Dijkstra | native Python implementation of famous Dijkstra | Learning library

 by   ahojukka5 Python Version: v0.2.1 License: MIT

kandi X-RAY | Dijkstra Summary

kandi X-RAY | Dijkstra Summary

Dijkstra is a Python library typically used in Tutorial, Learning, Example Codes applications. Dijkstra has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can download it from GitHub.

Package author: Jukka Aho (@ahojukka5, ahojukka5@gmail.com). dijkstra is a native Python implementation of famous Dijkstra's shortest path algorithm. The implemented algorithm can be used to analyze reasonably large networks. The primary goal in design is the clarity of the program code. Thus, program code tends to be more educational than effective. Project source code is licensed undet MIT license. The source code of the project is hosted on on GitHub: Releases of this package are hosted in PyPi, where they can be easily accessed using pip:

            kandi-support Support

              Dijkstra has a low active ecosystem.
              It has 11 star(s) with 2 fork(s). There are 2 watchers for this library.
              It had no major release in the last 12 months.
              There are 1 open issues and 1 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Dijkstra is v0.2.1

            kandi-Quality Quality

              Dijkstra has 0 bugs and 0 code smells.

            kandi-Security Security

              Dijkstra has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Dijkstra code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Dijkstra is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Dijkstra releases are available to install and integrate.
              Build file is available. You can build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              It has 183 lines of code, 21 functions and 6 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed Dijkstra and discovered the below as its top functions. This is intended to give you an instant insight into Dijkstra implemented functionality, and help decide if they suit your requirements.
            • Return the version string
            • Read the content of a file
            Get all kandi verified functions for this library.

            Dijkstra Key Features

            No Key Features are available at this moment for Dijkstra.

            Dijkstra Examples and Code Snippets

            No Code Snippets are available at this moment for Dijkstra.

            Community Discussions


            Using generators to make lazy streams in python
            Asked 2022-Mar-27 at 05:41

            I've been messing with streams in python and been trying to generate the Hamming numbers (all the numbers with prime factors of 2, 3, or 5 only). The standard way for doing so, described by Dijkstra, is to observe that:

            1. The sequence of Hamming numbers begins with 1.
            2. The remaining values in the sequence are of the form 2h, 3h, and 5h, where h is any Hamming number.
            3. h is be generated by outputting the value 1, and then merging together 2h, 3h, and 5h

            My implementation is this:



            Answered 2022-Mar-27 at 05:41

            The further you get out into your stream, the more duplicates you're going to have to be merging. The number 2**4 * 3 **4 = 1296 is going to appear 70 times in your multiple stream (8 choose 4), and your program is going to be spending more time merging duplicates than it is outputting new items.

            The further you go out, the more duplication you'r going to be dealing with. There is no reason to expect your program to be linear.

            Source https://stackoverflow.com/questions/71633932


            Using timeit to time algorithms without timing already sorted or setup
            Asked 2022-Mar-26 at 22:30

            I am trying to use timeit to time two algorithms I have implemented, but I need to construct a graph object and don't want to sort graphs that are already sorted (for time accuracy).

            This is the best attempt I have so far at separating the setup from the actual timing. Later I want to call ShortestPathAlgorithm() with no arguments and print the results in a table to a txt file, so I believe the format has to be something like this. With everything being completed inside the shortestPathAlgorithm Function.

            Can anyone give any pointers on how to do all of this in the nested functions?



            Answered 2022-Mar-26 at 19:33

            Your understanding is correct. However, there are some issues that could be improved.

            Firstly, you usually want to measure only one algorithm at a time. If you measure each algorithm separately you can compare the two and get more accurate data. Also, I would stick to measuring it on the same graph multiple times and then average the time to get one more accurate (you can use copy.deepcopy() to make duplicates of the graph). Then do this on each of the graphs you have. Since each algorithm may be more efficient on different types of graphs (you would lose this information completely if measured as you propose).

            Secondly, since timeit can repeat the measured operation multiple times but the setup is done only once before any measurement starts (see the docs) you would measure the algorithm on already traversed (or sorted as you put it) graphs. Which you correctly point out.

