hilbert | : dancers : Implement mathematics | Math library

The code provided in the question does not work correctly, since it repeatedly overwrites the same list, so that in the end all rows of the resulting matrix are the same. One way to fix it and vectorize it is as follows:

At face value, that error means that tags aren't being placed for at least one of your recipients. Since you're using anchor strings to place tags, you'll want to confirm your document is machine-readable. The most straightforward way to do this would be to start a draft in the web console using your document and try to create auto-place tags using the same string you're using in your API Call.

Another test you could perform would be to change "status":"sent" to "status":"created" to generate a draft, then check that draft in the web console to see which recipient is missing tags.

Finally, I'm not sure it would cause the problem you're describing, but I notice you're defining RecipientIds along with the RoleName. In some cases, defining a recipient id can prevent the recipient role from matching correctly with the template - you might try this with the recipient ID removed to see if the behavior changes.

Short of rethinking the program's entire approach, here's a quick fix that provides noticeable speed up. We'll use tracer() and update() to precisely control the graphics. We don't want to hide any of the drawing (which is possible with tracer()) but rather only draw when there is a line to draw, treating all the turtle's turns as internal logic calculations, displaying only the final heading:

Thanks for providing the URL to the repro. This error, as it happens not infrequently, appears to be one deeper down 'hidden' by devtools::document().

When I clone your repo onto a machine with 'current everything' from CRAN running Ubuntu 21.04 and doing my usual two-step of

You can try str.replace

What the cited paragraph means, is a separated section of your program. These string constants are neither in the stack nor on the heap.

Think about these kinds of sections a program may use to store stuff (common names of sections defined in the executable's file format in parentheses):

• The machine code to execute (.text);
• Static read-only values, for example static const variables (.rodata);
• Static read-write variables with non-zero initial values (.data);
• Static read-write variables with zero'ed initial values (.bss);
• The stack to hold return addresses, function parameters, local variables, and so on; sometimes these are separated;
• The heap, if there is one at all.

String constants commonly fall in the category "static read-only values". Some compiler systems separate them from non-string values.

Any compiler system may have these sections or not, but they are quite common.

Anyway, abstract from this implementation detail. It will only help you if you need to go that deep, and you need to know how your specific compiler system works.

On the abstract level, we can differentiate two cases:

The string constant is stored somewhere, and its address is assigned to p. If you overwrite this variable with another value, you will lose the address.

An extra space is needed for the variable p. Where this is, depends on the variable.

The string constant is stored somewhere, too. The array is allocated at this place. As long as a is visible, you can access its characters.

Final note: Characters of a string constant are read-only. Always declare your respective variable with const char.

"In addition to the bug mentioned by @PaulChernoch in the above mentioned SE post, the next for loop segfaults, too." Actually it was a bug in my code--I was having a hard time iterating over a container backwards. I started looking at myself after I realized there were other Python packages (e.g. this and this) that use the same underlying C code. Neither of them were complaining about the other for loop.

In short, I changed

numpy.ndarray.view returns a view of the same array with another (equally sized) datatype, and should due to not copying anything pretty much be instantaneous.

By your description I would simply use