robin | RObust document image BINarization | Computer Vision library
kandi X-RAY | robin Summary
kandi X-RAY | robin Summary
robin is a RObust document image BINarization tool, written in Python.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Parse command line arguments
- Create callbacks for model
- Create a directory
- Unetleneck tensors
- Double convolution layer
- Down layer
- Shuffle images
- Saves two images
- Save the metrics to disk
- Binarize an image
- Postprocess image
- Preprocess image
- Process an image
- Split an image overlays
- Saves two images together
- Create a directory if it exists
robin Key Features
robin Examples and Code Snippets
def round_robin(
self, ready_queue: deque[Process], time_slice: int
) -> tuple[deque[Process], deque[Process]]:
"""
RR(Round Robin)
RR will be applied to MLFQ's all queues except last queue
All processes
public int rob(int[] nums) {
if (nums.length == 0) {
return 0;
}
if (nums.length < 2) {
return nums[0];
}
int[] first = new int[nums.length + 1];
int[] second = new i
public int rob(int[] nums) {
if(nums.length == 0) {
return 0;
}
if(nums.length == 1) {
return nums[0];
}
int[] dp = new int[nums.length];
dp[0] = nums[0];
dp[1] = nums
Community Discussions
Trending Discussions on robin
QUESTION
This code is supposed to do the following:
- Take the four worksheets listed in the array (dim as s) export them as a pdf
- Attach that pdf to an email and add a simple generic message
- Insert the applicable email address into the To field on the email
- Display the email to allow the user to review it before they hit send.
I have this code working correctly except for Step 3.
The problem I am having is getting the 4 email addresses to loop correctly to load them into the “To: field” for the emails. It will assign the first email address to “strNames” but will continue to use it until after all 4 sheets are exported, so they all are addressed to ABC@gmail.com Only after it exits that loop, will it cycle down to the next email address Achieve@gmail.com Because there are 4 email addresses and 4 worksheets, I end up with 16 emails when it should be 4 different emails each having 4 different applicable attachments.
I need a nested loop in the code to cycle through the email list, but I’ve been unable to make it work as desired. I added a few notes below to illustrate what is needed.
Just to clarify, when done I should have 4 emails on my desktop ready to send as follows:
An email addressed to “ABC@gmail.com” with attached file: 2022 02 (TED)_ABC Therapy.pdf An email addressed to “Achieve@gmail.com” with attached file: 2022 02 (TED)_Achievement Therapy.pdf An email addressed to “Barb@gmail.com” with attached file: 2022 02 (TED)_Barb Therapy.pdf An email addressed to “Robin@yahoo.com” with attached file: 2022 02 (TED)_Felisa, Robin V..pdf
I would appreciate any help with this VBA code.
Thanks, Ted
...ANSWER
Answered 2022-Mar-10 at 17:57It is easy to see that you're getting 16 results (or emails) in this code because you're using two 4-time cycles. Basically your For i cycle is repeating your For each cycle four times.
What I would do is delete your For i cycle and maybe add a validation later in the code (if-then) to validate what email address to send the result to. For convenience and to keep it simple, I'll just add a counter for now.
QUESTION
I am an ASL.NET Core developer and I try to use vuejs
in order to create some complex forms. In order to learn how to use it I create static html files in order to understand how the components work in vuejs. I have the following example:
ANSWER
Answered 2022-Mar-06 at 15:59You can not use vuejs-datepicker
in Vue3, you can try with vue3datepicker
:
QUESTION
This is my first stack overflow question, so if I am presenting something wrong, please let me know. I am pretty new to computer programming, so I just have a small webpage where I am just implementing things that I am learning.
I made a little quiz with random trivia multiple choice questions you can take if you press a button. I am using window prompts to ask the questions and get the answers, and I have all of the questions and answers stored as objects with question/prompt and answer pairs. All of those objects are stored in an array in a variable called shortQuizPrompts. I already have the quiz working and everything, aka., It tells you after every question if you got the answer to that question right or wrong, and it gives you a grade afterwards... I also have it set up so that if you enter an answer that is not "a", "b", "c", or "d", it lets you know that it isnt a valid answer. Those sorts of things.
As of right now, you can choose how many questions long you want the quiz to be out of the 24 total questions I have so far. It just asks the questions in the order that they are stored in the array. For example, you will never be asked the last question in the array if you do not choose for the quiz to be the full 24 questions long. However, I want to make the quiz ask the questions in a random order, while also removing those questions from the array as to not ask the same question multiple times.
