ureq | A simple , safe HTTP client | HTTP library

 by   algesten Rust Version: 2.6.2 License: Apache-2.0

kandi X-RAY | ureq Summary

kandi X-RAY | ureq Summary

ureq is a Rust library typically used in Networking, HTTP applications. ureq has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

A simple, safe HTTP client. Ureq's first priority is being easy for you to use. It's great for anyone who wants a low-overhead HTTP client that just gets the job done. Works very well with HTTP APIs. Its features include cookies, JSON, HTTP proxies, HTTPS, and charset decoding. Ureq is in pure Rust for safety and ease of understanding. It avoids using unsafe directly. It uses blocking I/O instead of async I/O, because that keeps the API simple and and keeps dependencies to a minimum. For TLS, ureq uses rustls or native-tls. Version 2.0.0 was released recently and changed some APIs. See the changelog for details.
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            kandi-support Support

              ureq has a medium active ecosystem.
              It has 1316 star(s) with 124 fork(s). There are 9 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 53 open issues and 169 have been closed. On average issues are closed in 59 days. There are 16 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of ureq is 2.6.2

            kandi-Quality Quality

              ureq has 0 bugs and 0 code smells.

            kandi-Security Security

              ureq has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              ureq code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              ureq is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              ureq releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            ureq Key Features

            No Key Features are available at this moment for ureq.

            ureq Examples and Code Snippets

            No Code Snippets are available at this moment for ureq.

            Community Discussions

            QUESTION

            How to merge two lines of results in .csv file in Python (BeautifulSoup)
            Asked 2022-Mar-11 at 13:20

            I am trying to get data from one website, but I have difficulties on how to handle "Index is out of range" error or having results in two separate lines in .csv file. What I mean by the error "Index is out of range" is that it is possible on this site to have empty values on some records and I don't know how to put the correct condition in loop. I used some guides but it took me to nowhere.

            ...

            ANSWER

            Answered 2022-Mar-11 at 12:51

            Need to slightly alter your logic here. What I would do is instead of getting each container as the product name and then the product info, grab the whole container that contains all the info. You'll notice that each product is in a

          • tag, under the
              tag.

              So lets first grab the the

                tag that has a class that starts with 'products'. Then from there get all the
              • tags. Then we'll iterate through each of those and pull out the data needed.

                As you stated, some of the tags aren't present, so we'll do a try/except. It'll try to get the data, if it fails, it'll default to the except exception.

                Also, pandas is a really good and useful library to use/learn. So I went with that, as opposed to writing to csv file as you had it.

                Code:

          • Source https://stackoverflow.com/questions/71438112

            QUESTION

            Python - Get a list of URLs from a complicated html file for scraping purposes
            Asked 2021-Dec-16 at 09:20

            I am new to web scraping and could not get the list of URLs in the 'a' tags from this website: http://www.tauntondevelopment.org//msip/JHRindex.htm. All I get is an empty list- clients list: [] Thank you for your help!

            Here is my code:

            ...

            ANSWER

            Answered 2021-Dec-16 at 00:29

            In your code you're trying to get the href attribute from the li elements themselves. Actually the li element has a nested p with a nested b which has a nested inside, you need to get that nested a.

            Here is a suggestion:

            Source https://stackoverflow.com/questions/70371863

            QUESTION

            Is there a method/way to save text data into csv columns with the right formatting as requested?
            Asked 2021-Dec-01 at 19:31

            I need help on this script that will automatically scrape the web and save selected variables as a result. This is the result that I would like to have.

            Collection Homesites Bedrooms Price Range Mosaic 292 2 -3 $557,990 - $ 676,990 Legends 267 2 - 3 $673,990 - $788,990 Estates 170 2 - 3 $863,990 - $888,990

            This is the code that I already have. I was able to save 'collections' in the first column but I am not being able to save the numbers into the rest of the columns (not in the right place). I need help with write the result to the csv file in the correct formatting and the right place which is underneath the headers. Thank you!

            ...

            ANSWER

            Answered 2021-Oct-27 at 18:42

            This could be a solution for you:

            Source https://stackoverflow.com/questions/69743379

            QUESTION

            Python Web scraping | How to handle missing elements using try and except so that it prints as Not available if element not is found?
            Asked 2021-Nov-26 at 05:57
            from bs4 import BeautifulSoup as soup
            
            from urllib.request import urlopen as uReq
            
            import bs4
            
            headers = {'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Brave Chrome/83.0.4103.116 Safari/537.36'}
            
            my_url = 'https://www.jiomart.com/c/groceries/dairy-bakery/dairy/62'
            
            
            
            uclient = uReq(my_url)
            
            page_html = uclient.read()
            
            uclient.close()
            
            
            bs41 = soup(page_html, 'html.parser')
            
            
            containers = bs41.find_all('div', {'col-md-3 p-0'})
            #print(len(containers))
            
            
            #print(soup.prettify(containers[0]))
            
            
            
            for container in containers:
                p_name = container.find_all('span', {'class' : 'clsgetname'})
                productname = p_name[0].text
            
                o_p = container.find_all('span' , id = 'final_price' )
                offer_price = o_p[0].text
            
            
                try:
                    ap = container.find_all('strike', id = 'price')
                    actual_price = ap[0].text
            
                except:
                    print('not available')
            
                
            
                print('Product name is', productname)
                print('Product Mrp is', offer_price)
                print('Product actual price', actual_price)
                
                
                print()
            
            
               
            
            ...

            ANSWER

            Answered 2021-Aug-13 at 07:48

            The issue is that even if it does not find the element, it still prints actual_price which is probably in an outer scope.

