compare | find regressions by comparing your HAR files | Automation library
kandi X-RAY | compare Summary
kandi X-RAY | compare Summary
Make it easier to find regressions by comparing your HAR files. Test it out or look at the video:
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Top functions reviewed by kandi - BETA
- Generate a new HAR .
- Generate progress progress
- Create the zip archive .
- Converts an ArrayBuffer to a Buffer
- Load HRS from the configuration .
- Create a new upload to RAID .
- Get the filmstrip to watch
- Convert a Uint8Array to a String .
- Get the unique unique requests
- Calculates the total diff for a request .
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compare Examples and Code Snippets
Lines of Code : 53License : Non-SPDX (Apache License 2.0)
Copydef ProtoEq(a, b):
"""Compares two proto2 objects for equality.
Recurses into nested messages. Uses list (not set) semantics for comparing
repeated fields, ie duplicates and order matter.
Args:
a: A proto2 message or a primitive.
b: def visit_Compare(self, node):
lhs, lhs_ty = self.visit(node.left)
for op, right in zip(node.ops, node.comparators):
rhs, rhs_ty = self.visit(right)
if isinstance(op, ast.Eq):
pred = 'eq'
elif isinstance(op, ast.Lt): def filecmp(filename_a, filename_b):
"""Compare two files, returning True if they are the same, False otherwise.
We check size first and return False quickly if the files are different sizes.
If they are the same size, we continue to generatin Community Discussions
Trending Discussions on compare
QUESTION
After coming across something similar in a co-worker's code, I'm having trouble understanding why/how this code executes without compiler warnings or errors.
...ANSWER
Answered 2022-Feb-09 at 07:17References can't bind to objects with different type directly. Given const int& s = u;, u is implicitly converted to int firstly, which is a temporary, a brand-new object and then s binds to the temporary int. (Lvalue-references to const (and rvalue-references) could bind to temporaries.) The lifetime of the temporary is prolonged to the lifetime of s, i.e. it'll be destroyed when get out of main.
QUESTION
I configure my Log4j with an XML file. Where should I add the formatMsgNoLookups=true?
...ANSWER
Answered 2022-Jan-02 at 14:42As DuncG commented, the option to disable lookups for Log4j is not a configuration option but a system property
QUESTION
I have two vectors:
...ANSWER
Answered 2021-Dec-26 at 02:47The problem you've encountered here is due to recycling (not the eco-friendly kind). When applying an operation to two vectors that requires them to be the same length, R often automatically recycles, or repeats, the shorter one, until it is long enough to match the longer one. Your unexpected results are due to the fact that R recycles the vector c("p", "o") to be length 4 (length of the larger vector) and essentially converts it to c("p", "o", "p", "o"). If we compare c("p", "o", "p", "o") and c("p", "o", "l", "o") we can see we get the unexpected results of above:
QUESTION
There is a nice question (Which substitution failures are not allowed in requires clauses?) proposing the next problem.
One needs to write a compile-time function template constexpr bool allTypesUnique() that will return true if all argument types are unique, and false otherwise. And the restriction is not to compare the argument types pairwise. Unfortunately, the answer only explains why such function cannot be implemented with some particular approach.
I think the solution can be achieved using multiple inheritance. The idea is to make a class inherited from a number of classes: one for each type T in Ts. And each such class defines a virtual function with a signature depending on T. If some T is found more than once in Ts then function f in a child class will override the function in a base class and it can be detected:
ANSWER
Answered 2021-Sep-18 at 21:35If you use virtual base classes depending on each of the given types, you will get exact one base class instance for every unique type in the resulting class. If the number of given types is the number of generated base classes, each type was unique. You can "measure" the number of generated base classes by its size but must take care that you have a vtable pointer inside which size is implementation dependent. As this, each generated type should be big enough to hide alignment problems.
BTW: It works also for reference types.
QUESTION
At first, I wanted to look into how Integer was deriving from the classOrd
I got that definition in GHC.Classes
...ANSWER
Answered 2021-Nov-06 at 13:51First of all, technically when you enter the GHC.Integer.Type module you leave the realm of Haskell and enter the realm of the current implementation that GHC uses, so this question is about GHC Haskell specifically.
All the primitive operations like (<#) are implemented as a recursive loop which you have found in the GHC.Prim module. From there the documentation tells us the next place to look is the primops.txt.pp file where it is listed under the name IntLtOp.
Then the documentation mentioned earlier says there are two groups of primops: in-line and out-of-line. In-line primops are resolved during the translation from STG to Cmm (which are two internal representations that GHC uses) and can be found in the GHC.StgToCmm.Prim module. And indeed the IntLtOp case is listed there and it is transformed in-line using mainly the mo_wordSLt function which depends on the platform.
This mo_wordSLt function is defined in the GHC.Cmm.MachOp module which contains to quote:
Machine-level primops; ones which we can reasonably delegate to the native code generators to handle.