I have tried increasing the iterator while looping through the array to a random number from 0 to the length of however many questions they chose. Then checking to see if the iterator was larger than the length of the number of questions they chose, it would decrease the iterator until it found a question that is still in the array that it could ask...
If anyone knows how to go about doing that, it would be great. Sorry for the long question btw. I am pretty new to coding, so this is probably a simple answer, but I digress. I'm pretty sure I did everything right. Thx.
...ANSWER
Answered 2022-Jan-12 at 01:03You can shuffle the shortQuizPrompts
array before starting the quiz. Array shuffle details can be found in this answer.
QUESTION
So, I am trying to check the format of a key using the regex.h
library in C. This is my code:
ANSWER
Answered 2021-Dec-26 at 22:00There are at least two issues here and one extra potential problem:
- The limiting quantifiers will work as such in a POSIX ERE flavor, thus, as it has been pointed out in comments, you need to
regcomp
the pattern with aREG_EXTENDED
option (i.e.res = regcomp(®ex, reg, REG_EXTENDED)
) - The
\w
shorthand character class does not work inside bracket expressions as a word char matching pattern, you need to replace it with[:alnum:]_
, i.e.[\w-]
must be replaced with[[:alnum:]_-]
. The solution will be:
QUESTION
Would it be possible to make a round robin algorithm with an unbounded number of resting players? For example this would work but it can only manage one resting player/team.
An actual scenario would be 24 players, 16 players playing each round and 8 players waiting out each round. Ideally they would all have played each other in 23 rounds and double rests would be avoided as much as possible.
I've been stuck on this problem for quite a while now so I would really appreciate your help!
...ANSWER
Answered 2021-Nov-11 at 20:42As long as the total number of matches is divisible by the number of matches per day, that's possible. In your scenario, there are 8 matches per day and (12*23) total matches, so it's not possible, but having 12, 8, 6, 4, or 2 players in each round would work.
You can modify the circle method of scheduling. If you have 2N players, the scheduling algorithm normally generates blocks of N pairs in columns:
QUESTION
I have a simple class Person
:
ANSWER
Answered 2021-Oct-22 at 19:25Basically, all you need is grouping using Collectors.groupBy(Function)
and a function that assigns each Person
into a correct group:
QUESTION
For a college assignment, we have to write a bunch of SQL queries based on question we got, the last question states:
`Write a query that will indicate which employee has been booked off for the most number of days by doctor ‘D0001’. Display the employee name and surname, doctor name, and the number of days
My issue is even when I say what value I want to select it return the wrong name of the doctor which I can't understand as to why that happens. The other values in the query are being displayed as it should, the only issue is the Doctor's name from their ID that is incorrectly displayed
The Table
...ANSWER
Answered 2021-Oct-21 at 07:48Really important point in the comments
Tip of today: Switch to modern, explicit JOIN syntax everywhere. Easier to write (without errors), easier to read (and maintain), and easier to convert to outer join if needed.
~ jarlh
So let's take your joins:
QUESTION
I have an AWS Application load balancer to distribute the http(s) traffic.
Problem 1:
Suppose I have a target group with 2 EC2 instances: micro and xlarge. Obviously they can handle different traffic levels. Does the load balancer manage traffic proportionally to instance sizes or just round robin? If only round robin is used and no other factors taken into account, then it's not really balancing load, because at some point the micro instance will be suffering from the traffic, while xlarge will starve.
Problem 2:
Suppose I have target group with 2 EC2 instances, both are same size. But my service is not using a classic http request/response flow. It is using HTTP websockets, i.e. a client makes HTTP request just once, to establish a socket, and then keeps the socket open for longer time, sending and receiving messages (e.g. a chat service). Let's suppose my load balancer is using round robin and both EC2 instances have 1000 clients connected each. Now suppose one of the EC2 instances goes down and 1000 connected clients drop their socket connections. The instance gets back up quickly and is ready to accept websocket calls again. The 1000 clients who dropped are trying to reconnect. Now, if the load balancer would use pure round robin, I'll end up with 1500 clients connected to instance #1 and 500 clients connected to instance #2, thus not really balancing the load correctly.
Basically, I'm trying to find out if some more advanced logic is being used to select a target in a group, or is it just a naive round robin selection. If it's round robin only, then how can I really balance the websocket connections load?
