leetcode | Python & JAVA Solutions for Leetcode | Learning library

 by   qiyuangong Python Version: Current License: MIT

kandi X-RAY | leetcode Summary

kandi X-RAY | leetcode Summary

leetcode is a Python library typically used in Tutorial, Learning, Example Codes applications. leetcode has no vulnerabilities, it has a Permissive License and it has medium support. However leetcode has 6 bugs and it build file is not available. You can download it from GitHub.

Remember solutions are only solutions to given problems. If you want full study checklist for code & whiteboard interview, please turn to jwasham's coding-interview-university. Also, there are open source implementations for basic data structs and algorithms, such as Algorithms in Python and Algorithms in Java. I'm currently working on Analytics-Zoo - an unified Data Analytics and AI platform. Check it out, if you are interested in big data and deep learning.

            kandi-support Support

              leetcode has a medium active ecosystem.
              It has 4810 star(s) with 1435 fork(s). There are 123 watchers for this library.
              It had no major release in the last 6 months.
              There are 3 open issues and 12 have been closed. On average issues are closed in 68 days. There are 7 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of leetcode is current.

            kandi-Quality Quality

              leetcode has 6 bugs (2 blocker, 0 critical, 2 major, 2 minor) and 1211 code smells.

            kandi-Security Security

              leetcode has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              leetcode code analysis shows 0 unresolved vulnerabilities.
              There are 1 security hotspots that need review.

            kandi-License License

              leetcode is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              leetcode releases are not available. You will need to build from source code and install.
              leetcode has no build file. You will be need to create the build yourself to build the component from source.
              leetcode saves you 3748 person hours of effort in developing the same functionality from scratch.
              It has 7999 lines of code, 683 functions and 488 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed leetcode and discovered the below as its top functions. This is intended to give you an instant insight into leetcode implemented functionality, and help decide if they suit your requirements.
            • Generate palindromes
            • Permute a permutation
            • Get_permute function
            • Returns the partition of the value at the given position
            • Return True if head is palindrome
            • Recursively recursively recursively subroutine
            • Minimal XOR
            • Count the number of elements in x
            • Compute the maximum overlap between a set of points
            • Generate the GCD
            • Generate a list of unique permutations
            • Returns the number of islands in a grid
            • Return the index of the substring in haystack
            • Find the length of the ladder
            • Adds key to the list
            • Determines if two trees are similar
            • Return the value of key in the tree
            • Calculates the number of islands between two points
            • Find circular array loop
            • Returns the length of the longest sequence of nums
            • Insert new intervals into intervals
            • Computes the minimum optimal cost for a given customer cost
            • Find the next permutation
            • Reverse words
            • Flatten a tree
            • Reverse node in the list
            Get all kandi verified functions for this library.

            leetcode Key Features

            No Key Features are available at this moment for leetcode.

            leetcode Examples and Code Snippets

            LeetCode CLI,Demo
            Pythondot img1Lines of Code : 141dot img1License : Permissive (MIT)
            copy iconCopy
            #:/> ls
                 29 #
                 81 array
                 28 backtracking            <- 28 problems todo in backtracking
                  5 binary-indexed-tree
                 35 binary-search
                 12 binary-search-tree
                 26 bit-manipulation
                  3 brainteaser
                 31 breadth-first-  
            LeetCode Solution Swift,Notes,Helper Class
            Swiftdot img2Lines of Code : 38dot img2License : Permissive (MIT)
            copy iconCopy
            Empty tree. The root is a reference to nil
                  / \
                 2   3
                  / \
                 4   7
                /   /
               3   2
              /   /
             -1  9
            let root = BinaryTreeHelper.buildTree(withNodes: [10,7,12,6,  
            LeetCode CLI,Usage
            Pythondot img3Lines of Code : 31dot img3License : Permissive (MIT)
            copy iconCopy
            $ leetcode-cli
            Username: student
            Welcome student!
            243 solved 17 failed 523 todo
            #:/> ?
            cat                     - Show test case(s).
            cd          - Change problem(s).
            cheat           - C.H.E.A.T.
            Convert roman to an integer .
            pythondot img4Lines of Code : 21dot img4License : Permissive (MIT License)
            copy iconCopy
            def roman_to_int(roman: str) -> int:
                LeetCode No. 13 Roman to Integer
                Given a roman numeral, convert it to an integer.
                Input is guaranteed to be within the range from 1 to 3999.