            As a solution, I suggest manually timing the runs using the time.perf_counter_ns(). The code for measuring the bellmanFord algorithm could look as such:

            Source https://stackoverflow.com/questions/71630480


            How to solve the dining philosophers problem with only mutexes?
            Asked 2022-Mar-22 at 06:59

            I wrote this program to solve the dining philosophers problem using Dijkstra's algorithm, notice that I'm using an array of booleans (data->locked) instead of an array of binary semaphores.

            I'm not sure if this solution is valid (hence the SO question).

            Will access to the data->locked array in both test and take_forks functions cause data races? if so is it even possible to solve this problem using Dijkstra's algorithm with only mutexes?

            I'm only allowed to use mutexes, no semaphores, no condition variables (it's an assignment).

            Example of usage:



            Answered 2022-Mar-22 at 06:59

            Your spin loop while (data->locked[i]); is a data race; you don't hold the lock while reading it data->locked[i], and so another thread could take the lock and write to that same variable while you are reading it. In fact, you rely on that happening. But this is undefined behavior.

            Immediate practical consequences are that the compiler can delete the test (since in the absence of a data race, data->locked[i] could not change between iterations), or delete the loop altogether (since it's now an infinite loop, and nontrivial infinite loops are UB). Of course other undesired outcomes are also possible.

            So you have to hold the mutex while testing the flag. If it's false, you should then hold the mutex until you set it true and do your other work; otherwise there is a race where another thread could get it first. If it's true, then drop the mutex, wait a little while, take it again, and retry.

            (How long is a "little while", and what work you choose to do in between, are probably things you should test. Depending on what kind of fairness algorithms your pthread implementation uses, you might run into situations where take_forks succeeds in retaking the lock even if put_forks is also waiting to lock it.)

            Of course, in a "real" program, you wouldn't do it this way in the first place; you'd use a condition variable.

            Source https://stackoverflow.com/questions/71552461


            Defining a recursive function inside another function in C
            Asked 2022-Mar-18 at 18:13

            I'm trying to write a recursive function (printPath) inside another function (dijkstraSSSP), but it gives me a compiler error.

            When I run gcc dijkstra.c WGraph.c PQueue.c, it compiles just fine. However, when I run dcc -Wall -Werror -std=c11 -o dijkstra dijkstra.c WGraph.c PQueue.c. I got this error:



            Answered 2022-Mar-18 at 17:10

            Move the definition of printPath outside of the body of dijkstraSSSP and, to give it access to pred, change it to accept two parameters instead of one. The additional parameter should have type int * and should point to the first element of pred.

            In the call, pass pred for that new parameter. The array pred will be automatically converted to a pointer to its first element.

            Source https://stackoverflow.com/questions/71530625


            Why can Dijkstra's Algorithm be modified to find K shortest paths?
            Asked 2022-Feb-17 at 19:54

            I am trying to find an intuitive explanation as to why we can generalize Dijkstra's Algorithm to find the K shortest (simple) paths from a single source in a directed, weighted graph with no negative edges. According to Wikipedia, the pseudocode for the modified Dijkstra is as follows:



            Answered 2022-Feb-17 at 19:54

            The Wiki article doesn't specify, but that code will only solve the 'loopy' version of k-shortest-paths, where paths are not required to be simple.

            The simple path version of the problem is harder: you'll want to look at something like Yen's algorithm, which does clever filtering to avoid repeated points when generating paths. Yen's algorithm can use Dijkstra's algorithm as a subroutine, but any other shortest-path algorithm can also be used instead.

            There is no obvious way to modify Dijkstra's algorithm to solve the k-shortest-simple-paths problem. You'd need to track the paths in the priority queue (which is already done in your posted code), but there's an exponential upper bound on the number of times each vertex can be explored.

            Here, if count[u] <= K puts an upper bound of K+1 on the number of times a vertex can be explored, which works for the non-simple path case. On the other hand, a direct modification of Dijkstra's algorithm for simple paths would, in the worst case, require you to explore a node once for each of the 2^(V-1) possibilities of which nodes had been previously visited (or possibly a slightly smaller exponential).

