familytree | A very incomplete Django-based genealogy web app | Continuous Deployment library
kandi X-RAY | familytree Summary
kandi X-RAY | familytree Summary
A very incomplete Django-based genealogy web app.
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Top functions reviewed by kandi - BETA
- Return a listing of surnames
- List of surnames
- Show the surnames
- Return all locations for a given surname
- Render the ancestors of a person
- Describes a person
- Annotated list of ancestors
- Return a mapping of ancestors to their ancestors
- Render a person
- Iterate over the ancestors of this node
- Add a person
- Return the age of the person
- Displays a list of people in a given year
- View of the ancestors of a person
- Render a ring chart
- View of blood relations
- View of descendants of a person
- Report the ancestors of a person
- Validate that this person is valid
- Generate an HTML showing the ancestors of a person
- Displays all people in a given year
- Return True if the person has the age of death
- Displays people who have unknown man names
- Render a tree of descendants
- Convert to a date
- Returns a list of all the events
familytree Key Features
familytree Examples and Code Snippets
Community Discussions
Trending Discussions on familytree
QUESTION
I have a function that retrieve the details of family member and can count the total of family member to the fifth generation. Below is my code snipped
...ANSWER
Answered 2021-Dec-15 at 10:22check this out : assume the family function is defined and returns an array of all persons Childs, as we can get it from your question. in any recursive functions, you need a STOP condition that is a leaf from family tree (persons with no child). if we get this condition we must return 1 that defined the individual leaf person. otherwise, we can iterate over his/her Childs and do it again for he/she. the only remained item is to plus plus the total variable for persons with children.
QUESTION
I have a django app hosted on heroku, and I have a 'family album' page that loads a bunch of image thumbnails which link to a larger image detail page. (And the set of pictures can be different per user).
Each of these thumbnails uses an image_link.html template. At the most there can be up to ~1100 of these thumbnails on the family album page, and it loads peachy in production.
The problem: now I've added a little hover overlay (grabbed from w3schools here), so that when you mouse over a thumbnail you can see an overlay of who the picture contains. This list of is returned by a method on the Image class- it's not an attribute, so it's not returned with the Image objects.
Adding this has made the template really slow to load: 4-5 seconds locally, and ~22 seconds in production (Heroku, using 1 professional Dyno). I think usually this sort of thing would be made better by pagination, but in this case I like having one long page. (Though I'd be fine with having the top part load first and then the rest fill in afterward).
So I've done a few things:
- added a 'get_image_index_data' function in views.py to loop through, get the pictured_list results, make an array with what I'll need, and cache it. I'm calling this in a receiver function (listening for signal that user logged in) so it'll be set by the time the user clicks the Family Album link, and views.py gets it from the cache
- I added template fragment caching on the family album page
Issues: even with the data cached (and I confirmed that there wasn't a miss), this can still be slow-loading (until the template fragment caching kicks in? investigating...)
Here's the code:
I have a receiver function that calls this code to save the data:
...ANSWER
Answered 2021-Aug-25 at 12:40Some suggestions:
- Delegate the cache building on a background process handler like
celery - If you want to display a long page, have a look at doing a facebook-like infinite scroll pagination, to give the illusion that you have a long page but still paginating in the background.
QUESTION
I've been building my first Django project (just running it locally so far using runserver), and I'm taking the steps to host it on Heroku, adding gunicorn. The build succeeds, but when I try to open the app, the Heroku logs show an exception in worker process:
...ANSWER
Answered 2021-Jul-01 at 12:11#----------------------------Install packages----------------------------
1)pip install django-heroku
2)pip install whitenoise
#-----------------------------setting.py----------------------------------#
1)INSTALLED_APPS = [
...,
'django_heroku',
]
2)MIDDLEWARE = [
'whitenoise.middleware.WhiteNoiseMiddleware',
]
3)STATICFILES_STORAGE =
'whitenoise.storage.CompressedManifestStaticFilesStorage'
4)STATIC_ROOT = os.path.join(BASE_DIR, 'staticfiles')
STATIC_URL = '/static/'
# Extra places for collectstatic to find static files.
STATICFILES_DIRS = (
os.path.join(BASE_DIR, 'static'),
)
django_heroku.settings(locals())
#-----------------------urls.py---------------------------------------#
from django.conf import settings
from django.conf.urls.static import static
urlpatterns = [
...,
] + static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
#------------------Procfile create in Root DIR-----------------#
paste in (web: gunicorn projectname.wsgi)
#--------------create requirements.txt---------------------------#
pip freeze > requirements.txt
# runtime.txt create in Root DIR
paste in (your python version for ex.python-3.8.5)
#---------then commands in terminal-------------------------#
heroku login
heroku create YOUR_APP_NAME
##for Clone the repository.......
