oop-python | Object-Oriented Programming in Python
kandi X-RAY | oop-python Summary
kandi X-RAY | oop-python Summary
Object-Oriented Programming in Python
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Run game
- End game
- Checks if the target score is above the target score
- Start a game
- Loop over all players
- Run a game
- Returns whether the game has been played
- Roll the score
- Roll a random integer
- Calculates profit price
- Update the price of a ride
- Updates the cost
- Updates the sale price
- Update the price of a ride
- Get a default cyclist
- Calculates sell price
- Create a ride
- Return the age of a given year
- Square number
oop-python Key Features
oop-python Examples and Code Snippets
Community Discussions
Trending Discussions on oop-python
QUESTION
Problem: I have 50 text files, each with thousands of lines of text, each line has a value on it. I am only interesting in a small section near the middle (lines 757-827 - it is actually lines 745-805 I'm interested in, but the first 12 lines of every file is irrelevant stuff). I would like to read each file in. And then total the values between those lines. In the end I would like it to print off a pair of numbers in the format (((n+1)*18),total count), where n is the number of the file (since they are numbered starting at zero). Then repeat for all 50 files, giving 50 pairs of numbers, looking something like:
(18,77),(36,63),(54,50),(72,42),...
Code:
...ANSWER
Answered 2021-Mar-31 at 14:55Solution was to edit code as shown starting from 'xmin = 745':
QUESTION
I have some pictures in the folder I want to pair so I can add them to my slide with iterative fashion. I want to pair pictures ending with mp
ones to bp
ones. One caveat is that there are multiple pictures ending with bp
and bp
so that adding logical check would be feasible.
lets say we have a pictures in the folder
I want to pair 1_birds_bp.png
to other pictures starting with 1
and ending with mp
so that the pair should look like #expected result
...ANSWER
Answered 2020-Feb-20 at 00:23You can check all combinations and pick the ones that match:
QUESTION
So far I mostly used Python for data analysis but for some time try to implement stuff. Right now I'm trying to implement a toxicokinetic-toxicodynamic model for a fish to analyse the effect of chemicals on them.
So given the following code:
...ANSWER
Answered 2020-Jan-10 at 16:16You can create a class FishPopulation
and then store there all the Fish
you need based on the size argument. For example, something like this would work:
QUESTION
Similar to this and many other questions, I have many nested loops (up to 16) of the same structure.
Problem: I have 4-letter alphabet and want to get all possible words of length 16. I need to filter those words. These are DNA sequences (hence 4 letter: ATGC), filtering rules are quite simple:
- no XXXX substrings (i.e. can't have same letter in a row more than 3 times, ATGCATGGGGCTA is "bad")
- specific GC content, that is number of Gs + number of Cs should be in specific range (40-50%). ATATATATATATA and GCGCGCGCGCGC are bad words
itertools.product
will work for that, but data structure here gonna be giant (4^16 = 4*10^9 words)
More importantly, if I do use product
, then I still have to go through each element to filter it out. Thus I will have 4 billion steps times 2
My current solution is nested for
loops
ANSWER
Answered 2018-May-25 at 12:28Since you happen to have an alphabet of length 4 (or any "power of 2 integer"), the idea of using and integer ID and bit-wise operations comes to mind instead of checking for consecutive characters in strings. We can assign an integer value to each of the characters in alphabet
, for simplicity lets use the index corresponding to each letter.
Example:
65463543
10 = 3321232103313
4 = 'aaaddcbcdcbaddbd'
The following function converts from a base 10 integer to a word using alphabet
.
QUESTION
this question is based on this other one: Nested Loop Python
One of the answer is
...ANSWER
Answered 2018-Mar-09 at 21:54It is only run after the nested loop. Looking at the output from the post you referenced, the program starts with 1, prints one 1 without a newline, then exits the nested loop, then prints the newline. Then it enters the nested loop with 2, loops twice (prints a 2 without a newline, then prints a second two without a newline), then exits the loop and prints a newline.
QUESTION
I am very new to python and learning my way up. My task is to crawl data from web and filing xlsx data using json and pandas (and etc..). I am researching through some examples of modifing json dic to pandas DataFrame, and I cant seem to find the one that I need.
Im gussing this would be very basic, but help me out.
so below is my code
...ANSWER
Answered 2017-Nov-27 at 08:36Assuming your structure is consistent, use a list comprehension and then concatenate -
QUESTION
I use Python in Emacs, with Elpy and iPython. I run code from a file with C-c C-c, but sometimes I would like to terminate the process (keyboard interrupt). I use the same shortcut to try to terminate the process (as per this question).
My goal would be to try to distinguish between killing the whole Python process or just interrupting the kernel. With the above shortcut, it sometimes does the first and sometimes does the second. I am yet to find any clues, how to generalize it.
So, the question is: How to stop the Python process and how to interrupt the kernel?
...ANSWER
Answered 2017-Nov-21 at 23:28I would just define a function to send an interrupt to the process. I use anaconda-mode
not elpy
, so I am not sure what elpy
uses to get the associated process-buffer
, but python-mode
has python-shell-get-process-or-error
. Then you could bind the key C-c C-a, for example, in the python-mode-map
to the following function.
QUESTION
According to this post, I need to use .copy()
on a dictionary, if I want to reference a dictionary which gets updated in a loop (instead of always referencing the same dictionary). However, in my code example below this doesn't seem to work:
main.py
:
ANSWER
Answered 2017-Sep-20 at 13:11dict.copy
only makes a shallow copy of the dict, the nested dictionaries are never copied, you need deep copies to have those copied over too.
However, you can simply define each new dict at each iteration of the loop and append the new dict at that iteration instead:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install oop-python
Install, open, and use the default settings.
If you're viewing this on GitHub already, stay on this page. Otherwise, go to the GitHub repository: https://github.com/ariannedee/oop-python.
Click the "Clone or download" (green) button at the top-right of the page
Click "Download ZIP"
Unzip it and move the oop-python-master folder to a convenient location
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page