nprime | :100 : Prime numbers algorithms in Python | Math library
kandi X-RAY | nprime Summary
kandi X-RAY | nprime Summary
Some algorithm on prime numbers. You can find all the functions in the file nprime/pryprime.py.
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nprime Key Features
nprime Examples and Code Snippets
Lines of Code : 5License : Strong Copyleft (GPL-3.0)
Copyfrom nprime import sieve_eratosthenes
# With as a parameter the upper limit
sieve_eratosthenes(10)
>> {2: [4, 6, 8, 10], 3: [9], 5: [], 7: []}
from nprime import fermat
# With n the number you want to test
fermat(n)
a^(n-1) ≡ 1 (mod n) ⇔ a^(n-1) = kn + 1
from nprime import miller_rabin
# With n the number you want to test
miller_rabin(n)
Community Discussions
Trending Discussions on nprime
QUESTION
I have a function that It has to be in size_t* type. When all size_t types are declared as integers, all it works perfect. When I change the decleration to size_t it doesn't run with this fail Aborted (core dumped). If i change all size_t* to int no problem happens.
That's the function:
...ANSWER
Answered 2020-Nov-09 at 08:19Consider your lines
QUESTION
I want to iterate through a list in python, detect prime numbers and then add them to another list.
...ANSWER
Answered 2020-Jun-20 at 15:39If num % k == 0 is false you can't say it's prime directly you have to wait the whole loop, so move the else with the for loop, it'll be executed of no break has been encountered which means it's prime
- you may iterate directly on the values
for num in arr - you can stop your loop at
sqrt(num)you won't find a new divisor after that
QUESTION
I have recently started to learn c and as a programming exercise, I've written a program that computes and lists out prime numbers from 0 up to a maximum entered by the user. It's a rather short program so I'll post the source code here.
...ANSWER
Answered 2019-Dec-07 at 16:49I can give you two main ideas as I have worked on a project discussing this problem.
- A prime number bigger than 3 is either
6k-1or6k+1, so for example 183 can't be prime because183=6x30+3, so you don't even have to check it. (Be careful, this condition is necessary but not sufficient,25for exemple is6x4+1but is not prime) - A number is prime if it can't be divided by any prime number smaller or equal to its root, so it's preferable to take a benefit out of the smaller primes you already found.
Thus, you can start with a primesList containing 2 and 3, and iterate k to test all the 6k-1 and 6k+1 numbers (5, 7, 11, 13, 17, 19, 23, 25...) using the second rule I gave you, by using division on elements in the primesList which are smaller than or equal to the root of the number you are checking, if you found only one element dividing it, you just stop and pass to another element, 'cause this one is not prime, otherwise (if no one can divide it): update the primesList by adding this new prime number.
QUESTION
I'm new to C++ and trying to make this piece of code work properly. It's a basic algorithm for prime numbers. I make an array the size of which is defined by the user input. Then I need to print only the max prime number from this array. How can I do that here?
...ANSWER
Answered 2019-Nov-22 at 09:52As it seems you mark non-prime numbers with value 0 in the array. We know that primes are positive numbers, to simplify, let maxNum be -1. Then I added one for at the and of the function which will calculate the maximum prime value in the array. This is the one way to do :
QUESTION
I made this program to find prime factors of a number, but when i am running this code it's giving the wrong output. I have debugged this code and also the logic is correct. what i found is that, when "x == 1" the the program misbehaves. I am not able to find the answer.
...ANSWER
Answered 2019-Nov-16 at 14:30You should break from your loop once you find the first divisor. Otherwise, your outer method call will continue searching for divisors of your x even though it's no longer needed:
QUESTION
I'm required to code a program that, using a do-while loop, will print 25 prime numbers on a new line. I have everything figured out on it, except for printing out exactly 25 numbers. However, the program is only giving me prime numbers up to the number 25, not 25 prime numbers.
I set a variable "count" to increase every time the loop is run, with the same result. Here's my code (sorry for the length, I would shorten it but I'm worried the whole thing might be messed up):
...ANSWER
Answered 2019-Oct-01 at 03:35Here's an example showing how you can iterate through some loop a fixed number of times, and separately calculate your next prime number. I'm clearly not calculating any primes here, just showing how you can separate the two concerns of "loop quantity" and "determine the next prime".
QUESTION
There are many implementations of the Sieve of Eratosthenes online. Through searching Google, I found this implementation in C.
...ANSWER
Answered 2019-Mar-03 at 05:11You have some problem with your loop statement, j variable should use for index of primes that is pointer to array of int with 0 or 1 values. You can use primes array in this case is S(k) in algorithm.
QUESTION
I'm writing a short snippet for a class that is supposed to run through a given list of numbers and append any primes. Right now it is returning all numbers in the range though.
I've found examples online for how to do this, but wanted to try it myself but I've seem to hit a wall... Here is my code:
...ANSWER
Answered 2018-Nov-11 at 06:26Checking if the result of a modulo operation is 1 is not the correct approach. For example, 6 % 5 is 1, but 6 definitely isn't a prime number. Instead, for each suspect N you should check that no number X exists such that N % X == 0.
A wildly sub-optimal implementation could look like this:
QUESTION
I'm a complete beginner to programming so forgive me for my naivete.
I wanted to make a program in Python that lets me print a given N number of prime numbers, where N is inputted by the user. I searched a little on "for/while" loops and did some tinkering. I ran a program I saw online and modified it to suit the problem. Here is the code:
ANSWER
Answered 2018-Sep-05 at 13:31c in this case is used to count the number of numbers that divide evenly into i.
for example, if i = 8: 8 is divisible by 1, 2, 4, and 8. so c = 4 since there are 4 things that divide evenly into it
if i = 5: 5 is divisible by 1 and 5. so c = 2 since there are 2 numbers that divide evenly into it
if i = 4 (where you seem to be confused): 4 is divisible by 1, 2, and 4. so c = 3, not 2.
QUESTION
Sorry if the question seems really trivial but I'm just learning how to code and this one kept me in front of the computer for about 2 hours without getting to realize why this happens.
I'll pass the code below. So, in order to keep it straightforward:
isPrime() is a function that just checks if a current number is Prime or not.
nPrime() is a function that returns the n-ism prime number, given N as the parameter.
The key point here is the main function and, more precisely, the number value in the first while-loop.
If you run this code, when it reaches the last prime number by which number is divisible, it'll enter an infinite loop. This can be easily solved if you just change the first while condition from while(number > 0) to while(number > 1).
That's the weird thing I can't come to realize: If the inner second while-loop won't exit as long as number % nPrime(index) != 0 and the last instruction of the outter first while-loop is number /= nPrime(index);, how come the program enters an infinite loop?
That last instruction set number's value to 0, so the first while-loop condition should return false and exit the loop.
What am I missing?
Thank you all for your time and patience.
PS: I got downvoted and I don't know why, so I'll make an clarification:
I've done the research. As far as I know, every source seems to agree on the same point:
the > condition returns true if and only if left operand is greater than right operand.
Which takes me to the previously written question: if number is equal to 0, how's the while-loop not evaluating the number > 0 as false and exiting from the iteration?
...ANSWER
Answered 2018-Feb-03 at 21:10What am I missing?
That last instruction set number's value to 0
No it doesn't, it never gets that far. When number equals one then number % nPrime(index) != 0 is always true, so the inner while loop never exits.
Your understanding of while loops is perfect, it's your understanding of what your own code does that is in error. This is normal for bugs like this.
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