git init
heroku git:clone -a YOUR_APP_NAME
## for Deploy your changes......
git init
git add .
git commit - m "initial"
git push heroku master
## then
heroku run python manage.py migrate
heroku run python manage.py createsuperuser
QUESTION
I'm building out my first Django Project, and I'm always grateful that authentication steps are provided in modern frameworks, but I'm having trouble seeing how/where to customize the login process to do an additional step behind the scenes.
I followed a tutorial to use the Django authentication, and everything is working great. I made a registration/login.html page that includes 'next' for where to take the users. I include the Django urls for authentication in mysite/urls.py:
...ANSWER
Answered 2021-May-09 at 12:31First, see if this is needed. On every new login, Django updates last_login on the user model. If this is really different from what you want, read on.
You can override the authentication views and reimplement LoginView's form_valid.
First, we create a new app to handle the authentication. We will only override one bit, and delegate the rest to django.contrib.auth, but we may want to override more in the future, so let's keep it neatly organized.
So, create the new app, myauth:
python ./manage.py startapp myauth
And add it to INSTALLED_APPS in settings:
QUESTION
I have two javascript files which are both used in the same web page and which both use the resources of a third javascript file.
The main JS file Person6.js, at /FamilyTree/Person6.js on the webserver:
...ANSWER
Answered 2021-Mar-16 at 04:29import HTTP from "../jscripts6/js20/http.js";
QUESTION
I am trying to move my web site to use ES2015 including the use of export and import to control access to shared resources. This means that javascript files which formerly were explicitly included using HTML tags are now accessed using import statements. So I am moving from pages which include the following:
...ANSWER
Answered 2021-Mar-15 at 07:58It's not clear which module your initializeMaps() function is defined in, but that particular Google API requires that it be a global symbol so Google can find it when that script executes. And, it will have to be defined before the Google script executes too.
With ES6 modules, nothing in the script is automatically defined as globally available. So, unlike the older script files, top level variables in your script only have module scope and are not available globally. This is an important change with ES6 modules. You have to either export a symbol to make it available to other scripts or you have to explicitly make it global by assigning it to the window object (in the browser) like this:
QUESTION
I have a JSON parent-child recursive structure made like in the example below.
How can I filter this JSON list to exclude just the object corresponding to a selected index?
...ANSWER
Answered 2020-Nov-20 at 17:24Here is a way to solve your problem. The function familyTreeFilterChildrenByIndex checks the index of each element and also runs itself on any children.
QUESTION
So I'm making this family tree program thing, I've got two files:
FamNames.txt
...ANSWER
Answered 2020-Sep-20 at 23:49This line is breaking your logic:
QUESTION
My backend has two graphql queries: familiyTreeQuery which returns a family tree as a node with children, which can also have children and so on, and personPicturesQuery($name: string) which returns pictures of the given person.
My goal is to call the familyTreeQuery, iterate the tree and if the person is called Alice, then I want to call the personPicturesQuery for the person and add the information to the node in the tree. This should be done for all Alices in the tree.
My problem is, that the call to fetch pictures happens asynchronous and the data is therefore returned before the information is added to the node.
I failed to use flatMap as suggested in this question, because the call to fetch the pictures is happening while iterating the tree and I can't call it in the pipe method of the familyTreeQuery.
ANSWER
Answered 2020-Sep-03 at 14:14You can achieve that by creating an array of observables and passing it along recursively, then subscribing to it in getContext using forkJoin, as demonstrated below:
QUESTION
I have written a code that has a decorator function in Ruby 2.7. It works well in that version but the same code does not work correctly in Ruby 2.6. If I remove the call for the the decorator i.e., wrapper_function then the code executes in Ruby 2.6 but it is not the functionality that I want. So what is my mistake here and how can I rectify it?
EDITED
#test.rb
...ANSWER
Answered 2020-Aug-18 at 08:34Yes - removing both of the **kwargs in wrapper_function will make it work in both 2.6.x and 2.7.x
It has to do with Ruby 2.7 deprecating automatic conversion from a hash to keyword arguments
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install familytree
You can use familytree like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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