Roster | Tor project that awards points | iOS library

 by   seansaito Python Version: Current License: No License

kandi X-RAY | Roster Summary

kandi X-RAY | Roster Summary

Roster is a Python library typically used in Mobile, iOS applications. Roster has no bugs, it has no vulnerabilities, it has build file available and it has low support. You can download it from GitHub.

A Tor project that awards points and badges to relay operators based on the performance of their families.
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            kandi-support Support

              Roster has a low active ecosystem.
              It has 4 star(s) with 1 fork(s). There are 5 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 6 open issues and 18 have been closed. On average issues are closed in 13 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of Roster is current.

            kandi-Quality Quality

              Roster has no bugs reported.

            kandi-Security Security

              Roster has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Roster does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              Roster releases are not available. You will need to build from source code and install.
              Build file is available. You can build the component from source.

            Top functions reviewed by kandi - BETA

            kandi has reviewed Roster and discovered the below as its top functions. This is intended to give you an instant insight into Roster implemented functionality, and help decide if they suit your requirements.
            • Group by family .
            • Add a uuid field .
            • Generate the index .
            • Lookup the latest family for a given fingerprint .
            • Return the diversity badge for the given fingerprint .
            • Groups by AS org_id
            • Checks to see if the onionoo has the given fingerprint .
            • Records the port stats
            • Records country stats .
            • Aggregate a list of Relays .
            Get all kandi verified functions for this library.

            Roster Key Features

            No Key Features are available at this moment for Roster.

            Roster Examples and Code Snippets

            No Code Snippets are available at this moment for Roster.

            Community Discussions

            QUESTION

            Writing to Excel file in Python
            Asked 2021-Jun-14 at 07:09
            import pandas as pd
            import openpyxl
            
            filename="Tests.xlsx"
            
            def createWorkBook():
                wrkbk = openpyxl.Workbook()
                ws = wrkbk.active
                Sheets=["Rostered Patient","Non-Rostered Patient","Email","Error Handling"]
                for sheet in Sheets:
                    if not sheet in wrkbk.sheetnames:
                        print("Created sheet: "+ sheet)
                        wrkbk.create_sheet(sheet)
                wrkbk.save(filename)
            
            def main():
                Columns=[[""],["ID","Testing Procedure:","Pass/Fail","Issue#","Date"],[""],[""],[""]]
            
                createWorkBook()
            xl_writer = pd.ExcelWriter(filename, engine='openpyxl')
                df = pd.DataFrame([["1","2","3","4","5",'6','7','8']],columns = Columns[1])
                df.to_excel(xl_writer, 'Rostered Patient', index=False, startcol=1, startrow=1)
            
            if __name__ == "__main__":
                main()
            
            ...

            ANSWER

            Answered 2021-Jun-14 at 06:23

            you have to save writer after assigning changes.

            use xl_writer.save() at the end of main().

            Source https://stackoverflow.com/questions/67965468

            QUESTION

            why my Rust program always enters while loop and never exits
            Asked 2021-Jun-11 at 18:37

            I am reading through the Rust book and doing the optinal exercise along the way. I've finished the chapter 8 (Common Collections) and am trying the last exercise. The exercise instructions are:

            Using a hash map and vectors, create a text interface to allow a user to add employee names to a department in a company. For example, “Add Sally to Engineering” or “Add Amir to Sales.” Then let the user retrieve a list of all people in a department or all people in the company by department, sorted alphabetically.

            What I want my program to do is firstly ask the user if they want to add a new employee, if no, the program ends else it allows them to continously add an employee until the user declines to add any more.

            I've chosen to simply start with the initial user prompt asking if they want to add a new employee. I start with an empty String for the user input, once the user enters their response there is a while loop that repeats until the user enters a valid response ([Y/n]). Since the condition for the while loop is when the response is not equal to "y" or "n" I expected correct responses to skip the while loop but instead the while loop is always entered and never exited no matter what. Since I'm new to Rust I'm not sure if there some obvious or idiosyncratic reason for this behaviour. I'll also add that I remove whitespace (incl. \n) from the response and make the response lowercase in the while loop condition, all of which can be seen in my code below.

            ...

            ANSWER

            Answered 2021-Jun-11 at 18:34

            Check your while conditions (it is always true) , and what you wrote

            "loop is when the response is not equal to "y" or "n""

            means in pseudo code

            NOT (answer = "y" OR answer="n")

            Source https://stackoverflow.com/questions/67941893

            QUESTION

            My C++ program crashed whenever I try to read the string
            Asked 2021-Jun-10 at 03:11

            Here my code:

            ...

            ANSWER

            Answered 2021-Jun-10 at 03:11

            Please don't mind the prints to user I've introduced here. The execution flow is just so much more clear with them.

            So, you should look toward the following:

            Source https://stackoverflow.com/questions/67913986

            QUESTION

            I am stuck with this struct in C++
            Asked 2021-Jun-09 at 18:20

            I am currently learning "struct" in C++ and stuck at this:

            ...

            ANSWER

            Answered 2021-Jun-09 at 18:20

            The problem is that gets(temp.name) does not allocate memory for the string for you, it expects temp.name to already point to allocated storage. However, temp.name was never initialized, at best your program will crash trying to read the name, at worst it will seem to work but will overwrite memory that will cause problems later. Even if you provide it with a buffer, gets() doesn't know how big your buffer is and will happily write past the end of the buffer it the line it tries to read is long enough. This is why gets() is a deprecated function that has been removed since C11, and my compiler won't even compile your code.

            To read in a line, either use the POSIX function getline(), which is not standard C or C++, or use C++'s std::getline() function. However, the latter requires you to read into a std::string, not into a char *.

            Finally, as Thomas Matthews mentioned in the comments, don't mix C++'s I/O functions with C I/O functions, so std::getline() is the way to go.

            Source https://stackoverflow.com/questions/67909125

            QUESTION

            Formula only recognizes one submission
            Asked 2021-Jun-07 at 06:10

            My goal is to make it so that the spreadsheet checks to see if the respective Web ID in Column B has an Active LOA as determined in Column I. An Active LOA being defined as one with an end date that has NOT yet passed.

            I've gotten the formulas to work with the first entry. But if that first entry's date has passed (marked as Expired) and the entry after that one hasn't passed (marked as Active LOA) then the formula breaks down. It's as if the formula works only once.

            The formula that checks the respective Web ID's in Column B of the "Roster" tab against the Web ID in the "ScD LOA Responses" tab is in cell F9 of the "Roster" tab.

            The formula that determines whether or not the date has passed/whether the person is still on LOA is found in column I of the respective row.

            ...

            ANSWER

            Answered 2021-Jun-07 at 06:10

            You are getting wrong result on second row because you have lock the range on first row, change it as following should work properly:

            Source https://stackoverflow.com/questions/67865197

            QUESTION

            How do I prepend to the beginning of a string in Python using re.sub()?
            Asked 2021-May-31 at 20:56

            I'm using RegEx in Python to search through a text file for occurrences of names in a roster, and then append a "!" character to the start of the string. For example:

            roster = ["name1," "name2," "name3"]

            Original String = "name1 went home."

            Output String - "!name1 went home."

            I found this thread on how to append to the end of the string, which I used successfully for that purpose. I've tinkered with RegEx to append at the start of the string, but with no success. My attempt is below - any recommendations?

            ...

            ANSWER

            Answered 2021-May-31 at 20:56

            Take out the .*s -- matching too much data makes your logic more complicated than it should be for no good reason. Your regex doesn't need to be anchored, and you don't need re.MULTILINE here (since no individual match will ever span multiple lines).

            Source https://stackoverflow.com/questions/67779558

            QUESTION

            How to delete nested JSON attribute in dynamodb / python
            Asked 2021-May-28 at 08:25

            I have a simple dynamodb database that uses "League" as a partition key and "Team" as a sort key to store all roster data under a "Players" attribute field that uses a JSON format. I would like to access and delete a specific player (Larry Bird or Jayson Tatum in this case), however, I am having trouble accessing the schema correctly to delete the specific key and values, especially given that Players.Jayson Tatum wont work because it is two separate words. Here is the basic skeleton code for the function so far:

            ...

            ANSWER

            Answered 2021-May-28 at 08:25

            Removing a nested item in DynamoDB can be done by using the REMOVE-expression in the update_item-method:

            Source https://stackoverflow.com/questions/67712929

            QUESTION

            How to set the data from db to the reducer initial state?
            Asked 2021-May-24 at 09:53

            I have a functional component that requires receiving parameter (i.e. props.rosterMonth) from the parent component and then retrieving data from the database, finally pass the result to the children component.

            My problem is, how to set the initial state for the children component?

            ...

            ANSWER

            Answered 2021-May-10 at 03:14

            The data from the database will always be delayed because it has to be retrieved via that API call from the server, (unless you are doing server side rendering). So you have to deal with the fact that at the beginning you don't have a rosterlist..

            What I would do in this case is check if contextvalue.rosterList is defined and if it's not display a nice loading spinner to the user, something like this:

            Source https://stackoverflow.com/questions/67464212

            QUESTION

            error CS0103: The name does not exist in the current context; system doesn't recognize that my list
            Asked 2021-May-10 at 08:31

            This is for an assignment in my object oriented programming class.

            I am a beginner, especially with this language, so a lot of things could be wrong with this code.

            For now, I am focusing on the error it keeps giving me when I run it: error CS0103: "The name `StudentList' does not exist in the current context."

            I thought that by making my list public, this issue wouldn't occur.

            It gives this error for every object that I try to add to the list in MainClass. This is my first time using lists in C#. Am I missing something pretty obvious? How do I fix this?

            ...

            ANSWER

            Answered 2021-May-09 at 17:02

            you try to access StudentList in MainClass but your list declaration public List StudentList = new List(); is in the different class.

            Try this:

            Source https://stackoverflow.com/questions/67460124

            QUESTION

            Why isn't my method printing what I want it to whenever I call it?
            Asked 2021-May-10 at 01:55

            I am very much a beginner at C# and for some reason, my method is not doing what I want it to.

            The method I am referring to is the Roll() method. I want it to print the class name and all of the students in the class list whenever I call the method. It doesn't do any of that. All it does is print "Roster:", leaving out the things I want it to print. Am I missing something? How can I fix this?

            ...

            ANSWER

            Answered 2021-May-10 at 01:55

            Here is code that work:

            Source https://stackoverflow.com/questions/67463634

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Roster

            You can download it from GitHub.
            You can use Roster like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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          • HTTPS

            https://github.com/seansaito/Roster.git

          • CLI

            gh repo clone seansaito/Roster

          • sshUrl

            git@github.com:seansaito/Roster.git

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