...ANSWER
Answered 2021-Oct-14 at 12:42Websockets start out as http or https connections, so a load balancer can dispatch them to a server. Once the server accepts the http connection, both the server and the client "upgrade" the connection to use the websocket protocol. They then leave the connection open to use for websocket traffic. As far as the load balancer can tell, the connection is simply a long-lasting http connection.
Taking a server down when it has websocket connections to clients requires your application to retry lost connections. Reconnecting on connection failure is one of the trickiest parts of websocket client programming. Your application cannot be robust without reconnect logic.
AWS's load balancer has no built-in knowledge of the capabilities of the servers behind it. You have observed that it sends requests equally to big and small servers. That can overwhelm the small ones.
I have managed this by building a /healthcheck endpoint in my servers. It's a straightforward https://example.com/heathcheck web page. You can put a little bit of content on the page announcing how many websocket connections are currently open, or anything else. Don't password protect it or require a session to hit it.
My /healthcheck endpoints, whenever hit, measure the server load. I simply use the number of current websocket connections, but you can use any metric you want. I compare the current load to a load threshold configured for each server. For example, on a micro instance I can handle 20 open websockets, and on a production instance I can handle 400.
If the server load is too high, my endpoint gives back a 503 http error status along with its content. 503 typically means "I am overloaded, please try again later." It can also mean "I will shut down when all my connections are closed. Please don't use me for any more connections."
Then I configure the load balancer to perform those health checks every couple of minutes on all the servers in the server pool (AWS calls the pool a "target group"). The health check operation detects "unhealthy" servers and temporarily takes them out of its rotation. (The health check also detects crashed servers, which is good.)
You need this loadbalancer health check for a large-scale production setup.
All that being said, you will get best results if all your server instances in your pool have roughly the same capacity as each other.
QUESTION
I have an (internal) K8s deployment (Python, TensorFlow, Guinicorn) with around 60 replicas and an attached K8s service to distribute incoming HTTP requests. Each of these 60 pods can only actually process one HTTP request at a time (because of TensorFlow reasons). Processing a request takes between 1 and 4 seconds. If a second request is sent to a pod while it's still processing one, the second request is just queued in the Gunicorn backlog.
Now I'd like to reduce the probability of that queuing happening as much as possible, i.e., have new requests routed to one of the non-occupied pods as long as such a non-occupied one exists.
Round-robin would not do the trick, because not every request takes the same amount of time to answer (see above).
The Python application itself could make the endpoint used for the ReadinessProbe fail while it's processing a normal request, but as far as I understand, readiness probes are not meant for something that dynamic (K8s would need to poll them multiple times per second).
So how could I achieve the goal?
...ANSWER
Answered 2021-Sep-24 at 04:55Can't you implement the pub/sub or message broker in between?
saver data into a queue based on the ability you worker will fetch the message or data from queue and request will get processed.
You can use Redis for creating queues and in queue, you can use pub/sub also possible using the library. i used one before in Node JS however could be possible to implement the same using python also.
in 60 replicas ideally worker or we can say scriber will be running.
As soon as you get a request one application will publish it and scribers will be continuously working for processing those messages.
We also implemented one step further, scaling the worker count automatically depends on the message count in the queue.
This library i am using with the Node js : https://github.com/OptimalBits/bull
QUESTION
From my understanding, the Datastax driver is TokenAware
:
Token-aware policy is used to reduce network hops whenever possible by sending requests directly to the node that owns the data.
The driver has also some DCAwareRoundRobinPolicy
, in order to query an other datacenter if needed, and to repartitate the load :
This policy provides round-robin queries over the node of the local data center. It also includes in the query plans returned a configurable number of hosts in the remote data centers
Questions :
It seems out that with client driver configuration, it is already possible to do HighAvailability, LoadBalancing, and be TokenAware.
Regarding those elements, do you think it is still a good practice to also add
HaProxy
on top of Cassandra ?If yes on first question, may I loose the
TokenAware
property ?If yes on first question, will the contact point continue to send to the java driver the correct topology (ip/host list of nodes) ?
Thank you
...ANSWER
Answered 2021-Sep-24 at 10:07Usually it's not recommended to have a proxy before Cassandra - the TokenAware load balancing policy will work just out of box (if you're using prepared statements). Besides the selecting correct replicas, it will take into account the status of the node, etc.
The problem with proxy is that after the first contact, the driver will receive the list of the all nodes in the cluster, so driver will try to use these nodes anyway, not the proxy node (until you're using whitelist code load balancing policy, or you implemented the address translation functionality).
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install robin
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page