Competitive_Programming | Questions solved from Various Coding websites | Learning library

by anantkaushik Python Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | Competitive_Programming Summary

Competitive_Programming is a Python library typically used in Tutorial, Learning applications. Competitive_Programming has no bugs, it has no vulnerabilities and it has low support. However Competitive_Programming build file is not available. You can download it from GitHub.

Questions solved from Various Coding websites viz. HackerRank, HackerEarth, CodeChef and other websites. This repository also contains Questions from various offline and onsite competitions.

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Competitive_Programming has a low active ecosystem.

It has 245 star(s) with 87 fork(s). There are 8 watchers for this library.

It had no major release in the last 6 months.

There are 1 open issues and 1 have been closed. On average issues are closed in 35 days. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of Competitive_Programming is current.

Quality

Competitive_Programming has 0 bugs and 0 code smells.

Security

Competitive_Programming has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

Competitive_Programming code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

Competitive_Programming does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

Competitive_Programming releases are not available. You will need to build from source code and install.

Competitive_Programming has no build file. You will be need to create the build yourself to build the component from source.

Competitive_Programming saves you 2191 person hours of effort in developing the same functionality from scratch.

It has 4797 lines of code, 300 functions and 323 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed Competitive_Programming and discovered the below as its top functions. This is intended to give you an instant insight into Competitive_Programming implemented functionality, and help decide if they suit your requirements.

Returns the cuts of a given string
Return True if x is a power of y
This function is used to help the heuristic
Checks if a given row is valid
Return the first sibling of a node
Return the leftmost child of a node
Merge two nodes
Merge two lists
Return a sequence of x
Greatest common divisor
Rotate a list
Returns the number of elements in the head
Check if two arrays are equal
Calculate the score
Check if a b is a rotation
Greatest common divider
Return the nth value of the last nth node
Build a tree from a string
Return the number of stars in the tribe
Count the number of nodes in a loop
Return the minimum element of arr
Solve the problem
Find the length of a substring in s
Find the distance between a and b
Add two nodes
Generate Fibonacci series
Find the nearest stars in a planet

Get all kandi verified functions for this library.

Competitive_Programming Key Features

No Key Features are available at this moment for Competitive_Programming.

Competitive_Programming Examples and Code Snippets

No Code Snippets are available at this moment for Competitive_Programming.

Community Discussions

Trending Discussions on Competitive_Programming

From a given set of straight lines, how to find the points, lying on any line, having minimum y co-ordinate at a particular x?

QUESTION

From a given set of straight lines, how to find the points, lying on any line, having minimum y co-ordinate at a particular x?

Asked 2018-Jun-04 at 19:39

A naive solution would be to iterate over each straight line equation (~1e5 of them), substitute the 'x' with the given value, obtain 'y', and compare this 'y' with the 'y's obtained from the other straight line equations. This solution however, fails to complete within the Time Limit if number of queries is large (~1e5). Is there any efficient way to find the minimum 'y' for a particular 'x'?

The JAVA code, which fails:

...

ANSWER

Answered 2018-Jun-04 at 19:39

The locus of the lowest y for any x is a convex polyline with at most N-1 vertices.

You can construct it incrementally by adding one line at a time. The update of the polyline isn't very difficult when done the naive way: for every segment, check if it crosses the new line, and only keep the portions "below". Make sure to keep the left-to-right ordering of the vertices.

I suspect that this operation can be done more efficiently by dichotomic-like processes, but that requires more sophisticated data structures.

When you have obtained the final polyline, it takes a simple dichotomic search to find the y for a given x.

Source https://stackoverflow.com/questions/50685361

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install Competitive_Programming

You can download it from GitHub.
You can use Competitive_Programming like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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