            Community Discussions


            LeetCode TwoSum question returning buggy answer (C Implementation)
            Asked 2021-Jun-15 at 16:06

            Here is the question:



            Answered 2021-Jun-15 at 16:06

            You have to assign the number of elements of the array to return (2 in this case) to what the argument returnSize points at (*returnSize) to tell the judge system how large the array you returned is.

            Source https://stackoverflow.com/questions/67989752


            Why is the output an empty list, when I call a function that skips nodes in a linked-list?
            Asked 2021-Jun-15 at 10:52

            I am writing code to answer the following LeetCode question:

            Given the head of a linked list and an integer val, remove all the nodes of the linked list that has Node.val == val, and return the new head

            Example 1 ...


            Answered 2021-Jun-15 at 10:52

            Some issues in your code (as it was first posted):

            • return skipper(prev,curr) is going to exit the loop, but there might be more nodes to be removed further down the list. skipper only takes care of a sub sequence consisting of the same value, but it will not look beyond that. The list is not necessarily sorted, so the occurrences of the value are not necessarily grouped together.

            • Be aware that the variable prev in skipper is not the same variable as the other, outer prev. So the assignment prev=curr in skipper is quite useless

            • Unless the list starts with the searched value, dummy.next will always remain None, which is what the function returns. You should initialise dummy so it links to head as its next node. In your updated code you took care of this, but it is done in an obscure way (in the else part). dummy should just be initialised as the head of the whole list, so it is like any other node.

            In your updated code, there some other problems as well:

            • while prev.next: risks to be an infinite loop, because it continues while prev is not the very last node, but it also doesn't move forward in that list if its value is not equal to the searched value.

            I would suggest doing this without the skipper function. Your main loop can just deal with the cases where current.val == val, one by one.

            Here is the corrected code:

            Source https://stackoverflow.com/questions/67982630


            how can i check if a string contains another string throughout it
            Asked 2021-Jun-14 at 19:40

            I have two lists of strings and i want to check if the words within one list contain the strings within the other list throughout

            Here is an example of what i mean:



            Answered 2021-Jun-14 at 19:33


            Time and Space complexity of Palindrome Partitioning II
            Asked 2021-Jun-13 at 16:48

            So I was solving this LeetCode question - https://leetcode.com/problems/palindrome-partitioning-ii/ and have come up with the following most naive brute force recursive solution. Now, I know how to memoize this solution and work my way up to best possible with Dynamic Programming. But in order to find the time/space complexities of further solutions, I want to see how much worse this solution was and I have looked up in multiple places but haven't been able to find a concrete T/S complexity answer.



            Answered 2021-Jun-13 at 16:48

            Let's take a look at a worst case scenario, i.e. the palindrome check will not allow us to have an early out.

            For writing down the recurrence relation, let's say n = end - start, so that n is the length of the sequence to be processed. I'll assume the indexed array accesses are constant time.

            is_palindrome will check for palindromity in O(end - start) = O(n) steps.

            dfs_helper for a subsequence of length n, calls is_palindrome once and then has 2n recursive calls of lengths 0 through n - 1, each being called two times, plus the usual constant overhead that I will leave out for simplicity.

            So, we have

            Source https://stackoverflow.com/questions/67870431


            Unable to resolve memory read and segmentation fault error in C++
            Asked 2021-Jun-12 at 00:42

            I am coding a solution program for leetcode. I have encountered memory read errors and segmentation fault errors which I am unable to resolve. I have tried tinkering with the code to try and remove the errors.
            For example: in the numIslands function's last lines, I had tried declaring coordinates as an array rather than a pointer but the results did not change.
            *(last + 1) = *(coordinates + 1); does not seem to work at all in the numIslands function. I am totally blank about what to do next.



