estrada | Very lightweight javascript router manager | Router library
kandi X-RAY | estrada Summary
kandi X-RAY | estrada Summary
Estrada is a lightwell router manager crafted with no dependencies and based to work on major browsers (IE9+). It was inspired by Backbone Router.
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Community Discussions
Trending Discussions on estrada
QUESTION
I don't know why this is happening but I need help to understand why the program is crashing. My program intends to use the Kruskal algorithm to find the lightest paths between cities (airports and roads). For this, it creates an undirected graph that links the vertices with the assigned arcs. However, after I introduce the number of cities, airports and roads, the program crashes.
Full code:
...ANSWER
Answered 2021-Jan-25 at 19:02QUESTION
I'm having the error that is in the title. I don't really get where it's coming from but the error is located in line 26 of the following code:
...ANSWER
Answered 2021-Jan-17 at 14:47The error message is pretty self-explanatory: the "Edge" in line 26 is undeclared, just as it sais:
graph->edge = Edge[E];
Edge is a type in your code, so Edge[E] does not really make sense. You would use the [] indexing operator on arrays, so that is definitely a problem there.
I guess I know what you wanted to do there, you wanted to create an array of Edge types. Try it like this:
graph->edge = (struct Edge*)malloc(E * sizeof(struct Edge));
Since you have a pointer in graph, you need to allocate the memory for that. But don't forget to delete it at the end.
free(graph->edge);
Or else you will get a memory leak.
QUESTION
I have a list called transactions_clean, cleaned up from whitespace etc., look like this:
...ANSWER
Answered 2021-Jan-06 at 11:01When you iterate over your list by for item in transactions_clean:
you get items for each list, so indexing them like item[1]
would just give you string characters. If the order is always like customer -> sale -> thread_sold, you can do something like this:
QUESTION
import React from 'react';
import {ImageBackground, Image, TouchableOpacity, TextInput, Text, View, Keyboard, } from 'react-native';
import { NavigationContainer } from '@react-navigation/native';
import { createStackNavigator } from '@react-navigation/stack';
import styles from "./comp/styles.js"
import listadoPrep from "./comp/list.json";
class HomeScreen extends React.Component{
constructor(){
super();
this.state={
sueldo:'',
}
}
submit(){
for (let key of Object.keys(listadoPrep)) {
if(this.state.sueldo <= listadoPrep[key][0]) {
console.warn("howdoisavethis")
}
}
this.props.navigation.navigate('Screen2', {
})
}
render(){
return (
¿Cuál es tu sueldo bruto?
{this.setState({sueldo:text})}}/>
{this.submit()}}>
Siguiente
);}}
function Screen2() {
return (
☕
);
}
const Stack = createStackNavigator();
function App() {
return (
);
}
export default App;
...ANSWER
Answered 2020-Oct-28 at 19:18I think I solved it. I add my solution for if anyone finds it useful in the future. Solved it by eliminating the class while passing parameters to routes
QUESTION
Image of csv file I have a csv file which looks like the image provided. I am reading the csv file, defined a pattern and using spacy Matcher. I am iterating through the rows and columns of the CSV file. My end goal is to identify the email Ids and SSN numbers as sensitive information and encrypt and decrypt them. But unfortunately all the information is getting encrypted and decrypted in the process.
...ANSWER
Answered 2020-Jun-17 at 13:03I must say I don't understand why you're using spacy to match things you specify as a regular expression which could be matched equally well and more simply by ordinary regular expressions.
I've got it at least indicating email address that need encrypting - I'm sure you can do the rest.
I had to change your regex so it actally matched an email address. In particular you had +@
in your regular expression which seems like a way to not match an email address as they don't include a space before the @. I changed that to *@
but that space probably shouldn't be there. Also the bit before the space didn't have a +
after it. And I simplified the bit after the @
, I'm sure you can sort that out.
Also I had to specifically skip the header row of the CSV.
You weren't actually detecting a match so you were encrypting everything - this code detects a non-empty span
as requiring encrypting. You will have to handle if there are multiple span
s in a match.
Python 3.8.3 code (you'll have to edit the print()
statements where they use the new f"{value=}" syntax)
QUESTION
I am new to web-development and am having some issues deploying my very basic website with Heroku. Upon creating my app, I have successfully pushed my app to git and deployed it to Heroku. Also, it does run locally just fine.
However, upon opening the app (using "Heroku open" command and clicking the "Open app" button on the Heroku app page itself), I am getting a page that says Not Found.
I have been searching for a solution all over and would really appreciate some help here. Thank you.
Procfile:
...ANSWER
Answered 2020-Apr-14 at 06:59The express.static middleware is separate from res.sendFile, You need to use an absolute path directly with res.sendFile. you can do it:
make a public directory in current project folder and put you html file there.
include path module in the server.js file like
const path = require('path');
- replace your res.sendFile with below line of code
res.sendFile(path.join(__dirname, './public', 'Apr29Home.html'));
Note: __dirname returns the directory that the currently executing script is in.
QUESTION
I'm working on a project in python where I get a json from a REST API using requests and then proceed to load it into a PostgreSQL database. The json the API responds with is strctured like shown below. My main issue is concerning the nested fields, like location.lat
and the fields nested in the info
array, like info[0].value
.
{
...
ANSWER
Answered 2020-Feb-19 at 02:02for future reference, solved it like so:
QUESTION
My app was running well, then suddenly it's failed with error "Cannot read property 'answers' of undefined".
Here is the following piece of code:
...ANSWER
Answered 2020-Jan-03 at 16:26The error is on this line:
QUESTION
I'm a very unexperienced user of REST APIs, requests and python, so bear with me. I've managed to throw a GET request using requests via python towards this REST API that was developed with Postman. I get results fine, but only for the first page (only 50 items). I know that all I need to do in order to get more results is adding '?page=2' and so on to the URL, but somehow I couldn't manage the loop so far. It appears to me that this API doesn't have the "nextUrl" or total number of pages features, so I'm a bit lost. This is what I have so far:
...ANSWER
Answered 2020-Feb-08 at 02:19Since we don't know the number of pages( the available projectid
), you can use try & except
as below:
QUESTION
Below is some code: I want to run the final for loop and I receive this asinine unindent error upon compilation. I know python's indentation rules are pretty straight forward and more or less represent {} in C. WHY am I getting "
...ANSWER
Answered 2019-Aug-17 at 00:32It's hard to tell for sure what's going on in your code because StackOverflow automatically replaces tabs with spaces in code blocks.
However, as others have suggested, it is likely you have a mix of tab characters and spaces in your code. We say this because we have made the same mistake ourselves many times in the past. Sometimes many times in the same 10 minutes.
Usually it is suggested to always use 4 spaces per indent. I prefer a little less (2 or 3) but I have forced myself to go with the rest of society and adhere to the PEP 8 Style Guide for Python Code that says 4.
Most code editors can be configured to replace a typed tab character with a programmable number of spaces (usually defaulting to 4). Also, many code editors have a command to replace all with spaces for in a file. I use this one a lot. I use Geany a lot as a code editor, but every time I do a new install on a different machine, I have to remember to set the option to use ONLY spaces for indentation.
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