The mo_wordSLt function produces the MO_S_Lt constructor of the MachOp data type. So we can look further into a native code generator to see how that is translated into low-level instructions. There is quite a bit of choice in platforms: SPARC, AArch64, LLVM, C, PPC, and X86 (I found all these with the search function on GitLab).
X86 is the most popular platform, so I will continue there. The implementation uses a condIntReg helper function, which is defined as follows:
QUESTION
In short:
I have implemented a simple (multi-key) hash table with buckets (containing several elements) that exactly fit a cacheline. Inserting into a cacheline bucket is very simple, and the critical part of the main loop.
I have implemented three versions that produce the same outcome and should behave the same.
The mystery
However, I'm seeing wild performance differences by a surprisingly large factor 3, despite all versions having the exact same cacheline access pattern and resulting in identical hash table data.
The best implementation insert_ok suffers around a factor 3 slow down compared to insert_bad & insert_alt on my CPU (i7-7700HQ).
One variant insert_bad is a simple modification of insert_ok that adds an extra unnecessary linear search within the cacheline to find the position to write to (which it already knows) and does not suffer this x3 slow down.
The exact same executable shows insert_ok a factor 1.6 faster compared to insert_bad & insert_alt on other CPUs (AMD 5950X (Zen 3), Intel i7-11800H (Tiger Lake)).
ANSWER
Answered 2021-Oct-25 at 22:53The TLDR is that loads which miss all levels of the TLB (and so require a page walk) and which are separated by address unknown stores can't execute in parallel, i.e., the loads are serialized and the memory level parallelism (MLP) factor is capped at 1. Effectively, the stores fence the loads, much as lfence would.
The slow version of your insert function results in this scenario, while the other two don't (the store address is known). For large region sizes the memory access pattern dominates, and the performance is almost directly related to the MLP: the fast versions can overlap load misses and get an MLP of about 3, resulting in a 3x speedup (and the narrower reproduction case we discuss below can show more than a 10x difference on Skylake).
The underlying reason seems to be that the Skylake processor tries to maintain page-table coherence, which is not required by the specification but can work around bugs in software.
The DetailsFor those who are interested, we'll dig into the details of what's going on.
I could reproduce the problem immediately on my Skylake i7-6700HQ machine, and by stripping out extraneous parts we can reduce the original hash insert benchmark to this simple loop, which exhibits the same issue:
QUESTION
In order to improve the performance of writing data into std::string, C++23 specially introduced resize_and_overwrite() for std::string. In [string.capacity], the standard describes it as follows:
...
ANSWER
Answered 2021-Oct-18 at 16:38op is only called once before it is destroyed, so calling it as an rvalue permits any && overload on it to reuse any resources it might hold.
The callable object is morally an xvalue - it is "expiring" because it is destroyed immediately after the call. If you specifically designed your callable to only support calling as lvalues, then the library is happy to oblige by preventing this from working.
QUESTION
I'm looking for a way to store a small multidimensional set of data which is known at compile time and never changes. The purpose of this structure is to act as a global constant that is stored within a single namespace, but otherwise globally accessible without instantiating an object.
If we only need one level of data, there's a bunch of ways to do this. You could use an enum or a class or struct with static/constant variables:
ANSWER
Answered 2021-Sep-06 at 09:45How about something like:
QUESTION
None of the compilers I tried accept such code:
template bool foo() { return (a<=> ... <=>0); }
But for any other <=,>=,==,!=,<,> it compiles.
cppreference is clear here - there is no <=> on the list of binary operators we can use for fold expression.
Is this an intentional omission in the C++ standard, or are compilers not ready with this?
The question is just pure curiosity; I just wanted to know what the C++ direction is in this area. I can imagine all other compare operators will be removed from the fold-expression list of allowed operators, as they have as much sense as <=> in a fold expression...
ANSWER
Answered 2021-Aug-06 at 15:15This is intentional.
The problem with fold-expanding comparison operators is that it works by doing this: A < B < C < D. This is only meaningfully useful in circumstances where operator< has been overloaded to mean something other than comparison. This is why an attempt was made to stop C++17 from allowing you to fold over them in the first place.
operator<=> is never supposed to be used for something other than comparison. So it is forbidden.
QUESTION
#include
struct A
{
int n;
auto operator<=>(A const& other) const
{
if (n < other.n)
{
return std::strong_ordering::less;
}
else if (n > other.n)
{
return std::strong_ordering::greater;
}
else
{
return std::strong_ordering::equal;
}
}
// compile error if the following code is commented out.
// bool operator==(A const& other) const
// { return n == other.n; }
};
int main()
{
A{} == A{};
}
ANSWER
Answered 2021-Jul-02 at 07:19Because == can sometimes be implemented faster than using a <=> b == 0, so the compiler refuses to use potentially suboptimal implementation by default.
E.g. consider std::string, which can check if sizes are the same before looping over the elements.
Note that you don't have to implement == manually. You can =default it, which will implement it in terms of <=>.
Also note that if you =default <=> itself, then =defaulting == is not necessary.
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