            Source https://stackoverflow.com/questions/71140260


            How to fix an error associating with a comparator?
            Asked 2022-Feb-03 at 21:36

            The code is compiled, and run without any issue in CLion IDE with g++ compiler in MinGW, however, the same exact code has a compilation error in Visual Studio IDE and with (MSVC compiler)

            I believe the error should have to do with the follwoing comparator class:



            Answered 2022-Feb-03 at 21:36

            Your somewhat odd comparator...

            Source https://stackoverflow.com/questions/70978400


            Shortest Path with Dijkstra’s Algorithm from a dataframe
            Asked 2022-Feb-01 at 19:36

            I am trying to find shortest path between graph nodes using Dijkstra's Algorithm, by using the code enclosed in the following article:


            But this code creates the graph from an edgelist. Instead I would like to create the graph from a dataframe like this:



            Answered 2022-Feb-01 at 19:15

            Perhaps you can try this

            Source https://stackoverflow.com/questions/70942564


            Time complexity for Dijkstra's algorithm with min heap and optimizations
            Asked 2022-Jan-04 at 00:18

            What is the time complexity of this particular implementation of Dijkstra's algorithm?

            I know several answers to this question say O(E log V) when you use a min heap, and so does this article and this article. However, the article here says O(V+ElogE) and it has similar (but not exactly the same) logic as the code below.

            Different implementations of the algorithm can change the time complexity. I'm trying to analyze the complexity of the implementation below, but the optimizations like checking visitedSet and ignoring repeated vertices in minHeap is making me doubt myself.

            Here is the pseudo code:



            Answered 2021-Dec-22 at 00:38
            1. Despite the test, this implementation of Dijkstra may put Ω(E) items in the priority queue. This will cost Ω(E log E) with every comparison-based priority queue.

            2. Why not E log V? Well, assuming a connected, simple, nontrivial graph, we have Θ(E log V) = Θ(E log E) since log (V−1) ≤ log E < log V² = 2 log V.

            3. The O(E + V log V)-time implementations of Dijkstra's algorithm depend on a(n amortized) constant-time DecreaseKey operation, avoiding multiple entries for an individual vertex. The implementation in this question will likely be faster in practice on sparse graphs, however.

            Source https://stackoverflow.com/questions/70431085


            Dijkstra algorithm to select randomly an adjacent node with same minimum weight
            Asked 2021-Dec-22 at 20:46

            I have implemented Dijkstra's algorithm but I have a problem. It always prints the same minimum path while there may be other paths with the same weight.

            How could I change my algorithm so that it randomly selects the neighbors with the same weight?

            My algorithm is below:



            Answered 2021-Dec-22 at 20:36

            probably just try something like this

            Source https://stackoverflow.com/questions/70454750


            Can I use Breadth-First-Search on weighted graphs if I modify it?
            Asked 2021-Dec-10 at 08:20

            I am having a discussion with a friend if the following will work:

            We recently learned in a lecture about Breadth-First-Search. I know that it is a special case of Dijkstra where each edge weight is set to one. Assume now we are given a graph where the edges have integer weights of more than one. Then I would modify this graph by introducing additional vertices and connecting them by edges with weight one, e.g. assume we have an edge of weight 3 connecting the vertices u and v, then I would introduce dummy-vertices d1, d2, remove the edge connecting u and v and instead add edges {u, d1}, {d1, d2}, {d2,v} of weight one.

            If I modify my whole graph this way and then apply breadth-first search starting from one of the original vertices, wouldn't this work as well?

            Thank you very much in advance!



            Answered 2021-Dec-10 at 08:20

            Since BFS is guaranteed to return an optimal path on unweighted graphs, and you've created the unweighted equivalent of your original graph, you'll be guaranteed to get the shortest path.

            What you lose by doing this over Dijkstra's algorithm is runtime optimality. Now the runtime of your algorithm is dependent on the edge weights, whereas Dijkstra's is only dependent on the number of edges.

            This sort of thought experiment is a great way to understand how Dijkstra's algorithm works (eg. how would you modify your algorithm to not require creating a new graph? Or not take 100 steps for an edge with weight 100?). In fact this is probably how Dijkstra discovered the algorithm to begin with.

            Source https://stackoverflow.com/questions/70291888

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network


            No vulnerabilities reported

            Install Dijkstra

            You can download it from GitHub.
            You can use Dijkstra like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.


            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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