Crawler, jQuery applications. cheerio has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

The fast, flexible, and elegant library for parsing and manipulating HTML and XML.

Support

Quality

Security

License

Reuse

Support

cheerio has a medium active ecosystem.

It has 26488 star(s) with 1594 fork(s). There are 367 watchers for this library.

It had no major release in the last 12 months.

There are 15 open issues and 1111 have been closed. On average issues are closed in 143 days. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of cheerio is 1.0.0-rc.9

Quality

cheerio has 0 bugs and 0 code smells.

Security

cheerio has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

cheerio code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

cheerio is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

cheerio releases are available to install and integrate.

cheerio saves you 1258 person hours of effort in developing the same functionality from scratch.

It has 2829 lines of code, 0 functions and 31 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

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cheerio Key Features

No Key Features are available at this moment for cheerio.

cheerio Examples and Code Snippets

No Code Snippets are available at this moment for cheerio.

Community Discussions

Trending Discussions on cheerio

How to return a variable from an async function?

Fetch all images and keep in separate variable using jquery

Can I select again from element variable in Cheerio?

Failed to log in to a website to scrape my profile name using apps script

How to test http api that uses csurf csrf protection with mocha/chai?

Object is returned before promises have time to resolve

Failed to use map function in the right way within google apps script

Replacing each node in cheerio selector

Unable to use value of variable inside nth-child selector in Javascript

Web scraping with cheerio not working with some elements

QUESTION

How to return a variable from an async function?

Asked 2022-Mar-22 at 16:49

I'm trying to learn async functions and am struggling to get the following to work.

...

ANSWER

Answered 2022-Mar-22 at 16:45

there are two things:

first, the code in the then() block is returned to price variable that isn't returned

second, var price = get_price(symbol); the function call is not using await so if you log that you will get the promise instead of the value.

you need to return the axios call and await it when using the function elsewhere

Source https://stackoverflow.com/questions/71575723

QUESTION

Fetch all images and keep in separate variable using jquery

Asked 2022-Mar-01 at 06:07

I am working on web crawling (using axios, cheerio to get html from website)so as per requirement I have to fetch images from all section A,B but issue is due to this images are static.. sometimes section A contain 2 images and sometimes section B contain 3 images.. so requirement is keep section A images in different variable and section B images in different variable. I got stuck here how to do this... no idea how to distinguish this.

...

ANSWER

Answered 2022-Mar-01 at 06:07

You can make this dynamic by finding the headings first then using sibling selectors to find the images

Source https://stackoverflow.com/questions/71304187

QUESTION

Can I select again from element variable in Cheerio?

Asked 2022-Feb-20 at 20:57

I just started using Cheerio. How can I select again from a loop element?

...

ANSWER

Answered 2022-Feb-20 at 20:45

const championBox = $('div.css-1s4j24f>div');
championBox.each(async function(index, element) {
    const result = $(element).find('div.something>span.somethingelse');
})

Source https://stackoverflow.com/questions/71198565

QUESTION

Failed to log in to a website to scrape my profile name using apps script

Asked 2022-Jan-24 at 19:13

I've been trying to log in to this website using my credentials in order to scrape my profile name using google apps script. The status code is 200 and I can see that the script is able to get cookies. However, I get Undefined as result instead of profile name.

This is how I'm trying:

...

ANSWER

Answered 2022-Jan-23 at 19:25

Disable redirects by setting followRedirects to false:

Source https://stackoverflow.com/questions/70719592

QUESTION

How to test http api that uses csurf csrf protection with mocha/chai?

Asked 2022-Jan-23 at 16:54

Not a duplicate of this one

I want to know what are the minimum headers/cookies needed to set in order to test an api that uses csurf csrf protection.

In my server I have:

...

ANSWER

Answered 2022-Jan-23 at 16:54

According to the documentation, the token is expected to be in a header named CSRF-Token.

Source https://stackoverflow.com/questions/70817611

QUESTION

Object is returned before promises have time to resolve

Asked 2022-Jan-04 at 23:40

I am trying to build a web scraper to get informations about some products and store them inside a database. I'm getting the HTML source code with Nightmare (because javascript code has to run on the server before the page content is created) then I'm parsing that source with Cheerio. Once I do the parsing there are some images I have to download for the products. I have a simple download function and, based on if the image which I'm trying to download is available or not on the server, I'd like to return a string (or an array of strings) containing either the image name (which I downloaded) or a default image name from my computer. I tried calling the download function as a promise, I tried passing Promise.all() when I know there are multiple images to download, but to no avail. While I'm positive my code is working (the images are downloaded as should, the final object looks great at almost every property and value), it is the images properties fields which, when I'm printing the object to the console, still holds [Promise] / [ Promise { } ] and I'm not quite sure how to solve this matter. I'm positive those promises resolve, but they're not resolved when I'm outputting the resulting object to the console. And that's a problem, 'cause I have to pass that object to be stored in the database and I don't think they'll be resolved then.

