project-euler | My solutions to Project Euler in Python | Learning library
kandi X-RAY | project-euler Summary
kandi X-RAY | project-euler Summary
My solutions to Project Euler in Python
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project-euler Key Features
project-euler Examples and Code Snippets
def solution(roman_numerals_filename: str = "/p089_roman.txt") -> int:
"""
Calculates and returns the answer to project euler problem 89.
>>> solution("/numeralcleanup_test.txt")
16
"""
savings = 0
file1 = o
def all_solution_file_paths() -> list[pathlib.Path]:
"""Collects all the solution file path in the Project Euler directory"""
solution_file_paths = []
for problem_dir_path in PROJECT_EULER_DIR_PATH.iterdir():
if problem_dir_pat
def test_project_euler(solution_path: pathlib.Path) -> None:
"""Testing for all Project Euler solutions"""
# problem_[extract this part] and pad it with zeroes for width 3
problem_number: str = solution_path.parent.name[8:].zfill(3)
Community Discussions
Trending Discussions on project-euler
QUESTION
So I designed this code (given below) for the question & it seems to be giving all the answers there are but for some reason I'm not able to pass my test cases in the Hackerrank Question except for the sample one.
My Code :
...ANSWER
Answered 2021-May-29 at 00:12You have three problems with this code:
- An actual bug. You don't handle when a prime divides the number multiple times. I'm fairly sure the four lines before the
println
output are a workaround you put in when you encountered a failure this causes, that fixed the specific failure you found but don't actually address the root cause. I just tested it, your code outputs 3 for the input 252. The correct output for 252 is 7. - Part of your code invokes a library method that may be significantly expensive. You should not be using
isProbablePrime
. - Your algorithm's logic scales poorly. Hackerrank's test cases probably include something where the correct output is something like 20 digits long. A major point of Project Euler is that it's not enough to write code that will find the correct answer. You need to write code that will find the correct answer efficiently. To fix this, you will need new logic for the fundamental design of the program.
QUESTION
I solving Problem 18 on Project Euler and have written the code for it as below:
...ANSWER
Answered 2021-Mar-21 at 12:52You are assuming that the optimal path will always move down via the child with the greatest value, but this is not true. A child with a lesser value may open up a possibility (at lower layers) to find a much greater value, which more than compensates for the temporary less optimal value.
So your algorithm, in its first iteration will go from 75 to the 95 on the second row. But this turns out to be the wrong choice. You'll have to come up with a better algorithm. You will find inspiration in other Q&A about this particular challenge, like this one.
Here you see the optimal path:
path 75 95 64 17 47 82 18 35 87 10 20 04 82 47 65 19 01 23 75 03 34 88 02 77 73 07 63 67 99 65 04 28 06 16 70 92 41 41 26 56 83 40 80 70 33 41 48 72 33 47 32 37 16 94 29 53 71 44 65 25 43 91 52 97 51 14 70 11 33 28 77 73 17 78 39 68 17 57 91 71 52 38 17 14 91 43 58 50 27 29 48 63 66 04 68 89 53 67 30 73 16 69 87 40 31 04 62 98 27 23 09 70 98 73 93 38 53 60 04 23QUESTION
Hello,
Question -- Problem 94, Project Euler -- Python -- Almost equilateral triangles
It is easily proved that no equilateral triangle exists with integral length sides and integral area. However, the almost equilateral triangle 5-5-6 has an area of 12 square units. We shall define an almost equilateral triangle to be a triangle for which two sides are equal and the third differs by no more than one unit. Find the sum of the perimeters of all almost equilateral triangles with integral side lengths and area and whose perimeters do not exceed one billion (1,000,000,000).
Output: 518408346
I have a very inneficient solution and it is as follows:
- I tried to bruteforce(it took a considerable amount of time)(using a for loop)
- Then I added in the condition to check whether it was a triangle(sum of two sides is greater than the third)
- Next, I defined the values in a perimeter variable and also used simple geometry for the area variable
- Next, to check whether they were valid, for the perimeter I used a type method to check whether it was int and since i couldn't do the same for area(since even if it was an integer, it would be part of the float class), I used modulo 1 == 0 to check if it was an integer
- If it satisfied the condition, i added it to my final 'sum of perimeter' variable. *The code is as follows: *
ANSWER
Answered 2020-Nov-21 at 09:19You could decide to use functions:
QUESTION
I was recently playing with problem 14 of the Euler project
: which number in the range 1..1_000_000
produces the longest Collatz sequence?
I'm aware of the issue of having to memoize to get reasonable times, and the following piece of Python
code returns an answer relatively quickly using that technique (memoize to a dict):
ANSWER
Answered 2020-Nov-16 at 03:56I think the majority of the extra time is because Raku has type checks, and they aren't getting removed by the runtime type specializer. Or if they are getting removed it is after a significant amount of time.
Generally the way to optimize Raku code is first to run it with the profiler:
QUESTION
I am going through a solution to the "Pyramid Slide Down" problem (https://www.mathblog.dk/project-euler-18/) and I need help understanding more intuitively the logic behind the solution for updating an index variable in the inner loop.
The algorithm:
...ANSWER
Answered 2020-Jul-01 at 04:22Here's how this algorithm works:
QUESTION
Edit: I found the issue: I have not accounted for when multiples of 3 and 5 match! Any hints on how to eliminate the duplicate numbers?
I'm trying to solve the first problem of the Euler Problems from Free Code camp: Multiples of 3 and 5 https://learn.freecodecamp.org/coding-interview-prep/project-euler/problem-1-multiples-of-3-and-5
The problem is this: Find the sum of all the multiples of 3 or 5 below the provided parameter value number.
When I look at my code, it works for the case of 10, but not any of the others. I have looked, tried another option but can not find the issue. Here is what I did.
My Thought Process and current implementation of task
- Made a loop listing all numbers until the parameter number
- Made two while loops one for multiples of 3 and one for multiples of 5
In each while loop I wanted to continuously add the multiplier (3 or 5) until the num is less than the total of threes or fives I had to add +3 and +5 so the last number in the total array would not go over num
I then took the total array and implemented the reduce function to get the sum of the threes and fives totals
Note: I am able to get an array of the values. In the case of 10, I got [3, 6, 9, 5]
My Code
...ANSWER
Answered 2019-Jan-13 at 22:12Your current solution could be fixed by eliminating the duplicates from the two arrays (the ones that store the multiples). However, it is still a very roundabout way of achieving what you want. From your problem statement I don't see why you need to store the multiples and then get the sum as you have chosen to do.
Since you are looping through all integers between 1 and your parameter anyway, you could instead add them to the sum as soon as you come across them:
QUESTION
I am trying to go through SICP using Racket and Project Euler as reference for practice. This question is in regards to problem 4 (https://projecteuler.net/problem=4), hence:
A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 × 99. Find the largest palindrome made from the product of two 3-digit numbers.
I am currently still on Chapter 1 (SICP) and loops have not been covered yet, as I see most solutions use. My code runs out of memory every time I try to execute (I have been stuck on this for hours - https://github.com/polila/Project-Euler/commits?author=polila&since=2018-03-19T04:00:00Z&until=2018-03-20T04:00:00Z) LOL.
What I am trying to do is use a recursive procedure by the process of linear iteration (at least that's what I think) - so in my mind it was something like this, where a and b are the max limit of n-digit:
...ANSWER
Answered 2018-Mar-20 at 08:33You have the right general idea of looking at multiples starting at 999x999 all the way down to 100x100. You can improve efficiency on this method by terminating b
whenever a x b
is a palindrome, such that you don't test for palindromes in a x b-1
etc. since those products will be smaller in value than a x b
.
What this looks like is:
QUESTION
I have created a spider to scrape problems from projecteuler.net. Here I have concluded my answer to a related question with
I launch this with the command scrapy crawl euler -o euler.json and it outputs an array of unordered json objects, everyone corrisponding to a single problem: this is fine for me because I'm going to process it with javascript, even if I think resolving the ordering problem via scrapy can be very simple.
But unfortunately, ordering items to write in json by scrapy (I need ascending order by id field) seem not to be so simple. I've studied every single component (middlewares, pipelines, exporters, signals, etc...) but no one seems useful for this purpose. I'm arrived at the conclusion that a solution to solve this problem doesn't exist at all in scrapy (except, maybe, a very elaborated trick), and you are forced to order things in a second phase. Do you agree, or do you have some idea? I copy here the code of my scraper.
Spider:
...ANSWER
Answered 2018-Feb-16 at 14:28If I needed my output file to be sorted (I will assume you have a valid reason to want this), I'd probably write a custom exporter.
This is how Scrapy's built-in JsonItemExporter
is implemented.
With a few simple changes, you can modify it to add the items to a list in export_item()
, and then sort the items and write out the file in finish_exporting()
.
Since you're only scraping a few hundred items, the downsides of storing a list of them and not writing to a file until the crawl is done shouldn't be a problem to you.
QUESTION
I was trying to solve Project Euler's 25th (https://projecteuler.net/problem=25) problem in Swift and got a pretty cryptical error message when I changed my condition in the while
loop.
At first, I started with 2, and then 10 and got the right results. But then with 100, the program crashed.
...ANSWER
Answered 2017-Aug-19 at 22:34Your algorithm is right, but the problem is that Swift 64 bit integers can only hold values up to 9,223,372,036,854,775,807, i.e. 9.22e+18. Unsigned integers can be twice as large, but still nowhere close to 1,000 digits. Decimal
/NSDecimalNumber
gets you up to 38 digits, which still is not sufficient.
You probably want to create/use a library that can represent arbitrarily large integers. Just search the interwebs for "swift arbitrarily large integer" or "swift biginteger".
Then your routine will correctly calculate the result.
QUESTION
so , I solved a problem online where I found the Largest product of any 5 consecutive numbers In a 1000-digit number :
...ANSWER
Answered 2017-Mar-24 at 10:48You may do as follows;
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Install project-euler
You can use project-euler like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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