bandmat | A banded matrix library for python | Math library

 by   MattShannon Python Version: 0.7 License: Non-SPDX

kandi X-RAY | bandmat Summary

kandi X-RAY | bandmat Summary

bandmat is a Python library typically used in Utilities, Math applications. bandmat has no bugs, it has no vulnerabilities, it has build file available and it has low support. However bandmat has a Non-SPDX License. You can install using 'pip install bandmat' or download it from GitHub, PyPI.

A banded matrix library for python.
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            kandi-support Support

              bandmat has a low active ecosystem.
              It has 24 star(s) with 11 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 3 open issues and 6 have been closed. On average issues are closed in 168 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of bandmat is 0.7

            kandi-Quality Quality

              bandmat has 0 bugs and 0 code smells.

            kandi-Security Security

              bandmat has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              bandmat code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              bandmat has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              bandmat releases are not available. You will need to build from source code and install.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.
              bandmat saves you 723 person hours of effort in developing the same functionality from scratch.
              It has 1670 lines of code, 99 functions and 12 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed bandmat and discovered the below as its top functions. This is intended to give you an instant insight into bandmat implemented functionality, and help decide if they suit your requirements.
            • Generate a simple example with random parameters
            • Build a polynomial polynomial
            • Build a list of windows from a list of windows
            Get all kandi verified functions for this library.

            bandmat Key Features

            No Key Features are available at this moment for bandmat.

            bandmat Examples and Code Snippets

            No Code Snippets are available at this moment for bandmat.

            Community Discussions

            QUESTION

            Get all Many:Many relationships from reference/join-table
            Asked 2020-May-07 at 11:13

            I am having difficulty querying for possible relationships in a Many:Many scenario.

            I present my schema:

            What I do know how to query with this schema is:

            • All Bands that a given User belongs to.
            • All Users that belong to a given Band.

            What I am trying to do is:

            • Get all Band Members across all Bands that a given User belongs to.
            • ie, say I am in 5 bands, I want to know who all of my bandmates are.

            My first questions are:

            • Is there a name for this type of query? Where I am more interested in the joined relationships than what I am joined to (just saying that made me want to put this whole system into a Graph DB :/ )? I'd like to learn proper terminology to help me google for problems down the road.
            • Is this a terrible idea in RDBMS land in general? I feel like this should be a common use case but I want to know if I'm totally approaching this wrong.

            To recap:

            • I am looking to query the above schema with the expected output being one row per User as Band Members that a given User shares a Band with.
            ...

            ANSWER

            Answered 2020-May-07 at 11:13
            Terminology

            Your terminology seems to be correct - "many to many", often written as "many:many" with a colon. Sometimes the middle table (band_members) is called the "bridge table".

            You can probably drop band_members.id, since the two foreign keys also make up a composite primary key (and the primary key can actually be defined that way, since normally a User cannot be a member of the same Band twice. The only exception to that is if a User could have more than one role in the same Band).

            Solution

            On the surface of it, this sounds easy - we can see the relationships of the tables, and one would normally just use an INNER JOIN between them. There are three tables, so that would be two joins.

            However, we have to conceptualise the problem correctly first. The problem we have is that the join between Users and Band Members (user ID) is actually to be used for two things:

            • which User is in what Band
            • filtering by User

            So to do this we need to introduce one table with multiple purposes:

            Source https://stackoverflow.com/questions/61623942

            QUESTION

            UIPageViewController Affecting UIImage color?
            Asked 2020-Feb-12 at 02:39

            What I'm Doing: I am creating a custom view controller for encouraging users to invite friends to the app in exchange for premium features. I am doing this via presenting a UIViewController that has a container view with a UIPageViewController embedded within the container view. The details of all of the premium features are displayed in the embedded UIPageViewController's view controllers. I have an image of some bubbles that match our brand colors that are on the leading or trailing edge of each of the UIPageViewController's view controllers such that the images "connect" into one image when panning between each view controller. This is what it looks like:

            My problem: The problem with this approach is that, when half way panned between two of the UIPageViewController's view controllers, the colors of the bubbles in between the respective view controllers do not match:

            Notice that the shades of blue where the images meet up between each respective view controller are not the same shade.

            This is despite using the same "bubbles" image for each view controller, which looks like this:

            UPDATE I've decided to go ahead and create a cocoapod that does the same thing presented in the question above. Feel free to check it out!

            ...

            ANSWER

            Answered 2020-Feb-05 at 03:54

            Since you only have a few pages to show, abandon UIPageViewController and configure the entire sliding interface as the content of one big continuous paged UIScrollView instead. As a bonus you won’t have to work out the splitting of the bubble image.

            Source https://stackoverflow.com/questions/60065778

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install bandmat

            You can install using 'pip install bandmat' or download it from GitHub, PyPI.
            You can use bandmat like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            Install
          • PyPI

            pip install bandmat

          • CLONE
          • HTTPS

            https://github.com/MattShannon/bandmat.git

          • CLI

            gh repo clone MattShannon/bandmat

          • sshUrl

            git@github.com:MattShannon/bandmat.git

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