amy | A web-based workshop administration application | Learning library

 by   carpentries Python Version: v4.1.2 License: MIT

kandi X-RAY | amy Summary

kandi X-RAY | amy Summary

amy is a Python library typically used in Tutorial, Learning applications. amy has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However amy build file is not available. You can download it from GitHub.

AMY is a web-based workshop administration application for The Carpentries and related projects. Its target audience is workshop coordinators, most of whom are non-programmers, who need to keep track of what workshops are being arranged, when they're supposed to occur, who's teaching what, and so on.
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              amy has a low active ecosystem.
              It has 100 star(s) with 72 fork(s). There are 58 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 107 open issues and 1128 have been closed. On average issues are closed in 328 days. There are 4 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of amy is v4.1.2

            kandi-Quality Quality

              amy has no bugs reported.

            kandi-Security Security

              amy has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              amy is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              amy releases are not available. You will need to build from source code and install.
              amy has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions, examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed amy and discovered the below as its top functions. This is intended to give you an instant insight into amy implemented functionality, and help decide if they suit your requirements.
            • View for a person
            • Merge two objects
            • Add jobs to the scheduler
            • Check the status of a job
            • Get all TrainingRequests
            • Deletes the object
            • Bulk add_person_add_people
            • Create a list of uploaded persons
            • Creates a list of terms that are used in the carpentries
            • Return the comment model
            • Preview a job
            • Add the workshops
            • Extend the current Curriculum
            • Displays a list of Workshop issues
            • Return the details for a given event
            • View to merge events
            • Process training requests
            • Returns an email template
            • Returns a CSV of the Workshop staff
            • Add the descriptions for the curricula
            • Initialize the GitHub
            • Gets the form of the Werkzeug
            • Update the expiry end date
            • Migrate notes
            • Displays all trainees
            • Bulk upload training
            Get all kandi verified functions for this library.

            amy Key Features

            No Key Features are available at this moment for amy.

            amy Examples and Code Snippets

            No Code Snippets are available at this moment for amy.

            Community Discussions

            QUESTION

            Query the second highest value of a name, if there's only one value return null
            Asked 2021-Jun-10 at 10:18

            I have a table which has 2 columns, named "Name" and "Score", demonstrates the academic result of a class.

            "Name": Andy, Amy, Chloe, John, etc.

            "Score": From 0 to 100

            Some of the students had submitted all the tests but some have not done yet due to pandemic, in other words, there's some student only got only 1 result. Now I need to figure out what is the second-highest score that each of them has made.

            If the students only submitted once, means that they don't have the second-highest score so we will return null for the score.

            I tried

            ...

            ANSWER

            Answered 2021-Jun-10 at 10:18

            Use ROW_NUMBER() window function to rank the scores for each student and then get the 2nd highest score with conditional aggregation:

            Source https://stackoverflow.com/questions/67918515

            QUESTION

            SQL subquery in SELECT clause
            Asked 2021-Jun-05 at 23:14

            I'm trying to find admin activity within the last 30 days.

            The accounts table stores the user data (username, password, etc.)

            At the end of each day, if a user had logged in, it will create a new entry in the player_history table with their updated data. This is so we can track progress over time.

            accounts table:

            id username admin 1 Michael 4 2 Steve 3 3 Louise 3 4 Joe 0 5 Amy 1

            player_history table:

            id user_id created_at playtime 0 1 2021-04-03 10 1 2 2021-04-04 10 2 3 2021-04-05 15 3 4 2021-04-10 20 4 5 2021-04-11 20 5 1 2021-05-12 40 6 2 2021-05-13 55 7 3 2021-05-17 65 8 4 2021-05-19 75 9 5 2021-05-23 30 10 1 2021-06-01 60 11 2 2021-06-02 65 12 3 2021-06-02 67 13 4 2021-06-03 90

            The following query

            SELECT a.`username`, SEC_TO_TIME((MAX(h.`playtime`) - MIN(h.`playtime`))*60) as 'time' FROM `player_history` h, `accounts` a WHERE h.`created_at` > '2021-05-06' AND h.`user_id` = a.`id` AND a.`admin` > 0 GROUP BY h.`user_id`

            Outputs this table:

            Note that this is just admin activity, so Joe is not included in this data.

            from 2021-05-06 to present (yy-mm-dd):

            username time Michael 00:20:00 Steve 00:10:00 Louise 00:02:00 Amy 00:00:00

            As you can see this from data, Amy's time is shown as 0 although she has played for 10 minutes in the last month. This is because she only has 1 entry starting from 2021-05-06 so there is no data to compare to. It is 0 because 10-10 = 0.

