code-segment | 代码集和收藏项目目录。包括数据结构,算法,练习等的简单实现以及收藏项目列表。 | Learning library
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kandi X-RAY | code-segment Summary
代码集和收藏项目目录。包括数据结构,算法,练习等的简单实现以及收藏项目列表。
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Community Discussions
Trending Discussions on code-segment
QUESTION
I am working on a proof-of-concept app, written in Rust, with the end goal being to produce a shared library (.dll/.so) callable via C ABI from a number of other languages (C++, C#, etc). I have two simple components; poc
is a Rust console app, which references poclib
which exposes some simple functions. The app itself builds and runs fine so far, but I am stuck on how to debug it in VSCode using CodeLLDB.
I have a top level "workspace" like this:
...ANSWER
Answered 2021-Jun-10 at 15:46I don't understand why it worked at all initially, but the solution was to fix the crate_type
option so that I'm producing both C ABI libraries and native Rust libraries.
QUESTION
Consider the string "abc를"
. According to unicode's demo implementation of word segmentation, this string should be split into two words, "abc"
and "를"
. However, 3 different Rust implementations of word boundary detection (regex
, unic-segment
, unicode-segmentation
) have all disagreed, and grouped that string into one word. Which behavior is correct?
As a follow up, if the grouped behavior is correct, what would be a good way to scan this string for the search term "abc" in a way that still mostly respects word boundaries (for the purpose of checking the validity of string translations). I'd want to match something like "abc를"
but don't match something like abcdef
.
ANSWER
Answered 2021-Feb-06 at 23:58I'm not so certain that the demo for word segmentation should be taken as the ground truth, even if it is on an official site. For example, it considers "abc를"
("abc\uB97C"
) to be two separate words but considers "abc를"
("abc\u1105\u1173\u11af"
) to be one, even though the former decomposes to the latter.
The idea of a word boundary isn't exactly set in stone. Unicode has a Word Boundary specification which outlines where word-breaks should and should not occurr. However, it has an extensive notes section for elaborating on other cases (emphasis mine):
It is not possible to provide a uniform set of rules that resolves all issues across languages or that handles all ambiguous situations within a given language. The goal for the specification presented in this annex is to provide a workable default; tailored implementations can be more sophisticated.
For Thai, Lao, Khmer, Myanmar, and other scripts that do not typically use spaces between words, a good implementation should not depend on the default word boundary specification. It should use a more sophisticated mechanism, as is also required for line breaking. Ideographic scripts such as Japanese and Chinese are even more complex. Where Hangul text is written without spaces, the same applies. However, in the absence of a more sophisticated mechanism, the rules specified in this annex supply a well-defined default.
...
My understanding is that the crates you list are following the spec without further contextual analysis. Why the demo disagrees I cannot say, but it may be an attempt to implement one of these edge cases.
To address your specific problem, I'd suggest using Regex
with \b
for matching a word boundary. This unfortunately follows the same unicode rules and will not consider "를"
to be a new word. However, this regex implementation offers an escape hatch to fallback to ascii behaviour. Simply use (?-u:\b)
to match a non-unicode boundary:
QUESTION
In the article on the GDT the OSDev wiki describes the flag that is used as D bit for CS descriptors as follows:
Sz: Size bit. If 0 the selector defines 16 bit protected mode. If 1 it defines 32 bit protected mode. You can have both 16 bit and 32 bit selectors at once.
Another question quotes the Intel manuals: What does the D flag in the code segment descriptor do for x86-64 instructions? which links to the part "3.4.5 Segment Descriptors" from Intel 64 and IA-32 Architectures Software Developer’s Manual Volume 3 [...]: System Programming Guide, reading:
D/B (default operation size/default stack pointer size and/or upper bound) flag
Performs different functions depending on whether the segment descriptor is an executable code segment, an expand-down data segment, or a stack segment. (This flag should always be set to 1 for 32-bit code and data segments and to 0 for 16-bit code and data segments.)
• Executable code segment. The flag is called the D flag and it indicates the default length for effective addresses and operands referenced by instructions in the segment. If the flag is set, 32-bit addresses and 32-bit or 8-bit operands are assumed; if it is clear, 16-bit addresses and 16-bit or 8-bit operands are assumed. The instruction prefix 66H can be used to select an operand size other than the default, and the prefix 67H can be used select an address size other than the default.
The question is, what does "D" stand for?
...ANSWER
Answered 2020-Jul-28 at 12:04I found a copy of the Intel 80386 Programmer's Reference Manual, 1987 which has the following descriptions in 16.1 How the 80386 Implements 16-Bit and 32-Bit Features:
The features of the architecture that permit the 80386 to work equally well with 32-bit and 16-bit address and operand sizes include:
The D-bit (default bit) of code-segment descriptors, which determines the default choice of operand-size and address-size for the instructions of a code segment. (In real-address mode and V86 mode, which do not use descriptors, the default is 16 bits.) A code segment whose D-bit is set is known as a USE32 segment; a code segment whose D-bit is zero is a USE16 segment. The D-bit eliminates the need to encode the operand size and address size in instructions when all instructions use operands and effective addresses of the same size.
Instruction prefixes that explicitly override the default choice of operand size and address size (available in protected mode as well as in real-address mode and V86 mode).
Separate 32-bit and 16-bit gates for intersegment control transfers (including call gates, interrupt gates, and trap gates). The operand size for the control transfer is determined by the type of gate, not by the D-bit or prefix of the transfer instruction.
Registers that can be used both for 32-bit and 16-bit operands and effective-address calculations.
The B-bit (big bit) of data-segment descriptors, which determines the size of stack pointer (32-bit ESP or 16-bit SP) used by the CPU for implicit stack references.
So "D bit" stands for "Default operand and address size" (for code segments) and "B bit" for "Big" (for stack segments).
QUESTION
In C++ when joining a bunch of strings (where each element's size is known roughly), it's common to pre-allocate memory to avoid multiple re-allocations and moves:
...ANSWER
Answered 2019-Oct-29 at 17:44Your original code is fine and I do not recommend changing it.
The original version allocates once: inside String::with_capacity
.
The second version allocates at least twice: first, it creates a Vec<&str>
and grows it by push
ing &str
s onto it. Then, it counts the total size of all the &str
s and creates a new String
with the correct size. (The code for this is in the join_generic_copy
method in str.rs
.) This is bad for several reasons:
- It allocates unnecessarily, obviously.
- Grapheme clusters can be arbitrarily large, so the intermediate
Vec
can't be usefully sized in advance -- it just starts at size 1 and grows from there. - For typical strings, it allocates way more space than would actually be needed just to store the end result, because
&str
is usually 16 bytes in size while a UTF-8 grapheme cluster is typically much less than that. - It wastes time iterating over the intermediate
Vec
to get the final size where you could just take it from the original&str
.
On top of all this, I wouldn't even consider this version idiomatic, because it collect
s into a temporary Vec
in order to iterate over it, instead of just collect
ing the original iterator, as you had in an earlier version of your answer. This version fixes problem #3 and makes #4 irrelevant but doesn't satisfactorily address #2:
QUESTION
More broadly the question really is - when an exception is generated in v8086 mode that is propagated to a protected-mode interrupt/trap gate, does an error code get pushed onto the stack after the return address is pushed for those exceptions with an error code?
Say for instance I am running in V8086 mode (CPL=3, VM=1, PE=1) with an IOPL of 0. I would expect that the privileged instruction HLT
should raise a #GP exception. NASM code could look something like:
ANSWER
Answered 2019-Sep-15 at 16:27TL;DR: The pseudo-code in the Intel instruction set reference is incorrect. If an exception in v8086 mode causes a protected mode call/interrupt gate to execute an exception handler then an error code will be pushed if the exception is one of those with an error code. #GP has an error code and it will be pushed on the ring 0 stack before transferring control to your #GP handler. You must manually remove it prior to doing an IRET
.
The answer is that an exception in Virtual 8086 mode (v8086 or v86) that is processed by a protected mode handler (through an interrupt or trap gate) will have the error code pushed for those exceptions that use one (including #GP). The pseudo-code should have been:
QUESTION
While trying to reverse a string, I found the method mentioned in the title
i.e. UnicodeSegmentation::graphemes
I referred to the official documentation for usage, but there were two different references which bothered me a lot.
the first one works but the second does not.
To be specific: the function I coded using the first method:
...ANSWER
Answered 2019-Jun-02 at 05:17The first link is up-to-date. The second is to the documentation for version 1.2.0. There is a button on the bar at the head of the page to “Go to latest version.”
QUESTION
When I try to cargo build
the 'hello world' of amethyst on Ubuntu 18.04, I get an error about missing libraries from lxbcb. I'm not sure what this error is trying to tell me or how to fix it. It seems like I'm missing libraries -lxcb-render
, -lxcb-shap
, and -lxcb-xfixes
, but I can't seem to find them.
The hello world code of amethyst
...ANSWER
Answered 2019-Apr-21 at 06:53It looks like I missed installing some dependencies.
sudo apt install pkg-config libasound2-dev libssl-dev cmake libfreetype6-dev libexpat1-dev libxcb-composite0-dev
QUESTION
Do the lambdas and the functions saved on the 4'th part: 'text'/code segments(it had multiple names)?
Why am I askingI know that objects are disposable by the garbage collector and I remember that nothing on the code-segment will be deleted until the process is destroyed so how does Javascript claims that functions are objects?
...ANSWER
Answered 2019-Mar-02 at 16:01Do the lambdas and the functions saved on the 4th part: 'text'/code segments(it had multiple names)?
Yes. But the instances of those functions are saved on heap segment.
JavaScript GC collects instances of the function, not the function itself which is just code.
QUESTION
How to extract date and time from created_at field in the database,
...ANSWER
Answered 2018-Nov-01 at 18:37Laravel/Eloquent uses the Carbon library for their timestamps, so you can use their methods:
QUESTION
I'm implementing a scanner in Rust. I have a scan
method on a Scanner
struct which takes a string slice as the source code, breaks that string into a Vec<&str>
of UTF-8 characters (using the crate unicode_segmentation
), and then delegates each char to a scan_token
method which determines its lexical token and returns it.
ANSWER
Answered 2018-Nov-27 at 21:38Your problem can be reduced to this:
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PHP requires the Visual C runtime (CRT). The Microsoft Visual C++ Redistributable for Visual Studio 2019 is suitable for all these PHP versions, see visualstudio.microsoft.com. You MUST download the x86 CRT for PHP x86 builds and the x64 CRT for PHP x64 builds. The CRT installer supports the /quiet and /norestart command-line switches, so you can also script it.
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