            Answered 2021-Jun-12 at 00:42

            I have ran it through gdb. After a bit of digging, the error is this:

            Source https://stackoverflow.com/questions/67943797


            Detecting signed integer multiplication overflow in C
            Asked 2021-Jun-09 at 21:03

            I'm writing this code for more than 3 hours already..

            I gave up about the overflow thing and tried to google and look it up on stackoverflow.

            I did not find any solution besides the one that I wrote in my code as you can see in lines 27-28 (where it returns 0). But this condition also does not work.



            Answered 2021-Jan-13 at 12:43

            The main thing you want to check for overflow is this:

            Source https://stackoverflow.com/questions/65695619


            Not being able to find an edge case in question "Process Tasks Using Servers" asked in leetcode weekly contest 243
            Asked 2021-Jun-09 at 06:41

            [link to the question] (https://leetcode.com/problems/process-tasks-using-servers/). The problem statement is clearly written in the provided link. I've highlighted a difference between my result and the expected result.

            I'm not able to figure out which edge case or condition I've missed?

            If the problem statement is still unclear then please do let me know.

            Update: The updated solution is in the comment section.



            Answered 2021-Jun-09 at 06:39

            A point to remember: Servers present inside runningServers heap have higher priority than the servers that are present in the pool serverId waiting for some task.

            Now, assume that we have 3 servers s1, s2, s3 having priority order s1 > s2 > s3, and 4 tasks t1, t2, t3, t4 with arrival time in increasing order. Also, assume that when we were about to allocate a server for t4, then by that time s2 and s3 got free.

            Now, ideally, we should choose server s2 for task t4 but the above-given algorithm is going to choose s3 for t4 because it's maintaining a min-heap property on the finish time of the servers. So it's important to first free all the servers that have finish time <= currTime, and then choose a new server for t4 from the pool.

            Now, what would happen if no server can be chosen from runningServer and we don't even have any server available in the pool serverId?

            solution: We'll have to wait for some time for one of the servers to get free. let's say a server is going to get free at time = x ms, and it is also possible that there are multiple servers that are going to get free at time = x ms.

            So, the final solution for the problem statement is:

            Source https://stackoverflow.com/questions/67790422


            Why does my operation of mod (%) on a 2 digit number return zero in python
            Asked 2021-Jun-07 at 07:00

            I've been trying to attempt some leetcode questions as a complete beginner, and a section requires me to convert/return the thousands, hundreds, tens and units place of a number.

            This is the code in python.



            Answered 2021-Jun-07 at 07:00

            you have a typo in these code block:

            Source https://stackoverflow.com/questions/67866749


            Does variable shadowing work on all compilers in C++?
            Asked 2021-Jun-06 at 17:08

            I ran this code on Leetcode.com but it prints random numbers. It works on my local machine, however. Anybody know if variable shadowing is supposed to work across all compilers?



            Answered 2021-Jun-06 at 15:46

            The shadowing is defined by the C++ standard, and must work on all conforming compilers.

            Your code prints garbage, because carry in carry + 1 reads the new variable (which isn't initialized at that point yet, causing UB), not the old one.

            Source https://stackoverflow.com/questions/67860922


            Using char to access vector
            Asked 2021-Jun-06 at 13:42

            I'm working my way through the leetcode problems in C++ for practice.

            I'm at problem number 3. I don't quite understand why you can access vector using char datatype.

            For example:



            Answered 2021-Jun-06 at 03:23

            Assuming your system is using ASCII or UTF-8 or something like that, 'a' == 97.

            So, this is equivalent to chars[97]++.

            Source https://stackoverflow.com/questions/67855515

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network


            No vulnerabilities reported

            Install leetcode

            You can download it from GitHub.
            You can use leetcode like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.


            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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