BRouter | BRouter 是一个 Kotlin 编写的面向模块 Android 路由库，支持： | Router library

by bilibili Kotlin Version: v1.0.0 License: No License

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kandi X-RAY | BRouter Summary

BRouter is a Kotlin library typically used in Networking, Router applications. BRouter has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

BRouter 是一个 Kotlin 编写的面向模块 Android 路由库，支持：.

Support

Quality

Security

License

Reuse

Support

BRouter has a low active ecosystem.

It has 298 star(s) with 26 fork(s). There are 12 watchers for this library.

It had no major release in the last 6 months.

There are 7 open issues and 3 have been closed. On average issues are closed in 146 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of BRouter is v1.0.0

Quality

BRouter has no bugs reported.

Security

BRouter has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

BRouter does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

BRouter releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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BRouter Key Features

No Key Features are available at this moment for BRouter.

BRouter Examples and Code Snippets

No Code Snippets are available at this moment for BRouter.

Community Discussions

Trending Discussions on BRouter

I have to iterate some if-else conditions for each row in data-frame in python

QUESTION

I have to iterate some if-else conditions for each row in data-frame in python

Asked 2018-Jun-28 at 11:23

I have to iterate some if-else conditions for each row in dataframe in python.

If the first condition is satisfied for row1, it will answer 'yes' or 'no' by adding one more column for that row and exit.

But if for the row 2, with another other condition satisfied, it shouldn’t overwrite the first row’s ‘yes’ or ‘no’.

I want it to be preserved or we can say in second iteration it should check all if else conditions for only row2 and then row3 and so on.

To be precise, only one row will be check against all the condition and which ever condition satisfy, it will give the output by adding one more column for that row and exit.

I am new to python and the code I wrote is not working.

I have written the below code. Kindly help me.

...

ANSWER

Answered 2018-Jun-27 at 22:21

You shouldn't need to iterate rows explicitly. In fact, you shouldn't need to calculate the same Boolean values multiple times.

If you wish to prioritise a particular assignment given a condition, you can do so explicitly. Here's one way using numpy.where; we use ~ to indicate "negative".

Source https://stackoverflow.com/questions/51072138

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install BRouter

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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