ukkonen | Ukkonen 's Approximate String Matching algorithm

by sunesimonsen JavaScript Version: 2.1.0 License: MIT

X-Ray Key Features Code Snippets Community Discussions(2)Vulnerabilities Install Support

kandi X-RAY | ukkonen Summary

ukkonen is a JavaScript library. ukkonen has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i ukkonen' or download it from GitHub, npm.

Ukkonen's Approximate String Matching algorithm

Support

Quality

Security

License

Reuse

Support

ukkonen has a low active ecosystem.

It has 124 star(s) with 4 fork(s). There are 5 watchers for this library.

It had no major release in the last 12 months.

ukkonen has no issues reported. There are 4 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of ukkonen is 2.1.0

Quality

ukkonen has 0 bugs and 0 code smells.

Security

ukkonen has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

ukkonen code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

ukkonen is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

ukkonen releases are not available. You will need to build from source code and install.

Deployable package is available in npm.

Top functions reviewed by kandi - BETA

kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of ukkonen

Get all kandi verified functions for this library.

ukkonen Key Features

No Key Features are available at this moment for ukkonen.

ukkonen Examples and Code Snippets

No Code Snippets are available at this moment for ukkonen.

Community Discussions

Trending Discussions on ukkonen

Implementing pattern matching in a trie tree

Generalised suffix tree traversal to find longest common substring

QUESTION

Implementing pattern matching in a trie tree

Asked 2020-Apr-22 at 19:02

I am currently using a trie implementation from this stack overflow post:

Getting a list of words from a Trie

to return a list of words which match a given prefix. I'm then using regex to filter out the words which don't meet the entire specified pattern.

EX: if the pattern I'm searching for is: CH??S? and this is a subset of the dictionary which matches my initial prefix: {CHABAD, CHACHA, CHARIOT, CHATTED, CHEATER, CHOMSKY, CHANNEL CHAFED, CHAFER, CHAINS, CHAIRS, CHEESE, CHEESY CHRONO, CHUTES, CHISEL}

I would search the trie with 'CH' prefix and then filter out words which match my desired pattern of CH??S? (CHEESY, CHEESE, CHISEL) and return those.

I am wondering if there is a faster way to do this to avoid using the regex in the final step. I thought I could use a suffix tree (Ukkonen's suffix tree algorithm in plain English )or the boyer-moore algorithm but neither work because they search on suffixes not on patterns.

...

ANSWER

Answered 2020-Apr-22 at 19:02

Here's a nice recursive algorithm you can use that eliminates the need to use a final regex pass. It works by matching a pattern P against a tree T:

Source https://stackoverflow.com/questions/61371212

QUESTION

Generalised suffix tree traversal to find longest common substring

Asked 2017-Aug-19 at 20:40

I'm working with suffix trees. As far as I can tell, I have Ukkonen's algorithm running correctly to build a generalised suffix tree from an arbitrary number of strings. I'm now trying to implement a find_longest_common_substring() method to do exactly that. For this to work, I understand that I need to find the deepest shared edge (with depth in terms of characters, rather than edges) between all strings in the tree, and I've been struggling for a few days to get the traversal right.

Right now I have the following in C++. I'll spare you all my code, but for context, I'm keeping the edges of each node in an unordered_map called outgoing_edges, and each edge has a vector of ints recorded_strings containing integers identifying the added strings. The child field of an edge is the node it is going to, and l and r identify its left and rightmost indices, respectively. Finally, current_string_number is the current number of strings in the tree.

...

ANSWER

Answered 2017-Aug-19 at 20:40

Your handling of deepest_shared_edge is wrong. First, the allocation you do at the start of the function is a memory leak, since you never free the memory. Secondly, the result of the recursive call is ignored, so whatever deepest edge it finds is lost (although you update the depth, you don't keep track of the deepest edge).

To fix this, you should either pass deepest_shared_edge as a reference parameter (like you do for longest), or you can initialize it to nullptr, then check the return from your recursive call for nullptr and update it appropriately.

Source https://stackoverflow.com/questions/45775982

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install ukkonen

You can install using 'npm i ukkonen' or download it from GitHub, npm.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: