venice | Ruby Gem for In-App Purchase Receipt Verification | iOS library

by nomad Ruby Version: Current License: MIT

X-Ray Key Features Code Snippets(1)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | venice Summary

venice is a Ruby library typically used in Mobile, iOS applications. venice has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Note: This project is no longer being maintained. Venice is a simple gem for verifying Apple In-App Purchase receipts, and retrieving the information associated with receipt data. There are two reasons why you should verify in-app purchase receipts on the server: First, it allows you to keep your own records of past purchases, which is useful for up-to-the-minute metrics and historical analysis. Second, server-side verification over SSL is the most reliable way to determine the authenticity of purchasing records. See Apple's Receipt Validation Programming Guide for additional information. Venice is named for Venice, Italy—or more specifically, Shakespeare's The Merchant of Venice. It's part of a series of world-class command-line utilities for iOS development, which includes Cupertino (Apple Dev Center management), Shenzhen (Building & Distribution), Houston (Push Notifications), Dubai (Passbook pass generation), and Nashville (iTunes Store API).

Support

Quality

Security

License

Reuse

Support

venice has a low active ecosystem.

It has 586 star(s) with 139 fork(s). There are 22 watchers for this library.

It had no major release in the last 6 months.

There are 0 open issues and 26 have been closed. On average issues are closed in 359 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of venice is current.

Quality

venice has 0 bugs and 5 code smells.

Security

venice has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

venice code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

venice is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

venice releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

venice saves you 332 person hours of effort in developing the same functionality from scratch.

It has 797 lines of code, 26 functions and 12 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed venice and discovered the below as its top functions. This is intended to give you an instant insight into venice implemented functionality, and help decide if they suit your requirements.

This method is used for verification
Hash representation of the application .
Verify that the data is valid
Checks if the development environment is configured
Check if the given string is a string

Get all kandi verified functions for this library.

venice Key Features

No Key Features are available at this moment for venice.

venice Examples and Code Snippets

r Calculate lamber distance between two points .

python

Lines of Code : 75

License : Permissive (MIT License)

Copy

def lamberts_ellipsoidal_distance(
    lat1: float, lon1: float, lat2: float, lon2: float
) -> float:

    """
    Calculate the shortest distance along the surface of an ellipsoid between
    two points on the surface of earth given longitudes an

Community Discussions

Trending Discussions on venice

"for" loop for functions

Bootstrap Carousel Toggleable / Dynamic Tabs

How to insert user selected value from datalist dropdown into a template string to be shown as a message to the user when submitted?

How to get the doc that have max date value in elasticsearch index

Unable To Format String - Python

Column count doesn't match value count at row 1 - MySQL

Python Pandas groupby multiple columns and append

Python - Best way to detect accent HTML escape in a string?

Expected behavior FactoryBot

Arithmetic operations on row level in pandas dataframe

QUESTION

"for" loop for functions

Asked 2021-Apr-26 at 20:39

I have the following dataset with +7000 cities, divided by 21 age classes group. The columns are "City" "City Code" (unique) "Age Class" "N" and "D". I have to apply two functions for every city. I was wondering if it's possible to write a for loop to do that automatically.

The dataset is the following:

...

ANSWER

Answered 2021-Apr-26 at 20:36

This demonstrates it. The for-loop cycles through the cities. You get the list of cities with unique(TotalDf[["City"]]). The code is commented and explains itself (I hope).

Please note: in order to make it executable I had to mock some variables and functions.

Source https://stackoverflow.com/questions/67269642

QUESTION

Bootstrap Carousel Toggleable / Dynamic Tabs

Asked 2021-Mar-10 at 20:40

i try to do in every tab an Picture Gallery (Home, Menu1, Menu2, Menu3) , in the first tab it works but in the other tab(Menu1) it won´t work. It start the gallery but cant switch with the selektor icons. Have anybody an idea? .

...

ANSWER

Answered 2021-Mar-10 at 20:40

You have added same id on both careousel selector that's why it wasn't working in another tab. here is the working solution:

Source https://stackoverflow.com/questions/66571765

QUESTION

How to insert user selected value from datalist dropdown into a template string to be shown as a message to the user when submitted?

