dictionaries | Contains dictionaries related code and data | Dictionary library

by LibreOffice Python Version: cp-23.05.0-2 License: No License

X-Ray Key Features Code Snippets(4)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | dictionaries Summary

dictionaries is a Python library typically used in Utilities, Dictionary applications. dictionaries has no bugs, it has no vulnerabilities and it has low support. However dictionaries build file is not available. You can download it from GitHub.

Contains dictionaries related code and data. See for more information.

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Quality

Security

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Support

dictionaries has a low active ecosystem.

It has 352 star(s) with 300 fork(s). There are 35 watchers for this library.

It had no major release in the last 6 months.

There are 1 open issues and 22 have been closed. On average issues are closed in 355 days. There are 2 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of dictionaries is cp-23.05.0-2

Quality

dictionaries has 0 bugs and 1264 code smells.

Security

dictionaries has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

dictionaries code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

dictionaries does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

dictionaries releases are not available. You will need to build from source code and install.

dictionaries has no build file. You will be need to create the build yourself to build the component from source.

dictionaries saves you 19505 person hours of effort in developing the same functionality from scratch.

It has 38475 lines of code, 189 functions and 133 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed dictionaries and discovered the below as its top functions. This is intended to give you an instant insight into dictionaries implemented functionality, and help decide if they suit your requirements.

Do a proofreading
Performs proofreading
Capitalize characters
Compile regular expressions
Return the rule for the given language
Parse the blacklist
Return a string for classification
Load lightproof options
Loads a child window
Calculate a measurement
Calls the given function with the given parameter
Builds the saurus
Prints the usage of the program

Get all kandi verified functions for this library.

dictionaries Key Features

No Key Features are available at this moment for dictionaries.

dictionaries Examples and Code Snippets

title: Pluck values from list of dictionaries tags: list,dictionary expertise: beginner cover: blog_images/succulent-9.jpg firstSeen: 2020-10-22T03:49:25+03:00 lastUpdated: 2020-10-22T10:09:44+03:00

Python

Lines of Code : 9

License : No License

Copy

def pluck(lst, key):
  return [x.get(key) for x in lst]


simpsons = [
  { 'name': 'lisa', 'age': 8 },
  { 'name': 'homer', 'age': 36 },
  { 'name': 'marge', 'age': 34 },
  { 'name': 'bart', 'age': 10 }
]
pluck(simpsons, 'age') # [8, 36, 34, 10]

Merge two dictionaries .

python

Lines of Code : 30

License : Non-SPDX (Apache License 2.0)

Copy

def merge(self, x=None, y=None, ildj_map=None, kwargs=None, mapping=None):
    """Returns new _Mapping with args merged with self.

    Args:
      x: `Tensor`. Forward.
      y: `Tensor`. Inverse.
      ildj_map: `Dictionary`. This is a mapping from

Find the depth of nested dictionaries .

python

Lines of Code : 29

License : Non-SPDX (Apache License 2.0)

Copy

def _pyval_find_struct_keys_and_depth(pyval, keys):
  """Finds the keys & depth of nested dictionaries in `pyval`.

  Args:
    pyval: A nested structure of lists, tuples, and dictionaries.
    keys: (output parameter) A set, which will be update

Convert CSV file to list of dictionaries .

python

Lines of Code : 18

License : Non-SPDX (Apache License 2.0)

Copy

def _convert_decode_csv(pfor_input):
  lines = pfor_input.stacked_input(0)
  record_defaults = [
      pfor_input.unstacked_input(i) for i in range(1, pfor_input.num_inputs)
  ]
  field_delim = pfor_input.get_attr("field_delim")
  use_quote_delim = p

Community Discussions

Trending Discussions on dictionaries

How to remove empty or None fields in deeply nested dictionary of unknown depth?

GPO report missing data using XML

I have multiple dictionaries in one variable results. How to return only 1st dictionary value from that?

How to merge DataFrames, combining columns and creating new rows

How can I create column from dictionary keys in same dataframe?

Convert str type dicts with nan values to dict type objects

Adding to a nested Dictionary in a Column in Pandas

Fun Dictionary Manipulation in Pandas

can you give me a hand using list of dictionaries in Python

Sort a list of nested dictionaries by values without knowing its keys [Python]

QUESTION

How to remove empty or None fields in deeply nested dictionary of unknown depth?

Asked 2021-Jun-14 at 23:19

I have a dictionary of deeply nested dictionaries and I am trying to remove all k-v pairs that are None or "". The below dictionary d is an example of the input.

...

ANSWER

Answered 2021-Jan-28 at 20:48

You can use recursion with a dictionary comprehension:

Source https://stackoverflow.com/questions/65944618

QUESTION

GPO report missing data using XML

Asked 2021-Jun-14 at 23:19

I was looking for 'Network access: Allow anonymous SID/Name translation' in XML output and it isn't in the file but it exists in HTML version. Is there a work around?

...

ANSWER

Answered 2021-Jun-14 at 23:19

You'll find 'Network access: Allow anonymous SID/Name translation' named as LSAAnonymousNameLookup, so try

Source https://stackoverflow.com/questions/67977209

QUESTION

I have multiple dictionaries in one variable results. How to return only 1st dictionary value from that?

Asked 2021-Jun-14 at 17:27

I have multiple dictionaries in one variable results. How to return only 1st dictionary value from that?

...

