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All Algorithms implemented in Rust
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QUESTION
First, I tried something like this:
...ANSWER
Answered 2022-Apr-12 at 00:43It is definitely an interesting one.
They are similar - but not quite the same. resize()
is a member of Vec
. rotate_right()
, on the other hand, is a method of slices.
Vec
derefs to [T]
, so most of the time this does not matter. But actually, while this call:
QUESTION
When trying to run the command using nextjs npm run dev shows error - failed to load SWC binary see more info here: https://nextjs.org/docs/messages/failed-loading-swc.
I've tried uninstalling node and reinstalling it again with version 16.13 but without success, on the vercel page, but unsuccessful so far. Any tips?
Also, I noticed it's a current issue on NextJS discussion page and it has to do with the new Rust-base compiler which is faster than Babel.
...ANSWER
Answered 2021-Nov-20 at 13:57This worked as suggeted by nextJS docs but it takes away Rust compiler and all its benefits... Here is what I did for those who eventually get stuck...
Step 1. add this line or edit next.json.js
QUESTION
In the current stable Rust, is there a way to write a function equivalent to BTreeMap::pop_last?
The best I could come up with is:
...ANSWER
Answered 2022-Mar-15 at 16:55Is there a way to work around this issue without imposing additional constraints on map key and value types?
It doesn't appear doable in safe Rust, at least not with reasonable algorithmic complexity. (See Aiden4's answer for a solution that does it by re-building the whole map.)
But if you're allowed to use unsafe, and if you're determined enough that you want to delve into it, this code could do it:
QUESTION
Consider following code
...ANSWER
Answered 2022-Mar-03 at 21:14You are correct, this is due to match ergonomics. The first case should hopefully be self explanatory, but the second and third cases can be a bit counter-intuitive.
In the second case:
(x,)
is a non-reference pattern (see the second example in the RFC). Thet
tuple reference is dereferenced, andx
is bound as aref
as it also is a non-reference pattern. Note thatt.0
was a reference to begin with, thus resulting inx
being a double reference.(&y,)
is also a non-reference pattern. Thet
tuple is dereferenced again to a(&i32,)
. However,&y
is a reference pattern being matched to a&i32
reference. Hencey
is bound withmove
mode and is ani32
.
In the third case:
Using the same reasoning as the second case,
u
is dereferenced viaDeref
coercion to an(i32,)
, andx
, a non-reference pattern, is bound inref
mode. Hencex
is an&i32
.Again with the same reasoning as the second case,
u
is dereferenced to an(i32,)
. The&y
reference pattern is then matched to ani32
, a non-reference, which causes an error.
QUESTION
I have been using the #[tokio::main]
macro in one of my programs. After importing main
and using it unqualified, I encountered an unexpected error.
ANSWER
Answered 2022-Feb-15 at 23:57#[main]
is an old, unstable attribute that was mostly removed from the language in 1.53.0. However, the removal missed one line, with the result you see: the attribute had no effect, but it could be used on stable Rust without an error, and conflicted with imported attributes named main
. This was a bug, not intended behaviour. It has been fixed as of nightly-2022-02-10
and 1.59.0-beta.8
. Your example with use tokio::main;
and #[main]
can now run without error.
Before it was removed, the unstable #[main]
was used to specify the entry point of a program. Alex Crichton described the behaviour of it and related attributes in a 2016 comment on GitHub:
Ah yes, we've got three entry points. I.. think this is how they work:
- First,
#[start]
, the receiver ofint argc
andchar **argv
. This is literally the symbolmain
(or what is called by that symbol generated in the compiler).- Next, there's
#[lang = "start"]
. If no#[start]
exists in the crate graph then the compiler generates amain
function that calls this. This functions receives argc/argv along with a third argument that is a function pointer to the#[main]
function (defined below). Importantly,#[lang = "start"]
can be located in a library. For example it's located in the standard library (libstd).- Finally,
#[main]
, the main function for an executable. This is passed no arguments and is called by#[lang = "start"]
(if it decides to). The standard library uses this to initialize itself and then call the Rust program. This, if not specified, defaults tofn main
at the top.So to answer your question, this isn't the same as
#[start]
. To answer your other (possibly not yet asked) question, yes we have too many entry points.
QUESTION
According to doc.rust-lang.org
build[s] a package's documentation, using specified custom flags
build[s] a package's documentation
What is the difference between the two? From what I understand cargo rustdoc
is just like cargo doc
, but it allows for more lints—for instance:
ANSWER
Answered 2022-Jan-11 at 21:00Their relationship is like between cargo build
and cargo rustc
: cargo doc
performs all the usual work, for an entire workspace, including dependencies (by default). cargo rustdoc
allows you to pass flags directly to rustdoc, and only works for a single crate.
Here is the execution code for cargo rustdoc
. Here is the code for cargo doc
. The only differences is that cargo rustdoc
always specify to not check dependencies while cargo doc
allows you to choose (by default it does, but you can specify the flag --no-deps
), and that cargo rustc
allows you to pass flags directly to rustdoc with the flags after the --
.
QUESTION
I want to run an example via Cargo but I am facing an error:
...ANSWER
Answered 2021-Dec-14 at 14:09Update the Rust to satisfy the new edition 2021.
rustup default nightly && rustup update
Thanks to @ken.
Yes, you can use the stable
channel too!
But I love nightly
personally.
QUESTION
Is there a more idiomatic way to express something like the following?
...ANSWER
Answered 2022-Jan-27 at 07:32There are many ways to do it. One of the simplest (and arguably most readable) is something like this:
QUESTION
I'm trying to adapt some layers of existing C++ code to be used by Rust and apparently the way is through a C API.
For example, one function might return a struct as an object
...ANSWER
Answered 2022-Jan-21 at 01:15extern "C"
on both sides + #[repr(C)]
on the Rust side + only using C-compatible types for interfacing between C++ and Rust, should work.
QUESTION
These two loops are equivalent in C++ and Rust:
...ANSWER
Answered 2022-Jan-12 at 10:20Overflow in the iterator state.
The C++ version will loop forever when given a large enough input:
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