            Another flaw is that it doesn't include all activity in the last month, basically only subtracts the highest value from the lowest.

            So I tried fixing this by comparing the highest value after 2021-05-06 to their most previous login before the date. So I modified the query a bit:

            SELECT a.`Username`, SEC_TO_TIME((MAX(h.`playtime`) - (SELECT MAX(`playtime`) FROM `player_history` WHERE a.`id` = `user_id` AND `created_at` < '2021-05-06'))*60) as 'Time' FROM `player_history` h, `accounts` a WHERE h.`created_at` >= '2021-05-06' AND h.`user_id` = a.`id` AND a.`admin` > 0 GROUP BY h.`user_id`

            So now it will output:

            username time Michael 00:50:00 Steve 00:50:00 Louise 00:52:00 Amy 00:10:00

            But I feel like this whole query is quite inefficient. Is there a better way to do this?

            ...

            ANSWER

            Answered 2021-Jun-05 at 23:14

            I think you want lag():

            Source https://stackoverflow.com/questions/67854250

            QUESTION

            run function with uniquie value using javascript / node js
            Asked 2021-Jun-03 at 13:51

            ...

            ANSWER

            Answered 2021-Jun-03 at 13:51

            You can use Set which can be used to test if the object with value already exists or not. It will only call the function only once.

            Source https://stackoverflow.com/questions/67821312

            QUESTION

            How do i uniquely print out the elements of a list inside a dictionary
            Asked 2021-Jun-02 at 12:27

            I want to know how i can uniquely print out the elements of each list inside the dictionary without printing duplicates. Sorry i am quite new to programming. I am reading Python Crash Course 2nd edition and want to add a little bit of a challenge to my code.

            ...

            ANSWER

            Answered 2021-Jun-02 at 12:27

            You can combine the lists in favorite_languages.values() by adding them to a blank list, and taking the set at the end:

            Source https://stackoverflow.com/questions/67805045

            QUESTION

            cannot display images fetched from backend in Reactjs
            Asked 2021-May-29 at 09:29

            I am trying to display images fetched from backend and I am able to display all the data except the images,

            Below is the response which I got when I console.log the response,

            ...

            ANSWER

            Answered 2021-May-29 at 08:06

            You cannot access files that are out of you project baseUrl. baseUrl is determined by package.json, so in most cases it's (unless you will change it, but you cannot level up from there anyway) /src. You should move your images somewhere in src, e.g. project/client/src/upload/images.

            Additionally, looks like this path uploads\\employee.png has incorrect separator, it should be more like this \/ instead of \\. Anyway you can easy replace it by profile.replace(/\\/, '\/').

            Source https://stackoverflow.com/questions/67749041

            QUESTION

            Cannot replace values in variables.tfvars file with input variables through a python wrapper using module python_terraform
            Asked 2021-May-20 at 00:22

            Following are the files I have

            1. Python wrapper
            2. A simple terraform main.tf to spin up a ec2 instance
            3. A variables.tfvars file

            PYTHON WRAPPER

            ...

            ANSWER

            Answered 2021-May-20 at 00:22

            Your variables.tfvars should be called variables.tf. Also you can't declar variable "tags" which depends on other variables. Instead you should create a local in main.tf:

            Source https://stackoverflow.com/questions/67610454

            QUESTION

            Animate a matplotlib scatterplot with two frames
            Asked 2021-May-19 at 01:36

            I have a df consisting of two different frames for each observation, denoted by the ending character in the variable

            ...

