amy | A web-based workshop administration application | Learning library
kandi X-RAY | amy Summary
kandi X-RAY | amy Summary
AMY is a web-based workshop administration application for The Carpentries and related projects. Its target audience is workshop coordinators, most of whom are non-programmers, who need to keep track of what workshops are being arranged, when they're supposed to occur, who's teaching what, and so on.
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Top functions reviewed by kandi - BETA
- View for a person
- Merge two objects
- Add jobs to the scheduler
- Check the status of a job
- Get all TrainingRequests
- Deletes the object
- Bulk add_person_add_people
- Create a list of uploaded persons
- Creates a list of terms that are used in the carpentries
- Return the comment model
- Preview a job
- Add the workshops
- Extend the current Curriculum
- Displays a list of Workshop issues
- Return the details for a given event
- View to merge events
- Process training requests
- Returns an email template
- Returns a CSV of the Workshop staff
- Add the descriptions for the curricula
- Initialize the GitHub
- Gets the form of the Werkzeug
- Update the expiry end date
- Migrate notes
- Displays all trainees
- Bulk upload training
amy Key Features
amy Examples and Code Snippets
Community Discussions
Trending Discussions on amy
QUESTION
I have a table which has 2 columns, named "Name" and "Score", demonstrates the academic result of a class.
"Name": Andy, Amy, Chloe, John, etc.
"Score": From 0 to 100
Some of the students had submitted all the tests but some have not done yet due to pandemic, in other words, there's some student only got only 1 result. Now I need to figure out what is the second-highest score that each of them has made.
If the students only submitted once, means that they don't have the second-highest score so we will return null for the score.
I tried
...ANSWER
Answered 2021-Jun-10 at 10:18Use ROW_NUMBER()
window function to rank the scores for each student and then get the 2nd highest score with conditional aggregation:
QUESTION
I'm trying to find admin activity within the last 30 days.
The accounts table stores the user data (username, password, etc.)
At the end of each day, if a user had logged in, it will create a new entry in the player_history table with their updated data. This is so we can track progress over time.
accounts table:
id username admin 1 Michael 4 2 Steve 3 3 Louise 3 4 Joe 0 5 Amy 1player_history table:
id user_id created_at playtime 0 1 2021-04-03 10 1 2 2021-04-04 10 2 3 2021-04-05 15 3 4 2021-04-10 20 4 5 2021-04-11 20 5 1 2021-05-12 40 6 2 2021-05-13 55 7 3 2021-05-17 65 8 4 2021-05-19 75 9 5 2021-05-23 30 10 1 2021-06-01 60 11 2 2021-06-02 65 12 3 2021-06-02 67 13 4 2021-06-03 90The following query
SELECT a.`username`, SEC_TO_TIME((MAX(h.`playtime`) - MIN(h.`playtime`))*60) as 'time' FROM `player_history` h, `accounts` a WHERE h.`created_at` > '2021-05-06' AND h.`user_id` = a.`id` AND a.`admin` > 0 GROUP BY h.`user_id`
Outputs this table:
Note that this is just admin activity, so Joe is not included in this data.
from 2021-05-06 to present (yy-mm-dd):
username time Michael 00:20:00 Steve 00:10:00 Louise 00:02:00 Amy 00:00:00As you can see this from data, Amy's time is shown as 0 although she has played for 10 minutes in the last month. This is because she only has 1 entry starting from 2021-05-06 so there is no data to compare to. It is 0 because 10-10 = 0.
Another flaw is that it doesn't include all activity in the last month, basically only subtracts the highest value from the lowest.
So I tried fixing this by comparing the highest value after 2021-05-06 to their most previous login before the date. So I modified the query a bit:
SELECT a.`Username`, SEC_TO_TIME((MAX(h.`playtime`) - (SELECT MAX(`playtime`) FROM `player_history` WHERE a.`id` = `user_id` AND `created_at` < '2021-05-06'))*60) as 'Time' FROM `player_history` h, `accounts` a WHERE h.`created_at` >= '2021-05-06' AND h.`user_id` = a.`id` AND a.`admin` > 0 GROUP BY h.`user_id`
So now it will output:
username time Michael 00:50:00 Steve 00:50:00 Louise 00:52:00 Amy 00:10:00But I feel like this whole query is quite inefficient. Is there a better way to do this?
...ANSWER
Answered 2021-Jun-05 at 23:14I think you want lag()
:
QUESTION
ANSWER
Answered 2021-Jun-03 at 13:51You can use Set which can be used to test if the object with value already exists or not. It will only call the function only once.
