collision | numpy bindings for efficient triangle | Image Editing library
kandi X-RAY | collision Summary
kandi X-RAY | collision Summary
simple C++ collision detection library with numpy bindings for efficient triangle-mesh interactions and point cloud interactions. This approach is inspired by: makes use of numpy-boost: tips on building:
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Top functions reviewed by kandi - BETA
- Plot the simulation
- Merge two actors
- Integrate the mesh with the given dt
- Set the data
- Draw stars
- Draw the vertex shader
- Generate a new experiment
- Generate stars in the program
- Create an icospherehed mesh
- Refine a sphere
- Creates an icosahedron
- Triangulates a list of vertices
- Generate a geodesic curve
- Compute the angles of the collision
- Compute the divergence of the mesh
- Normalize a vector of vectors
- Prepare the spatial grid
- Returns a spatial grid
- Integrate the velocity
- The relaxation function
- Rotate the robot
- Compute the incidence matrix
- Generate a set of points
- Set the data
- Save the mesh to a STL file
- Calculate forces
collision Key Features
collision Examples and Code Snippets
def _collision_resolution(self, key, data=None):
i = 1
new_key = self.hash_function(key + i * i)
while self.values[new_key] is not None and self.values[new_key] != key:
i += 1
new_key = (
def _collision_resolution(self, key, data=None):
i = 1
new_key = self.hash_function(data)
while self.values[new_key] is not None and self.values[new_key] != key:
new_key = (
self.__hash_double_func
void handleCollision(Collection toCheck, HashMap allBubbles) {
var toBePopped = false; //if any other bubble collides with it, made true
for (var point : toCheck) {
var otherId = point.id;
if (allBubbles.get(otherId) != null &
Community Discussions
Trending Discussions on collision
QUESTION
I'm trying to use Matter.Query.region
to see if the character in my game is grounded. But, when I try to run region
with a bounds object that I created (displayed with the dots shown in the game), it doesn't come up with any collisions even though it is clearly intersecting other bodies.
Code:
...ANSWER
Answered 2022-Mar-24 at 00:20The bounds object doesn't appear to be properly created. The purple p5 vertices you're rendering may be giving you a false sense of confidence, since those aren't necessarily related to what MJS sees.
It's actually a pretty simple fix, passing an array of vertices instead of individual arguments:
QUESTION
It turns out that the function rlang::expr_interp()
essentially meets my goal.
ANSWER
Answered 2022-Mar-19 at 19:56Do you really need to store your desired symbols in an environment? It seems if you are just storing symbols/expressions then you can more easily do that in a container like exprs
and then can use the with_bindings
function to replace some values. So if you have
QUESTION
So, fundamentally, this question is Not opinion-based. I seriously pursuit this issue objectively without feeling mostly arisen from the predominant opinion - Why is extending native objects a bad practice?
and this quesion is related but unanswered questions:
Should the extension of built-in Javascript prototypes through symbols also be avoided?
The first question is already closed as they say it's opinion based, and as you might know in this community once a question is Banned, however we modified it, moderators will never bother to re-open. That is the way how the things work here.
For the second question. For some unknown reason, the question has been taken more seriously and not considered as opinion based although the context is identical.
There are two parts to the "don't modify something you don't own" rule:
You can cause name collisions and you can break their code.
By touching something you don't own, you may accidentally overwrite something used by some other library. This will break their code in unexpected ways.
You can create tight dependencies and they can break your code.
By binding your code so tightly to some other object, if they make some significant change (like removing or renaming the class, for example), your code might suddenly break.
Using symbols will avoid #1, but you still run into #2. Tight dependencies between classes like that are generally discouraged. If the other class is ever frozen, your code will still break. The answers on this question still apply, just for slightly different reasons.
Also, I've read opinions(how can we discuss such a thing here without "opinion" base?), they claim
a) Library code Using Symbols exists and they may tweak Symbol API (such as Object.getOwnPropertySymbols())
b) extending object property with Symbol is not different from non-Symbol property fundamentally.
Here, for the major rationale of untouching Object.prototype
is due to #1, almost all answers I saw claimed that and we don't have to discuss if there is no Symbol usage.
However, Using symbols will avoid #1 as they say. So most of the traditional wisdom won't apply anymore.
Then, as #2 says,
By binding your code so tightly to some other object, if they make some significant change (like removing or renaming the class, for example), your code might suddenly break.
well, in principle, any fundamental API version upgrade will break any code. The well-known fact is nothing to do with this specific question. #2 did not answer the question.
Only considerable part is Object.freeze(Object.prototype)
can be the remaining problem. However, this is essentially the same manner to upgrade the basic API by some other unexpectedly.
As the API users not as API providers, the expected API of Object.prototype
is not frozen.
If some other guys touch the basic API and modifies it as frozen, it is he/she who broke the code. They upgraded the basic API without notice.
For instance, in Haskell, there are many language extensions. Probably they solve the collision issue well, and most importantly, they won't "freeze" the basic API because freezing the basic API would brake their eco.
Therefore, I observe that Object.freeze(Object.prototype)
is the anti-pattern. It cannot be justified as a matter of course to prevent Object.prototype
extension with Symbols.
So here is my question. Although I observe this way, is it safe to say:
In case of that Object.freeze(Object.prototype)
is not performed, which is the anti-pattern and detectable, it is safe to perform extending Object.prototype
with Symbols?
If you don't think so, please provide a concrete example.
...ANSWER
Answered 2022-Mar-17 at 03:18Extending the Object prototype is a dangerous practice.
You have obviously done some research and found that the community of javascript developers overwhelmingly considers it to be a very bad practice.
If you're working on a personal project all by yourself, and you think the rest of us are all cowards for being unwilling to take the risk, then by all means: go ahead and modify your Object prototype! Nobody can stop you. It's up to you whether you will be guided by our advice. Sometimes the conventional wisdom is wrong. (Spoiler: in this case, the conventional wisdom is right.)
But if you are working in a shared repository, especially in any kind of professional setting, do not modify the Object prototype. Whatever you want to accomplish by this technique, there will be alternative approaches that avoid the dangers of modifying the base prototypes.
The number one job of code is to be understood by other developers (including yourself in the future), not just to work. Even if you manage to make this work, it is counterintuitive, and nobody who comes after you will expect to find this. That makes it unacceptable by definition, because what matters here is reasonable expectations, NOT what the language supports. Any person who fails to recognize that professional software development is a team effort has no place writing software professionally.
You are not going to find a technical limitation to extending the Object prototype. Javascript is a very flexible language -- it will give you plenty of rope with which to hang yourself. That does not mean it's a good idea to place your head in the noose.
QUESTION
I am analyzing large (between 0.5 and 20 GB) binary files, which contain information about particle collisions from a simulation. The number of collisions, number of incoming and outgoing particles can vary, so the files consist of variable length records. For analysis I use python and numpy. After switching from python 2 to python 3 I have noticed a dramatic decrease in performance of my scripts and traced it down to numpy.fromfile function.
Simplified code to reproduce the problemThis code, iotest.py
- Generates a file of a similar structure to what I have in my studies
- Reads it using numpy.fromfile
- Reads it using numpy.frombuffer
- Compares timing of both
ANSWER
Answered 2022-Mar-16 at 23:52TL;DR: np.fromfile
and np.frombuffer
are not optimized to read many small buffers. You can load the whole file in a big buffer and then decode it very efficiently using Numba.
The main issue is that the benchmark measure overheads. Indeed, it perform a lot of system/C calls that are very inefficient. For example, on the 24 MiB file, the while
loops calls 601_214 times np.fromfile
and np.frombuffer
. The timing on my machine are 10.5s for read_binary_npfromfile
and 1.2s for read_binary_npfrombuffer
. This means respectively 17.4 us and 2.0 us per call for the two function. Such timing per call are relatively reasonable considering Numpy is not designed to efficiently operate on very small arrays (it needs to perform many checks, call some functions, wrap/unwrap CPython types, allocate some objects, etc.). The overhead of these functions can change from one version to another and unless it becomes huge, this is not a bug. The addition of new features to Numpy and CPython often impact overheads and this appear to be the case here (eg. buffering interface). The point is that it is not really a problem because there is a way to use a different approach that is much much faster (as it does not pay huge overheads).
The main solution to write a fast implementation is to read the whole file once in a big byte buffer and then decode it using np.view
. That being said, this is a bit tricky because of data alignment and the fact that nearly all Numpy function needs to be prohibited in the while loop due to their overhead. Here is an example:
QUESTION
I encountered next issue:
Error: ENOENT: no such file or directory, rename '/home/user/my-web/.next/export/en/cities/berlin.html' -> '/home/user/my-web/.next/server/pages/en/cities/berlin.html'
What's the problem? Name collision?
...ANSWER
Answered 2021-Sep-23 at 07:38Discussed here: NPM: ENOENT: no such file or directory, rename
Possible reason, some node process is running. Check the running processes.
Easiest fix, delete package-lock.json and then reinstall packages. If this does not work, refer the given link for other possible resolutions and explanations.
QUESTION
I have this error when I touch a wall to change scene:
Cannot read properties of undefined (reading 'start')
I tried several techniques but none worked, yet I have no other errors and my code is quite simple and I don't understand why it doesn't work... Here is my code:
...ANSWER
Answered 2022-Feb-15 at 13:01The problem is this line:
QUESTION
Basically, I need to define infix operator for function composition, flipped g . f
manner.
ANSWER
Answered 2022-Feb-11 at 01:54You don't see a list of Haskell built-in operators for the same reason you don't see a list of all built-in functions. They're everywhere. Some are in Prelude
, some are in Control.Monad
, etc., etc. Operators aren't special in Haskell; they're ordinary functions with neat syntax. And Haskellers are generally pretty operator-happy in general. Spend any time inside your favorite lens library and you'll find plenty of amusing-looking operators.
In terms of (#)
, it might be best to avoid. I don't know of any built-in operators called that, but #
can be a bit special when it comes to parsing. Specifically, a compiler extension enables #
at the end of ordinary identifiers, and GHC defines a lot of built-in (primitive) types following this practice. For instance, Int
is the usual (boxed) integer type, whereas Int#
is a primitive integer. Most people don't need to interface with this directly, but it is a use that #
has in Haskell that would be confused slightly by the addition of your operator.
Your (#)
operator is called (>>>)
in Haskell, and it works on all Category
instances, including functions. Its companion is (<<<)
, the generalization of (.)
to all Category
instances. If three characters is too long for you, I've seen it called (|>)
in some other languages, but Haskell already uses that operator for something else. If you're not using Data.Sequence
, you could use that operator. But personally, I'd just go with (>>>)
. Any Haskeller will recognize it pretty quickly.
QUESTION
I am aware of the next scenario: (Weird formatting, I know)
...ANSWER
Answered 2022-Jan-20 at 17:24The Java memory model is sequential consistency in the absence of data races (which your program doesn't have). This is very strong; it says that all reads and writes in your program form a total order, which is consistent with program order. So you can imagine that reads and writes from different threads simply get interleaved, or shuffled together, in some fashion - without changing the relative ordering of actions made from the same thread as each other.
But for this purpose, every action is a separate element in this order.
So just by the mere fact that aBoolean.get()
and aBoolean.compareAndSet()
are two actions and not one action, it is possible for any number of other actions by other threads to take place in between them.
It doesn't matter whether those actions are part of a single statement, or different statements; or what kind of expression they appear in; or what operators (if any) are between them; or what computations the thread itself may or may not be doing around them. There is no way in which two actions can be "so close together" that nothing else can happen in between, short of replacing them by a single action defined to be atomic by the language.
At the level of the machine, a very simple way this can happen is that, since aBoolean.get()
and aBoolean.compareAndSet()
are almost certainly two different machine instructions, an interrupt may arrive in between them. This interrupt could cause the thread to be delayed for any amount of time, during which other threads could do anything they wish. So it is entirely possible that threads #1 and #2 are both interrupted in between their get()
and compareAndSet()
, and that thread #3 executes its set
in the meantime.
Caution: Reasoning about how a particular machine might work is often useful for understanding why undesired behavior is possible, as in the previous paragraph. But it is not a substitute for reasoning about the formal memory model, and should not be used to try to argue that a program must have its desired behavior. Even if a particular machine you have in mind would do the right thing for your code, or you can't think of a way in which a plausible machine would fail, that does not prove that your program is correct.
So trying to say "oh, the machine will do a lock cmpxchg
and so blah blah blah and everything works" isn't wise; some other machine you haven't thought of might work in a totally different fashion, that still complies with the abstract Java memory model but otherwise violates your x86-based expectations. In fact, x86 is a particularly poor example for this: for historical reasons, it provides a rather strong set of instruction-level memory ordering guarantees that many other "weakly ordered" architectures do not, and so there may be many things that Java abstractly allows but that x86 in practice won't do.
QUESTION
When running dbt jobs in Meltano, dbt run
jobs may collide with each other if run out of a triggered context - for instance, when an on-demand job collides with a scheduled job or a CI-based job.
If dbt run
operates on the same tables at the same time, this generally causes a crash and sometimes a data quality issue if the same insert is performed twice on a single target table.
Any way to prevent run collisions, using either Meltano functionality or native dbt functionality?
...ANSWER
Answered 2021-Dec-16 at 18:22One way is to generate a lock in your target database. Here's an example for MSSQL.
I chose a on-run-start: hook. This hook attempts to grab a lock for dbt that lasts for the duration of the DB session.
dbt_project.yml
QUESTION
I want to retrieve the entire sentence that surrounds a link, delimited by punctuation (such as . or ! or ? or newline).
The purpose is to provide a better context for the link.
So for example if i have this...
...ANSWER
Answered 2021-Dec-21 at 10:27Granted you do not care about abbreviations, you can match either a char other than ?
, !
and .
, or a link-like substring any zero or more times before and after a specific filter string:
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Vulnerabilities
No vulnerabilities reported
Install collision
You can use collision like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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