            ANSWER

            Answered 2021-May-19 at 01:36

            The answer in the linked question mentions that in order to change the data of a scatter plot you do

            Source https://stackoverflow.com/questions/67595260

            QUESTION

            Any problem when I declare a class inside another class?
            Asked 2021-May-17 at 02:36

            I am bit confused If any memory related issue happen when I declare classes like below by using Swift programming language, The main purpose is to reduce real-time compile process. Because my system goes very slow If I declare class globally that is using in only one class.

            ...

            ANSWER

            Answered 2021-May-16 at 06:14

            I believe what you're looking for is to create a subclass which would inherit all the properties of your main class.

            From my understanding it should look like this below:

            Source https://stackoverflow.com/questions/67551432

            QUESTION

            Data not inserting in sqlite3 database using php
            Asked 2021-May-16 at 00:44

            Hy guys, I have a sqlite database named signup.db and a signup table in it and I have a php code of a signup page but it us not inserting any data on submit I also am not getting Amy error even on clicking on submit *don't mind SQL injection this is just testing I will use SQL prepared statement when I make my next project Code

            ...

            ANSWER

            Answered 2021-May-15 at 16:00

            Your code has two issues:

            1. You should query on a db connection

            $db->exec($sql);

            1. In $sql string

            $pass should be $password

            Source https://stackoverflow.com/questions/67547896

            QUESTION

            Using a string of characters in front of a variable name to inform information in a new column
            Asked 2021-May-12 at 18:57

            So, I have a dataset that looks like this:

            R_fighter B_fighter Winner John Smith Bob Down Bob Down Oliver Black Harry Long Oliver Black Amy Kurev Maria Brooke Maria Brooke

            I want to add a column that adds a factor variable of Red or Blue called "Winner_Colour".

            I'm looking for a way for the code to look at the first letter of column 1 and 2, then look at Winner and create a new column "Winner_Colour" that has Red if the winner belongs to R_fighter or Blue if the winner belongs to B_fighter I have a feeling it might involve an if-statement and a ```mutate()`` function but I don't know where to start.

            ...

            ANSWER

            Answered 2021-May-12 at 06:34

            You can use an ifelse :

            Source https://stackoverflow.com/questions/67498397

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install amy

            Configure git to automatically ignore revisions in the .git-blame-ignore-revs:. Note: Pipenv will create a new virtual environment for this installation, so you don't have to create one yourself. The --dev flag installs development dependencies, required e.g. for testing.
            Clone the repository: $ git clone https://github.com/carpentries/amy.git $ cd amy
            Configure git to automatically ignore revisions in the .git-blame-ignore-revs: $ git config blame.ignoreRevsFile .git-blame-ignore-revs
            Install Pipenv: $ python -m pip install --user pipenv
            Install Python dependencies: $ pipenv sync --dev Note: Pipenv will create a new virtual environment for this installation, so you don't have to create one yourself. The --dev flag installs development dependencies, required e.g. for testing.
            Install yarn, the tool that manages AMY's JavaScript and CSS dependencies. You can install it here.
            Start running a local instance of Postgres and Redis. This requires Docker to be installed locally. Redis is required to have certain features (like creating a new person and viewing a workshop request) work correctly. $ docker compose -f docker/docker-compose.yml -p amy up -d database redis
            Set up your local database with fake (development-ready) data. This will create a superuser with "admin" as both the username and password. $ pipenv run make dev_database
            Create cache tables for use with the database cache backend. $ pipenv run python manage.py createcachetable
            Start a local Django development server by running: $ pipenv run make serve Note: this also installs front-end dependencies for AMY, including jQuery and Bootstrap (full list here).
            Open http://127.0.0.1:8000/workshops/ in your browser and start clicking. Use the default "admin" as username and password.
            Shut down the local server by typing Ctrl-C. Shut down the Docker Redis instance with: $ docker compose -f docker/docker-compose.yml -p amy down

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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          • HTTPS

            https://github.com/carpentries/amy.git

          • CLI

            gh repo clone carpentries/amy

          • sshUrl

            git@github.com:carpentries/amy.git

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