pentagon | building repeatable | Infrastructure Automation library
kandi X-RAY | pentagon Summary
kandi X-RAY | pentagon Summary
Pentagon is a cli tool to generate repeatable, cloud-based [Kubernetes] infrastructure. It can be used as a “batteries included” default which can: - provide a network with a cluster - Two HA KOPS based Kubernetes clusters - Segregated multiple development / non-production environments - VPN-based access control - A highly-available network, built across multiple Availability Zones.
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Top functions reviewed by kandi - BETA
- Runs the cluster
- Get the cluster configuration
- Get the cluster yaml file
- Get cluster admin secret
- Startentagon migration
- Return the current version of the git repository
- List available migrations
- Get the infrastructure repository
- Return information about the instance
- Perform API calls to API
- Returns a list of ElastiCacheClusters for the given region
- Add an Elasticache cluster to the inventory
- Configure the default project
- Adds the context to the production cluster
- Creates a kubernetes kubernetesk cluster context
- Start the project
- Write config file to config file
- Check if the repository directory exists
- Add a new configuration
- Create ssh keys
- Add a new configuration entry
- Add a new vpc
- Decorator to register filters
- Return a list of package files
- Return the context of the VPC
- Read config file
pentagon Key Features
pentagon Examples and Code Snippets
Lines of Code : 6
License : No License
Copypublic static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter the side: ");
double s = in.nextDouble();
System.out.println("The area of the pentagon is " + area(s));
} @Override
public String getType() {
return "Pentagon";
} Community Discussions
Trending Discussions on pentagon
QUESTION
The columns of a multi-index data frame, say,
...ANSWER
Answered 2021-May-30 at 21:05x = df_multi.mul(df_scale["factor"], level=0, axis="index")
print(x)
QUESTION
I would like to download the PDF files from https://www.archives.gov/research/pentagon-papers
...ANSWER
Answered 2021-May-19 at 15:20How about using the text from the tag as the name, as you wish?
Here's how:
QUESTION
All good times of day!
Faced with the following task: you need to find the shapes in the image, cut them out and save them in jpg or png.
Find the shapes worked out (attached the image), but how do I get their extreme coordinates?
I find shapes with EMGU CV.
I'm taking Image it out of PictureBox.
// - was like the idea to find the distance from the center to the edge of the figure through Moments, but did not understand how they work
...ANSWER
Answered 2021-May-08 at 18:09I found a solution to my question. There is a method that returns a description of the contour with an array of points.
QUESTION
I am making a Guardian game where you fire bullets at enemies and evolve. When you press the r key, your image changes. The image I want the player the turn into when the player hits the r key is an orange triangle with a red outline. The image that the player is before you press the r key is a yellow triangle with an orange outline. However, when I pressed the r key, instead of turning into an orange triangle with a red outline, you turn into a large yellow triangle with an orange outline.
Here is the player class (named Polygon):
...ANSWER
Answered 2021-Apr-23 at 04:40In your Sprite.upgrade() function, you first assign self.image = "triangle_plus.png" but immediately afterwards call check_image() which then overwrites self.image, undoing your previous change. You will probably want to return once you updated the image.
QUESTION
We are conducting shape detection using Python openCV. We find approx_poly_dp and then count number of vertices. However, the process does not work when object has many intersections (seen in second picture below). Opencv cannot detect individual objects, and just finds one large shape. In dealing with intersections, what is best way to find shapes, given general picture inputs. Or is this not a functionality of opencv, maybe better suited with machine learning?
...ANSWER
Answered 2021-Apr-17 at 09:44Following procedure might work for simple figures:
Find the connected components, and find neighboring components of each component ignoring the background and outline components.
Try a component with combinations of its neighboring components and feed it to the shape classifier that you already have. As a pre-processing step, you might have to combine the components into a single blob using a morphological closing.
QUESTION
I am making a Shape Defense game where you fire bullets at enemies and evolve from triangle, to square, to pentagon, and beyond. I am trying to make the game over image show. However, when an enemy and the player collide, pygame gives me an error that says TypeError: not a file object. How can I make the game over image show?
This is my current code:
...ANSWER
Answered 2021-Apr-15 at 16:00The image is loaded in your Sprite class:
QUESTION
I'm in need of a bit of code that takes a very simple math string and runs PHP's eval() function. For example ...
ANSWER
Answered 2021-Feb-17 at 22:07Using php, you can match those words that you don't want to remove and use a (*SKIP)(*FAIL) approach.
You can also shorten the character class by remove the backslashes, and if you use a different delimiter than / in php you also don't have to escape the /
As you are replacing the matched characters in the character class with an empty string, you can use a quantifier + to match 1 or more consecutive matches and do a single replacement.
QUESTION
I have a flex program written in C++ that needs to complete the following rules:
I want yytext to accept the following:
○ Zero or one of the following characters ABCDEFGH
For example - input:
"triangle ABC" is a valid shape and I want the program to print "Valid shape"
"triangle AAC" is not a valid shape because it contains a double A and I want the program to print nothing in this case
"triangle ABCD" is not a valid shape because it contains four letters and I want the program to print nothing in this case too.
The code below and what regular expressions I tried so far:
...ANSWER
Answered 2021-Feb-16 at 17:41This is not the sort of problem for which you would typically use (f)lex, since the base lexical analysis is trivial (it could be done by simply splitting the line at the space) and detailed error analysis is a bit outside of (f)lex's comfort zone, specifically because there's no way to match "a string containing the same character twice" using a regular expression.
Still, as shown by the question asked by one of your classmates, it can be done with (f)lex by taking advantage of the scanner's ordering rules:
- Always use the longest possible match.
- If two or more rules would qualify, choose the first one.
That doesn't get around the question of duplicate characters. The only way to solve that is to enumerate all possibilities, of which there are eight in this case. A simpler way of doing that than that proposed in the linked question is [A-H]*A[A-H]*A[A-H]*|[A-H]*B[A-H]*B[A-H]*|[A-H]*C[A-H]*C[A-H]*....
That let's you create an ordered set of rules something like this:
- Match lines with duplicate characters
- Match lines with too many characters
- Match lines with exactly the right number of characters
- Anything else is an error. (Too few characters, invalid shape name, invalid letter, etc.)
So that might include this (leaving out the definitions of the two macros, which is straightforward but tedious):
QUESTION
I am learning Julia for my next project because the data really text-heavy and we are looking into making the code run more efficiently and fast. So as experimentation, I am learning Julia.
Now I learned that there is a really nice way to enter the Unicode characters in Julia. For example:
"⎔" can be made using "\hexagon"+tab
Is there a way to get back the textual version of these Unicode characters?
So what I am kind of asking is:
For each of these:
...ANSWER
Answered 2020-Dec-27 at 17:55You can use this:
QUESTION
how can I bypass private mode detection with urllib3. I have the following code that does not work:
...ANSWER
Answered 2020-Dec-15 at 15:51Try this change (you need to specify a user-agent header):
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