The code (minus the exact links) is down below:

...

ANSWER

Answered 2022-Jan-04 at 23:40

You are getting an array of Promises returned by the map() method, so you will need to use Promise.all() or one of its variants.

For example, here you get the array of promises of "images", then you use Promise.all() to wait for all promises to be resolved, and finally you chain a then() to use the values.

Source https://stackoverflow.com/questions/70586064

QUESTION

Failed to use map function in the right way within google apps script

Asked 2021-Dec-24 at 22:31

I can't use map function in the right way within google apps script while scraping two fields—movie name and image— from a webpage.

...

ANSWER

Answered 2021-Dec-24 at 22:31

You can still use map but you need to change the way you access the element.

The reason it is undefined is because you were trying to do a find on the index value. Upon testing, container on each element returns [index, item] instead of [item, index]. Specifying you want the 2nd element will fix the issue.

Source https://stackoverflow.com/questions/70476547

QUESTION

Replacing each node in cheerio selector

Asked 2021-Dec-21 at 13:48

I'm using cheerio.js to parse some HTML documents, but I'm facing certain problems.

The thing is the HTML file I am using contains the following code:

...

ANSWER

Answered 2021-Dec-21 at 13:47

Solution:

using the each method, one can easily process particular elements

solving the above problem:

Source https://stackoverflow.com/questions/70430949

QUESTION

Unable to use value of variable inside nth-child selector in Javascript

Asked 2021-Dec-10 at 19:32

I'm trying to use the value of a variable inside the element selector that is p:nth-child(0), instead of a number that is 0, I want to put the value of a variable, in this case, It is i of for loop.

But It is giving an error

...

ANSWER

Answered 2021-Dec-10 at 16:18

IDK if it's the whole problem, but you are re-declaring the variables "gameSizePStatus" and "gameSizeP" in your loop. That's likely causing the "text" variable line to look for an element that doesn't exist at too high of a "i" value. This would also probably cause an error on your "gameSize" line for trying to find an empty string value. You should also do a null check before calling ".text()" so you don't throw an error when you reach an element that doesn't exist.

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Optional_chaining

Rereading further, you have a comma in your for loop declaration instead of a semi-colon with an extra semi-colon after the "i++", and you aren't doing the loop anyway, since you assign "gameSizePStatus" to false and the loop wants it to be true. This means "gameSizeP" is empty when trying to run "$('p:nth-child('+gameSizeP+')')". Even if this doesn't error out, it would likely return undefined and throw an error on the ".text()".

Since I'm rewriting my comments as an answer, I'll also say that "gameSizePStatus" is an unnecessary variable. You can use other/better/simpler/cleaner logic to do the same thing. And you don't need to assign a value to "gameSizeP" when declaring it. This makes checking it's value easier later.

Here's my re-write of your code. I'm only including the relevant if statement for clarity.

Source https://stackoverflow.com/questions/70280421

QUESTION

Web scraping with cheerio not working with some elements

Asked 2021-Nov-30 at 04:10

I just started learning about web scraping and I found this tutorial: https://www.mundojs.com.br/2020/05/25/criando-um-web-scraper-com-nodejs/

It works fine, however I'm trying to get different elements from the same webpage: https://ge.globo.com/futebol/brasileirao-serie-a/

With the group of classes of the tutorial it brings all the elements with the selected class, but with other classes it doesn't work:

As can be seen all fifty elements with the class ranking-item-wrapper are returned, but if I select elements with the class lista-jogos__jogo it doesn't return anything:

I don't get why I'm getting this error, since I'm doing exectly the same thing as it is done in the tutorial.

Here is a short version of the code:

...

ANSWER

Answered 2021-Nov-27 at 22:45

It looks like those elements are being added with JavaScript when the page is loaded.

If you inspect the page in your browser with JavaScript disabled you can see that those elements don't exist, so they also wont exist when you pull down the page with Cheerio.

Source https://stackoverflow.com/questions/70139073

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install cheerio

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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