Asked 2021-Mar-10 at 11:27

I have 2 datalists in the form below. I'm trying to get selected variable values (let input1 & let input2) to show in the message that appears when submitted via template string variable let message but it's not working. I'm not getting any errors.

Any idea why it does not work? And can event listeners be simplified so that I don't have to write out a new variable for each one since I have 4 datalists?

...

ANSWER

Answered 2021-Mar-10 at 11:27

The way you capture your input values is wrong. This will work.

Source https://stackoverflow.com/questions/66561454

QUESTION

How to get the doc that have max date value in elasticsearch index

Asked 2021-Feb-02 at 07:33

Imagine that I have some docs like below:

...

ANSWER

Answered 2021-Feb-02 at 07:31

{
  "size": 1,
  "query": {
    "bool": {
      "must": [
        {
          "match": {
            "person": {
              "query": "Ahmet"
            }
          }
        }
      ]
    }
  },
  "sort": [
    {
      "p_date": "desc"
    }
  ]
}

Source https://stackoverflow.com/questions/66005047

QUESTION

Unable To Format String - Python

Asked 2021-Jan-18 at 00:21

I'm unable to format this string, why is this?

...

ANSWER

Answered 2021-Jan-17 at 17:37

It should either be like:

Source https://stackoverflow.com/questions/65763849

QUESTION

Column count doesn't match value count at row 1 - MySQL

Asked 2020-Dec-22 at 16:53

So I created a table name locations:

create table locations (

...

ANSWER

Answered 2020-Dec-22 at 16:53

When inserting data into a MySQL table, you will have to specify which data goes into which column. You do this by specifying the column names before the VALUES part like:

Source https://stackoverflow.com/questions/65412498

QUESTION

Python Pandas groupby multiple columns and append

Asked 2020-Dec-18 at 10:21

I'm close to achieve what I want thanks to Python Pandas Groupby/Append columns but still not quite there.

DF:

City Plan Problem 1 Problem 2 Problem 3 Genoa Service 1 aaa bbb ccc Genoa Service 2 ddd zzz yyy Genoa Service 3 ggg ppp jjj Venice Service 2 lll vvv Venice Service 3 eee fff mmm

Expected Output:

City Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Genoa aaa bbb ccc ddd zzz yyy ggg ppp jjj Venice lll vvv eee fff mmm

Basically I want to:

Group by City
Discard Plan Column (if possible)
Append all the other parameters (They still need to be always in order, so if a service is missing the cells would be empty.

After playing a while with unstack and cumcount from the linked solution, I'm still missing something to respect the order of the Plan column and fill with empty cells if a service is missing.

This is the code I'm using:

...

ANSWER

Answered 2020-Dec-18 at 10:12

This is a pivot problem, but you can also do this by stacking and unstacking:

Source https://stackoverflow.com/questions/65355008

QUESTION

Python - Best way to detect accent HTML escape in a string?

Asked 2020-Nov-29 at 19:53

Python has some good libraries to convert Unicode accent characters to its closest Ascii character, as well as libraries to encode codepoint to its Unicode character.

However, what options are there to check whether a string has unicode codepoint or HTML escape? For example, this string:

Rialta te VeniceÇ

Has the Ç, which translates to a latin capital letter C. Is there a python library that detects codepoints/escape within a string and outputs the Unicode equivalent?

...

ANSWER

Answered 2020-Nov-29 at 19:37

It's not quite clear to me what you're asking, but here is my best try:

Ç is an HTML escape, which you can unescape like so:

Source https://stackoverflow.com/questions/65063318

QUESTION

Expected behavior FactoryBot

Asked 2020-Nov-19 at 10:45

I'm testing a rake task - update_city_status_for_users:

...

ANSWER

Answered 2020-Nov-19 at 10:45

Rails caches the model instances to avoid repetitive database queries. You'll need to call

Source https://stackoverflow.com/questions/64908406

QUESTION

Arithmetic operations on row level in pandas dataframe

Asked 2020-Nov-04 at 20:12

I have a dataframe as below:

...

ANSWER

Answered 2020-Nov-04 at 20:12

Try with this

Source https://stackoverflow.com/questions/64685175

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install venice

You can download it from GitHub.
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: