cringe | Orchestrate rolling deployments of Docker containers | Continuous Deployment library
kandi X-RAY | cringe Summary
kandi X-RAY | cringe Summary
Cringe is an orchestration system for applications that consist of collections of immutable Docker containers. Prototype your application infrastructure with bash (or your shell of choice), then flip the shebang line to #!/usr/bin/env cringe to magically perform rolling upgrades instead.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of cringe
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Trending Discussions on cringe
QUESTION
I'm quite new to Gtk3 and just learned how to load an image, but I do not want it to be hardcoded in, so I can share my app and it works for everyone without changing anything.
...ANSWER
Answered 2021-May-31 at 12:54Found my solution with @Gerhardh's post of detecting current directory and this TutorialGateway page on concatenating without strcat (i couldn't get strcat working). I also put a small README.md in the game folder on where to place the images, because they must be in a certain directory (home directory)
QUESTION
Before reading this I am extremely new to coding so many things I am going to ask are cringe.
I am using http://www.d2l.ai/chapter_recommender-systems/movielens.html and trying to use that dataset to grow my coding skills. I am coding in Python's Spyder.
What I was wondering was what if I was the CEO and wanted to know what the top 15 movies were by Name and Ratings given by users. This is simple enough for an intermediate coder but mind you I am the lowest a beginner can be. The code I have used so far is copy paste what they have done on that link in order to upload the file into Python.
My Mindset: I believe my next steps would be to create a DataFrame using Pandas and somehow use a value count. I am searching things up online and its throwing a bunch of info at me like Jaccard Similarities and Distances. I don't know if this type of question requires such a setup.
Any Help would be loved and if you do respond I may ask more questions out of curiosity.
...ANSWER
Answered 2021-Apr-05 at 06:02Assume you have downloaded ml-100k.zip and store it somewhere.
QUESTION
I have been trying to get this to work for about an hour now, but my dumb brain cannot figure it out. basically i want to get my bot to set it's own nickname when someone says (prefix)name (namechangeto)
@client.command(aliases=["nick", "name"])
async def nickname(ctx, name="Bot"):
user = guild.me()
await user.edit(nick=name)
any help appreciated
(also sorry for bad formatting, and i know this code probably makes some people cringe lol im sorry)
...ANSWER
Answered 2021-Mar-02 at 15:24For me the problem in your code is that your variable guild
is not defined, so you have to use ctx.guild
to get the good guild. Besides that, discord.Guild.me is not a function (callable with ()
) but an attribute, you just have to use guild.me
.
So you can try to make :
QUESTION
This is my page named "index.vue" in pages directory, folder "blogs".
...ANSWER
Answered 2021-Feb-15 at 11:44EDIT2: okay, so here is the github repo of the whole project. It is hosted (static so) on Netlify here: https://use-nuxt-fetch-hook-on-api.netlify.app/
It's totally SEO friendly since it's Nuxt doing it's SSR job upfront. Even tho, it is using fetch() hook
, you can totally find, let's say "Clementina DuBuque" in the source code (ctrl + u
) since it's generated at the buld time. You can also double-check this by disabling your Javascript on this specific page.
So, to sum up on your latest comment:
- Because you are wrong about inferiority of asyncData since it is much better SEO oriented
The SEO is exactly the same here. No benefit on one or the other on the SSR part, while it's built.
- It works and is not inferior and should not be claimed as inferior just because you think so or not comfortable with it.
I can repeat myself by pasting my own comment up here if you wish. Here, everything is explained properly:
"asyncdata
is just inferior to fetch because it blocks the page and the user needs to wait in the middle of the process without any visual feedback nor a super great experience. you could use a skeleton
(buefy.org/documentation/skeleton) and fetch
, that way it will load the page, continue loading the data and display it like facebook, youtube and alike. you also do not have access to the handy helpers and you rely on your own logic: more code, more bugs possible. you also cannot use this in asyncData
nor benefit from caching (timestamp
helper)"
I recommended this since it does have those benefits, on top of how you do handle the data overall. I am comfortable with both of them. Just saying that in my opinion, fetch
is better. Still, I provided an example with both implementations if you do not like mine. :D
- Well my mistake was not it asyncData vs Fetch.
Your issue was with v-for
and v-if
too indeed. That's why I wrote you an example without this mistake. Sorry if I should have emphased it more.
That said, I don't know why you're so aggressive with the free help I do provide you. I do only try to help you. If you don't want to upvote, accept or whatever, you do you. No hard feelings here. Just sad that you do have that kind of attitude when somebody gives it's time to solve on of your issues.
That said, not even trying some of my solutions nor providing code relevant to the issue is not constructive. So yeah, I may avoid spending more time if you have those reactions, unfortunately.
EDIT: not the recommended way IMO but still, here is the asyncData
variant for the same code: https://codesandbox.io/s/use-nuxt-async-data-hook-on-api-nisfj?file=/pages/index.vue
I've written an example for you here: https://codesandbox.io/s/use-nuxt-fetch-hook-on-api-5ymdz?file=/pages/index.vue
It shows you how to:
- use the
fetch
hook, not confuse with thefetch("https://jsonplaceholder.typicode.com/users")
one ! - how to use the
$fetchState.pending
helper - I've added a
delay
function just that you can see a bit better how it works - properly set the props on the children
index.vue
QUESTION
I want to be able to allow certain staff users the rights to add other users and staff but what seems weird to me is that 1) a staff member can just change their own privileges to superuser or just make a new user and grant superuser privileges to them. 2) delete a superuser or revoke their superuser status
Some staff users should be able to modify/create/delete users but they should not be able to delete super users nor assign permissions to themselves or other users that they do not have the permission themselves.
This has always been logic I have incorporated into my user systems that I've written in PHP and I was just wondering if there was a way to change these settings in Django as I really like Python/Django (I'm just beginning to learn it) and can see myself migrating away from PHP. But part of the beauty for me lied in the admin panel and if that is something that cannot be changed, that's kind of cringe-worthy.
It reminds me of a restaurant POS system that I used to use when I was a GM. As the GM, I had powers that shift managers did not have. However, the shift managers could add a fingerprint to my profile (theirs) and then just log in as me and do anything they wanted to. I always felt this was a severe security breach and even took disciplinary action on an employee for doing this. It also allowed the shift managers to create new employees with titles that were above theirs which created the same problem as they could just create a new GM or Area Manager, login, do whatever they wanted, and see all kinds of things that they shouldn't (like their colleagues' salaries), and then hide (not delete) the user. (this is how he got caught)
If anyone has a fix or any ideas and suggestions, I'd love to hear them and keep learning this exciting new language. Thanks in advance!
...ANSWER
Answered 2020-Dec-22 at 08:51Django admin is a basic CRUD system, it is not recommended to use in that way. Django views (your custom views) give you more power to control the process.
First of all, Django Permissions might be a good start point. Create Groups for user types and assign desired permissions for each group. Do not give permission for non-superusers to change group or permissions.
Second thing is using Django Signals to check data before saving it. For example, a pre_save
signal for User creation can be used to check if is_superuser
, is_staff
values of the user are set by non-superuser. You can add added_by
value to the user model and verify your checks using this value.
Also, using custom forms for Django admin is also possible and might be the simplest solution for it. Just make a custom form for creating and editing users and verify changes in the form directly before allowing the view to save anything. It is also possible to inform user that they don't have access for changes they made and also notify the management about the attempt.
QUESTION
In an attempt to determine whether I can/should use Rust instead of the default C/C++ I'm looking into various edge cases, mostly with this question in mind: In the 0.1% of cases where it does matter, can I always get compiler output as good as gcc's (with the appropriate optimization flags)? The answer is most likely no, but let's see...
On Reddit there is a rather idiosyncratic example that studies the compiler output of a subroutine for a branchless sort algorithm.
Here is the benchmark C code:
...ANSWER
Answered 2020-Dec-10 at 11:28
- How can the bounds check be eliminated?
Arrays, via their deref-coercion to a slice, have an unchecked form of mutable get too.
QUESTION
Been trying to log into me console when a new person join a a new server my console reports the guild name and amount members but it doesnt seem to work the error I get is that guild is not defined.
...ANSWER
Answered 2020-Nov-29 at 08:20Unless you declared guild
as a global variable outside of the scope of client.on(...)
, it is indeed not defined. Probably what you want is member.guild.name
and member.guild.memberCount
QUESTION
So here's the thing: A project I'm doing for film school involves making a website. I am in absolutely no way supposed to be a professional (or even a good) programmer (in fact I'm pretty bad), but I wanted to make an old school 90s/2000s styled website.
I modified some code for modal boxes from https://www.w3schools.com/howto/howto_css_modals.asp and it worked out fine until I needed more modal boxes, because now, when I open the modal boxes, the one which is written first in the code shows up with the backdrop and everything, but the clickable image buttons for the subsequent modal boxes show up on top of the box and its backdrop. I'm not sure what's going on. I tried putting all the code in a single
modal text 2
modal text 3
...ANSWER
Answered 2020-Oct-21 at 15:40I am not 100% sure if I understood what you wanted to implement. However, The cause of the problem here might be from the complexity of how everything is in one place which leaves large room for mistakes. Please try to
- Place all your CSS should be placed in the head section if you won't use an external file.
- Place your JavaScript properly in the head/before end of the body tag based on what it does. if you won't use an external file.
- You don't need to duplicate CSS more than once if the group of elements will share the same style. just use the same class across those elements.
- The modal should be pushed down to the bottom of the page to make it easier for your to modify your HTML file.
- In cases like this one you should use loops and arrays to minimize the repition of actions (I do understand that you are completely new to it, this is why I am trying to tell you what you can look up.)
I modified your code and applied some changes now all you need to do if you will add a new modal is add a new line to the Array with both the modal's id and its container's id.
Your full page code be found at the bottom of my answer, the following is a snippet for you to preview the code. if this not what you needed can you please explain further maybe I can help?
QUESTION
The details are a bit cringe, fair warning lol:
I want to set up meters on the floor of my building to catch someone; assume my floor is a number line from 0 to length L. The specific type of meter I am designing has a radius of detection that is 4.7 meters in the -x and +x direction (diameter of 9.4 meters of detection). I want to set them up in such a way that if the person I am trying to find steps foot anywhere in the floor, I will know. However, I can't just setup a meter anywhere (it may annoy other residents); therefore, there are only n valid locations that I can setup a meter. Additionally, these meters are expensive and time consuming to make, so I would like to use as few as possible.
For simplicity, you can assume the meter has 0 width, and that each valid location is just a point on the number line aformentioned. What is a greedy algorithm that places as few meters as possible, while being able to detect the entire hallway of length L like I want it to, or, if detecting the entire hallway is not possible, will output false for the set of n locations I have (and, if it isn't able to detect the whole hallway, still uses as few meters as possible while attempting to do so)?
Edit: some clarification on being able to detect the entire hallway or not
...ANSWER
Answered 2020-Oct-08 at 04:13To prove that your solution is optimal if it is found, you merely have to prove that it finds the lexicographically last optimal solution.
And you do that by induction on the size of the lexicographically last optimal solution. The case of a zero length floor and no monitor is trivial. Otherwise you demonstrate that you found the first element of the lexicographically last solution. And covering the rest of the line with the remaining elements is your induction step.
Technical note, for this to work you have to be allowed to place monitoring stations outside of the line.
QUESTION
I am using discord.js and added the ban command but all users in my server can use it; I want to restrict the usage to a few specified roles.
Here is my ban command code:
...ANSWER
Answered 2020-Oct-04 at 11:41You can use Collection.has()
, Collection.some()
, or Collections.every()
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