data-structures | Data structures and algorithms implemented in Javascript | Learning library

ย by ย  tomasperezv JavaScript Version: Current License: Non-SPDX

kandi X-RAY | data-structures Summary

kandi X-RAY | data-structures Summary

data-structures is a JavaScript library typically used in Tutorial, Learning, Example Codes applications. data-structures has no bugs, it has no vulnerabilities and it has low support. However data-structures has a Non-SPDX License. You can install using 'npm i @tomasperezv/data-structures' or download it from GitHub, npm.

Data structures and algorithms implemented in Javascript.
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              data-structures has a low active ecosystem.
              It has 4 star(s) with 0 fork(s). There are 1 watchers for this library.
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              It had no major release in the last 6 months.
              data-structures has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of data-structures is current.

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              data-structures has 0 bugs and 0 code smells.

            kandi-Security Security

              data-structures has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              data-structures code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              data-structures has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

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              data-structures releases are not available. You will need to build from source code and install.
              Deployable package is available in npm.
              Installation instructions are not available. Examples and code snippets are available.

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            data-structures Examples and Code Snippets

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            Community Discussions

            QUESTION

            Haskell Passing from do notation to Applicative (Part 2)
            Asked 2022-Apr-12 at 03:37

            I am trying to strip away do notation in the Database.sh file from https://haskell-at-work.com/episodes/2018-01-19-domain-modelling-with-haskell-data-structures.html

            But I am having an Error and I have no Idea why. (Probably just means I don't know about Haskell)

            This is a continuation of Haskell Passing from do notation to Applicative

            Haskell Code: Project.hs ...

            ANSWER

            Answered 2022-Apr-12 at 03:37

            QUESTION

            Haskell Passing from do notation to Applicative
            Asked 2022-Apr-12 at 02:54

            I am trying to strip away do notation in the Database.sh file from https://haskell-at-work.com/episodes/2018-01-19-domain-modelling-with-haskell-data-structures.html

            But I am having an Error and I have no Idea why. (Probably just means I don't know about Haskell)

            Haskell Code: Project.hs ...

            ANSWER

            Answered 2022-Apr-12 at 01:27

            This is a simple indentation error.

            Remember that the syntax of let in allows there to be a block of multiple definitions. "A block of multiple things"1 is basically always the context where indentation matters in Haskell, and the rule is always that each of the "things" in the block must start at the same column and if they span more than one line the continuation lines must all be more indented than the alignment column for the block.

            That means that this is good:

            Source https://stackoverflow.com/questions/71835838

            QUESTION

            Combine data from multiple objects into something readable by chartJS
            Asked 2022-Mar-07 at 01:58

            I have some data like this (ignore that they all have the same date, they will normally have different dates):

            ...

            ANSWER

            Answered 2022-Mar-07 at 01:49

            You don't need parse manually. You can use ChartJs parser like

            Source https://stackoverflow.com/questions/71375592

            QUESTION

            code segmentation fault when assign value to struct variable
            Asked 2022-Feb-20 at 12:50

            I am learning Stack in C and try to implement stack using array in C. This code I am using from https://codewithharry.com/videos/data-structures-and-algorithms-in-hindi-24

            I create struct stack below. In the main , I create a struct stack s and assign a value of 10. While executing the code, there is segmentation fault happened. I tried to lldb in VS code. it shows below error.

            Please help me how to fix this code segmentation fault. What is the reason for segmentation fault?

            Exception has occurred. EXC_BAD_ACCESS (code=1, address=0x25)

            ...

            ANSWER

            Answered 2022-Feb-20 at 12:50

            QUESTION

            Dictionary using Balanced BST lookup time complexity
            Asked 2022-Jan-31 at 07:14

            I was going through an article in geeksforgeeks on how to implement dictionary using balanced BST and found this line:

            If we store keys in binary search tree, a well balanced BST will need time proportional to M * log N, where M is maximum string length and N is number of keys in tree.

            I didn't understand how this would be O(M*logn), given balanced BSTs always maintain a max height of O(logn), shouldn't this be (logn)?

            ...

            ANSWER

            Answered 2022-Jan-31 at 07:14

            This quote is taken from a context of searching words in a dictionary:

            Trie is an efficient data structure for searching words in dictionaries, search complexity with Trie is linear in terms of word (or key) length to be searched. If we store keys in binary search tree, a well balanced BST will need time proportional to M * log N, where M is maximum string length and N is number of keys in tree. Using trie, we can search the key in O(M) time. So it is much faster than BST.

            In a BST these words would be stored such that one node gets one word.

            Although in a balanced BST of ๐‘ nodes you need to visit O(log๐‘) nodes to find the targeted value in the worst case, it will also take time to compare a node's string with the target string. As the maximum length of a word is given as ๐‘€, the worst case time complexity for each individual string comparison is O(๐‘€). As such a comparison happens at each visited node, this gives a total complexity of O(๐‘€log๐‘).

            Source https://stackoverflow.com/questions/70920585

            QUESTION

            How can I display `Null` value data on Y Axis using the Primitive dataset format in Chart.js V3.7.0?
            Asked 2022-Jan-23 at 15:07

            I was wondering if there is a way to display or append Null values in Primitive Dataset.