ANSWER

Answered 2021-Jun-14 at 14:20

If you have a list or a tuple of dictionaries, you can use indexing:

Source https://stackoverflow.com/questions/67971908

QUESTION

How to merge DataFrames, combining columns and creating new rows

Asked 2021-Jun-14 at 14:51

I have a couple of arcs dataframes with a very similar structure to these:

Ah: i j 0 1 1 1 1 2 2 2 1 3 2 2 K: Ok Dk 0 3 4 1 1 2 2 2 1

I need to find a way to create a new dataframe that merges both, following this structure:

Route: Ok i j Dk 0 3 1 1 4 1 3 1 2 4 2 3 2 1 4 3 3 2 2 4 4 1 1 1 2 5 1 1 2 2 6 1 2 1 2 7 1 2 2 2 8 2 1 1 1 9 2 1 2 1 10 2 2 1 1 11 2 2 2 1

or this structure:

Route: i j k 0 1 1 0 1 1 2 0 2 2 1 0 3 2 2 0 4 1 1 1 5 1 2 1 6 2 1 1 7 2 2 1 8 1 1 2 9 1 2 2 10 2 1 2 11 2 2 2

Currently I have a piece of code that can do something similar to that but instead of a pandas dataframe (which is what I want to use) I'm using dictionaries (the reason behind that is that each "route" has different caracteristics that makes them unique from each other so a dictionary is useful and at the time I was just learning Python) but the issue is that it takes too much time and uses a lot of memory so I'm trying to find a way to make it a little bit quicker, avoiding 'for' loops and trying to apply Pandas to create the merged dataframe.

This is an extract of the structure of my current piece of code, for this example, consider the 'A' dataframe as the one that holds every combination possible of arcs so the 'if' condition makes sure that a connection exists before creating the route.

...

ANSWER

Answered 2021-Jun-14 at 14:22

I think you can use pandas Concat function to merge your dictionaries the way you want to. https://pandas.pydata.org/pandas-docs/stable/user_guide/merging.html

It's kind of hard to see how you want it to be laid out, but I think you want to use .merge

Source https://stackoverflow.com/questions/67971916

QUESTION

How can I create column from dictionary keys in same dataframe?

Asked 2021-Jun-14 at 10:09

I have a dataframe, something like:

...

ANSWER

Answered 2021-Jun-14 at 10:09

You can try the following:

Source https://stackoverflow.com/questions/67968277

QUESTION

Convert str type dicts with nan values to dict type objects

Asked 2021-Jun-13 at 19:08

Similar questions to this have been asked many times, but surprisingly few of the answers seem to address what I believe my problem to be.

I have csv files with one or more columns that contain a dictionary in each cell. After read_csv step, I have tried ast.literal_eval on these columns in order to convert the str format dicts into dict type objects. However, I keep getting the malformed node or string error.

Here is a typical example of the dicts in question: {1: 3681.45, 0: 3693.3333333333335}. And another, with a nan value: {1: 4959.95652173913, 0: nan}. Edit: It was only this nan value causing the error, in fact (see Rakesh's solution below).

Looking through previous answers, one reason for this error may be because most of the values of the dicts in these columns are floating point numbers, and apparently literal_eval can't handle floats or nans, even if they're contained within dictionaries (although, this is me inferring from a question about tuples).

I had to read a lot of questions and answers even to get this much information, so thought it could be useful to start a new topic with the keywords str, dict, but also nan in the title.

Any help much appreciated!

...

ANSWER

Answered 2021-Jun-13 at 17:41

Use eval on json that has nan

Ex:

Source https://stackoverflow.com/questions/67960581

QUESTION

Adding to a nested Dictionary in a Column in Pandas

Asked 2021-Jun-13 at 18:43

So, I have a fun issue. I have some data that have a fun nested dictionary that I need to manipulate, but am having trouble. I can do it in pure python, but wanted to do the entire solution in Pandas so as to keep the code a little cleaner and not have to re-open the same files elsewhere.

Dataframe:

...

ANSWER

Answered 2021-Jun-13 at 17:17

One way:

Create another list of dict via to_dict('records').
zip and iterate over both the list of dict.
Update the 1st one with the other to get the desired JSON.

Source https://stackoverflow.com/questions/67960396

QUESTION

Fun Dictionary Manipulation in Pandas

Asked 2021-Jun-13 at 18:14

This is perfect for what I need an no one seems to be answering it:

I have the following Dataframe:

...

ANSWER

Answered 2021-Jun-13 at 18:14

Have you tried the pd.to_dict() options? You can pass in different ways of presenting your data. orient=records or orient=index might help you. Docs are here https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.DataFrame.to_dict.html.

Source https://stackoverflow.com/questions/67961135

QUESTION

can you give me a hand using list of dictionaries in Python

Asked 2021-Jun-13 at 15:15

I want to store basketball player information, and the things I want to store are Player name and Player height. Also, I want to be able to iterate using loops through that list, so therefore I made a list of dictionaries to achieve that? I am not sure if everything is correct?

The code:

...

ANSWER

Answered 2021-Jun-13 at 15:15

check the code in your first for loop, you append data inconsistantly.

Source https://stackoverflow.com/questions/67949400

QUESTION

Sort a list of nested dictionaries by values without knowing its keys [Python]

Asked 2021-Jun-12 at 14:13

As the title says I'm trying to sort a list of nested dictionaries without knowing its keys.
If possible I'd like to use one of the 2 following functions to solve my problem:

I want it to be sorted by occurrences OR tf-idf (same shit)
I've currently tried both with lambdas but nothing worked.

Sample of my data:

...

ANSWER

Answered 2021-Jun-12 at 14:07

You can pass lambda to sorted function as key:

Source https://stackoverflow.com/questions/67949490

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install dictionaries

You can download it from GitHub.
You can use dictionaries like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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