            You have 2 ways to approach this.

            • The 1st is to only print if the element was found, for which you can do:

            Source https://stackoverflow.com/questions/68768541

            QUESTION

            python scrape site with multiple pages
            Asked 2021-Sep-26 at 17:51

            Hey how can I change this code to enter each page and get the info from this url I want ( the book name and the url of the book )

            i wrote ( with google help ) this code but i want to get all the books from all the pages ( 50 pages )

            ...

            ANSWER

            Answered 2021-Sep-26 at 12:33

            This might work. I have removed uReq because I prefer using requests ;)

            Source https://stackoverflow.com/questions/69334913

            QUESTION

            How to extract text from inside div tag using BeautifulSoup
            Asked 2021-Sep-21 at 11:54

            Im trying to get the numbers from inside the div tag from the following html content

            47,864.58$47,864.58

            What I need is

            $47,864.5

            Ive tried multiple ways of trying to extract this but i either keep getting errors or it returns an empty list as [] or none in the output This is my code

            ...

            ANSWER

            Answered 2021-Sep-17 at 08:31

            Updated:

            What you can do price can be fetch from script tag which reflect in title of the page but it is static not dynamic

            Code:

            Source https://stackoverflow.com/questions/69219856

            QUESTION

            How do I idiomatically unwrap Rust errors with functions rather than closures?
            Asked 2021-Sep-04 at 18:55

            I'm struggling with error handling cleanly in Rust. Say I have a function that is propogating multiple error types with Box. To unwrap and handle the error, I'm doing the following:

            ...

            ANSWER

            Answered 2021-Sep-04 at 18:55

            As pointed out by @kmdreko, your code fails to compile because, while ! can be coerced to any T, fn() -> ! cannot be coerced to fn() -> T.

            To work around the above, you can declare fail() to return Value, and actually return the "value" of std::process::exit(1). Omitting the semicolon coerces the ! to Value, and you don't have to cheat with a Value::Null:

            Source https://stackoverflow.com/questions/69050068

            QUESTION

            Scraping PDFs from multiple pages using bs4
            Asked 2021-Aug-18 at 08:11

            I'm a python beginner and I'm hoping that what I'm trying to do isn't too involved. Essentially, I want to extract the text of the minutes (contained in PDF documents) from this municipality's council meetings for the last ~10 years at this website: https://covapp.vancouver.ca/councilMeetingPublic/CouncilMeetings.aspx?SearchType=3

            Eventually, I want to analyze/categorise the action items from the meeting minutes. All I've been able to do so far is grab the links leading to the PDFs from the first page. Here is my code:

            ...

            ANSWER

            Answered 2021-Aug-18 at 08:11

            Welcome to the exciting world of web scraping!

            First of all, great job you were on the good track. There are a few points to discuss though.

            You essentially have 2 problems here.

            1 - How to retrieve the HTML text for all pages (1, ..., 50)?

            In web scraping you have mainly to kind of web pages:

            1. If you are lucky, the page does not render using javascript and you can use only requests to get the page content
            2. You are less lucky, and the page uses JavaScript to render partly or entirely

            To get all the pages from 1 to 50, we need to somehow click on the button next at the end of the page. Why? If you check what happens in the network tab from the browser developer, console, you see that a new query getting a JS script to generate the page is fetched for each click to the next button. Unfortunately, we can't render JavaScript using requests

            But we have a solution: Headless Browsers (wiki).

            In the solution, I use selenium, which is a library that can use a real browser driver (in our case Chrome) to query a page and render JavaScript.

            So we first get the web page with selenium, we extract the HTML, we click on next and wait a bit for the page to load, we extract the HTML, ... and so on.

            2 - How to extract the text from the PDFs after getting them?

            After downloading the PDfs, we can load it into a variable then open it with PyPDF2 and extract the text from all pages. I let you look at the solution code.

            Here is a working solution. It will iterate over the first n pages you want and return the text from all the PDF you are interested in:

            Source https://stackoverflow.com/questions/68777334

            QUESTION

            Python webscraping, need input with formatting and how to access information at an array index
            Asked 2021-Aug-09 at 22:50
            import xml
            
            import bs4
            from urllib.request import urlopen as uReq
            from bs4 import BeautifulSoup as soup
            
            
            my_url = 'https://wwwn.cdc.gov/nchs/nhanes/search/datapage.aspx?Component=Laboratory&CycleBeginYear=2003'
            uClient = uReq(my_url)
            page_html = uClient.read()
            uClient.close()
            page_soup = soup(page_html,'html.parser').findAll('tr')
            
            print(page_soup[2])
            
            ...

            ANSWER

            Answered 2021-Aug-09 at 22:50

            You'll have to treat the individual table columns differently. For some of them you want just the text, for others you want the hrefs.

            Source https://stackoverflow.com/questions/68719259

            QUESTION

            Web-scraping a link from web-page
            Asked 2021-Aug-01 at 19:32

            New to web-scraping here. I basically want to extract a link from a web page into my jupyter notebook as shown in the image below :

            Following is the code that I tried out:

            ...

            ANSWER

            Answered 2021-Aug-01 at 19:06

            Your class filter is not very specific.

            The first and second elements are pointing to html nodes which do not contain the link. Thus you are getting error.

            A more specific class to check could be: _13oc-S

            Source https://stackoverflow.com/questions/68613463

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install ureq

            You can download it from GitHub.
            Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

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            CLONE
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            https://github.com/algesten/ureq.git

          • CLI

            gh repo clone algesten/ureq

          • sshUrl

            git@github.com:algesten/ureq.git

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