QUESTION
I want to know how i can uniquely print out the elements of each list inside the dictionary without printing duplicates. Sorry i am quite new to programming. I am reading Python Crash Course 2nd edition and want to add a little bit of a challenge to my code.
...ANSWER
Answered 2021-Jun-02 at 12:27You can combine the lists in favorite_languages.values() by adding them to a blank list, and taking the set at the end:
QUESTION
I am trying to display images fetched from backend and I am able to display all the data except the images,
Below is the response which I got when I console.log the response,
...ANSWER
Answered 2021-May-29 at 08:06You cannot access files that are out of you project baseUrl
. baseUrl
is determined by package.json
, so in most cases it's (unless you will change it, but you cannot level up from there anyway) /src
. You should move your images somewhere in src
, e.g. project/client/src/upload/images
.
Additionally, looks like this path uploads\\employee.png
has incorrect separator, it should be more like this \/
instead of \\
. Anyway you can easy replace it by profile.replace(/\\/, '\/')
.
QUESTION
Following are the files I have
- Python wrapper
- A simple terraform main.tf to spin up a ec2 instance
- A variables.tfvars file
PYTHON WRAPPER
...ANSWER
Answered 2021-May-20 at 00:22Your variables.tfvars
should be called variables.tf
. Also you can't declar variable "tags"
which depends on other variables. Instead you should create a local
in main.tf
:
QUESTION
I have a df
consisting of two different frames for each observation, denoted by the ending character in the variable
ANSWER
Answered 2021-May-19 at 01:36The answer in the linked question mentions that in order to change the data of a scatter plot you do
QUESTION
I am bit confused If any memory related issue happen when I declare classes like below by using Swift
programming language, The main purpose is to reduce real-time compile process. Because my system goes very slow If I declare class globally that is using in only one class.
ANSWER
Answered 2021-May-16 at 06:14I believe what you're looking for is to create a subclass which would inherit all the properties of your main class.
From my understanding it should look like this below:
QUESTION
Hy guys, I have a sqlite database named signup.db and a signup table in it and I have a php code of a signup page but it us not inserting any data on submit I also am not getting Amy error even on clicking on submit *don't mind SQL injection this is just testing I will use SQL prepared statement when I make my next project Code
...ANSWER
Answered 2021-May-15 at 16:00Your code has two issues:
- You should query on a db connection
$db->exec($sql);
- In $sql string
$pass should be $password
QUESTION
So, I have a dataset that looks like this:
R_fighter B_fighter Winner John Smith Bob Down Bob Down Oliver Black Harry Long Oliver Black Amy Kurev Maria Brooke Maria BrookeI want to add a column that adds a factor variable of Red
or Blue
called "Winner_Colour"
.
I'm looking for a way for the code to look at the first letter of column 1
and 2
, then look at Winner
and create a new column "Winner_Colour"
that has Red
if the winner belongs to R_fighter
or Blue
if the winner belongs to B_fighter
I have a feeling it might involve an if-statement
and a ```mutate()`` function but I don't know where to start.
ANSWER
Answered 2021-May-12 at 06:34You can use an ifelse
:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install amy
Clone the repository: $ git clone https://github.com/carpentries/amy.git $ cd amy
Configure git to automatically ignore revisions in the .git-blame-ignore-revs: $ git config blame.ignoreRevsFile .git-blame-ignore-revs
Install Pipenv: $ python -m pip install --user pipenv
Install Python dependencies: $ pipenv sync --dev Note: Pipenv will create a new virtual environment for this installation, so you don't have to create one yourself. The --dev flag installs development dependencies, required e.g. for testing.
Install yarn, the tool that manages AMY's JavaScript and CSS dependencies. You can install it here.
Start running a local instance of Postgres and Redis. This requires Docker to be installed locally. Redis is required to have certain features (like creating a new person and viewing a workshop request) work correctly. $ docker compose -f docker/docker-compose.yml -p amy up -d database redis
Set up your local database with fake (development-ready) data. This will create a superuser with "admin" as both the username and password. $ pipenv run make dev_database
Create cache tables for use with the database cache backend. $ pipenv run python manage.py createcachetable
Start a local Django development server by running: $ pipenv run make serve Note: this also installs front-end dependencies for AMY, including jQuery and Bootstrap (full list here).
Open http://127.0.0.1:8000/workshops/ in your browser and start clicking. Use the default "admin" as username and password.
Shut down the local server by typing Ctrl-C. Shut down the Docker Redis instance with: $ docker compose -f docker/docker-compose.yml -p amy down
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