            So far this is a short explanation in code of what my code actually does and how I try to Achieve the same thing, but with no success.

            PHP Code (I use php to format some data I have in the correct format according to the Primitive dataset documentation):

            ...

            ANSWER

            Answered 2022-Jan-23 at 15:07

            You can define spanGaps: true on your dataset.

            spanGaps: If true, lines will be drawn between points with no or null data.

            For further details, consult the Line Styling section of the Chart.js documentation.

            Source https://stackoverflow.com/questions/70798345

            QUESTION

            Return value evaluation of a stored function inside a loop with let variable
            Asked 2022-Jan-19 at 11:17

            To my understanding, if the loop variable of a for loop is defined with var, then any change on that variable is applied globally. for example:

            ...

            ANSWER

            Answered 2022-Jan-19 at 11:17

            however, the above code prints 3. What is the reason for this?

            Because you assign 3 to the i variable that printNumTwo closes over. It doesn't matter that the assignment happens after printNumTwo is created, only that it is the variable that printNumTwo is using.

            The difference between var and let in for loops is that a new variable is created for the body of the loop on each loop iteration with let. But you're assigning to that variable within the loop body, so the function closing over (printNumTwo) it sees that value later when you call it.

            It's exactly like this:

            Source https://stackoverflow.com/questions/70769427

            QUESTION

            JavaScript: filter array of objects using an object
            Asked 2022-Jan-09 at 20:19

            I was trying to do the following challenge from freecodecamp: https://www.freecodecamp.org/learn/javascript-algorithms-and-data-structures/intermediate-algorithm-scripting/wherefore-art-thou and I have a couple questions about it.

            1. Why is my attempt working in my local console but not on freecodecamp? Meaning, out of all the tests, 3 out of 4 are correct in my console, but none of them is on FCC.
            2. Why is this test whatIsInAName([{ "apple": 1, "bat": 2 }, { "bat": 2 }, { "apple": 1, "bat": 2, "cookie": 2 }], { "apple": 1, "bat": 2 }) not passing if all the others are?

            My attempt with expected results:

            ...

            ANSWER

            Answered 2022-Jan-09 at 20:19
            • Using Object#entries, get the list of key-value pairs from source
            • Using Array#filter, iterate over collection. In every iteration, using Array#every, check if all entries in the above sourceEntries match the current object

            Source https://stackoverflow.com/questions/70644869

            QUESTION

            Variadic Struct is Bloated, Extra Padding Being Added At The End of the Struct
            Asked 2021-Dec-11 at 20:12

            I have been following this tutorial for creating a variadic structure, which is nearly identical to another tutorial on creating a rudimentary tuple from scratch. Unfortunately when I analyze the variadic structure it seems very inefficient. The size of the structure seems bloated as in the struct's size does not seem to match its variable layout. It doesn't seem like byte alignment is the issue since actual tuples do not seem to suffer from this effect so I was wondering how they get around it, or what I am doing wrong in my struct.

            Below is the code I have been using to test the variadic struct:

            ...

            ANSWER

            Answered 2021-Dec-11 at 20:12

            Even an empty class needs space to store itself, the minimum size of a class is therefore 1. As your no argument DataStructure class is empty and a member it takes up space and causes the rest of the members to take more space to allow for alignment. Making the base non-empty fixes the issue:

            Source https://stackoverflow.com/questions/70317895

            QUESTION

            Choosing collisions of hash functions
            Asked 2021-Nov-27 at 09:44

            According to the condition of the problem, it is necessary to "break" the standard hash "gcc". It is necessary for the program to run for more than 1.5 seconds according to the input data. 15000 string with up to 15 characters 0-9A-Za-z_ is appended to unordered_set. If I understand correctly, it is necessary to choose such strings, the hash of which will be the same, but it is not clear how

            ...

            ANSWER

            Answered 2021-Nov-27 at 09:44

            In order to make the program slow, you'd need to find 15000 strings (15 chars or less) with an identical hash. That will degrade the performance of insertion on unordered_set to be equivalent to searching within a linked list for a duplicate and appending the new string at the end.

            If your code is running in the 32-bit space, a brute force attack on std::hash is feasible to find 15000 strings with the same hash.

            Each string is at most 15 characters long. Each character is one of 63 different values (A-Z, a-z, 0-9, or _). For a 15 character string, that's 63ยนโต possible combinations. But... std::hash returns a size_t value. And sizeof(size_t) == 4 on 32-bit machines. Intuitively thinking... if you hash 4 billion unique strings, you should find at least one pair of strings with identical hashes. And 63ยนโต divided by 2ยณยฒ is in the neighborhood of 227 quadrillion string with matching hashes for any given 15 character string in your allowed char set. We only need 15000. And we don't necessarily need a 15 character string either.

            So if we hash all strings from "AAAAAAAAAAAAAAAAA" to "ZZZZZZZZZZZZZZZ" to find a given hash, we'll eventually find 15000 unique strings that have the same hash. We can use a shorter string size too to reduce the complexity of hashing.

            Basically the algorithm is this:

            Source https://stackoverflow.com/questions/70129964

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