ureq | A simple , safe HTTP client | HTTP library
kandi X-RAY | ureq Summary
kandi X-RAY | ureq Summary
A simple, safe HTTP client. Ureq's first priority is being easy for you to use. It's great for anyone who wants a low-overhead HTTP client that just gets the job done. Works very well with HTTP APIs. Its features include cookies, JSON, HTTP proxies, HTTPS, and charset decoding. Ureq is in pure Rust for safety and ease of understanding. It avoids using unsafe directly. It uses blocking I/O instead of async I/O, because that keeps the API simple and and keeps dependencies to a minimum. For TLS, ureq uses rustls or native-tls. Version 2.0.0 was released recently and changed some APIs. See the changelog for details.
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Trending Discussions on ureq
QUESTION
I am trying to get data from one website, but I have difficulties on how to handle "Index is out of range" error or having results in two separate lines in .csv file. What I mean by the error "Index is out of range" is that it is possible on this site to have empty values on some records and I don't know how to put the correct condition in loop. I used some guides but it took me to nowhere.
...ANSWER
Answered 2022-Mar-11 at 12:51Need to slightly alter your logic here. What I would do is instead of getting each container
as the product name and then the product info, grab the whole container that contains all the info. You'll notice that each product is in a
tags. Then we'll iterate through each of those and pull out the data needed.
As you stated, some of the tags aren't present, so we'll do a
try/except
. It'll try to get the data, if it fails, it'll default to theexcept
exception.Also,
pandas
is a really good and useful library to use/learn. So I went with that, as opposed to writing to csv file as you had it.Code:
tag.
So lets first grab the the
- tag that has a class that starts with
'products'
. Then from there get all the
QUESTION
I am new to web scraping and could not get the list of URLs in the 'a' tags from this website: http://www.tauntondevelopment.org//msip/JHRindex.htm. All I get is an empty list- clients list: [] Thank you for your help!
Here is my code:
...ANSWER
Answered 2021-Dec-16 at 00:29In your code you're trying to get the href attribute from the li elements themselves. Actually the li element has a nested p with a nested b which has a nested inside, you need to get that nested a.
Here is a suggestion:
QUESTION
I need help on this script that will automatically scrape the web and save selected variables as a result. This is the result that I would like to have.
Collection Homesites Bedrooms Price Range Mosaic 292 2 -3 $557,990 - $ 676,990 Legends 267 2 - 3 $673,990 - $788,990 Estates 170 2 - 3 $863,990 - $888,990This is the code that I already have. I was able to save 'collections' in the first column but I am not being able to save the numbers into the rest of the columns (not in the right place). I need help with write the result to the csv file in the correct formatting and the right place which is underneath the headers. Thank you!
...ANSWER
Answered 2021-Oct-27 at 18:42This could be a solution for you:
QUESTION
from bs4 import BeautifulSoup as soup
from urllib.request import urlopen as uReq
import bs4
headers = {'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Brave Chrome/83.0.4103.116 Safari/537.36'}
my_url = 'https://www.jiomart.com/c/groceries/dairy-bakery/dairy/62'
uclient = uReq(my_url)
page_html = uclient.read()
uclient.close()
bs41 = soup(page_html, 'html.parser')
containers = bs41.find_all('div', {'col-md-3 p-0'})
#print(len(containers))
#print(soup.prettify(containers[0]))
for container in containers:
p_name = container.find_all('span', {'class' : 'clsgetname'})
productname = p_name[0].text
o_p = container.find_all('span' , id = 'final_price' )
offer_price = o_p[0].text
try:
ap = container.find_all('strike', id = 'price')
actual_price = ap[0].text
except:
print('not available')
print('Product name is', productname)
print('Product Mrp is', offer_price)
print('Product actual price', actual_price)
print()
...ANSWER
Answered 2021-Aug-13 at 07:48The issue is that even if it does not find the element, it still prints actual_price
which is probably in an outer scope.
You have 2 ways to approach this.
- The 1st is to only print if the element was found, for which you can do:
QUESTION
Hey how can I change this code to enter each page and get the info from this url I want ( the book name and the url of the book )
i wrote ( with google help ) this code but i want to get all the books from all the pages ( 50 pages )
...ANSWER
Answered 2021-Sep-26 at 12:33This might work. I have removed uReq
because I prefer using requests ;)
QUESTION
Im trying to get the numbers from inside the div tag from the following html content
47,864.58
$47,864.58
What I need is
$47,864.5
Ive tried multiple ways of trying to extract this but i either keep getting errors or it returns an empty list as [] or none in the output This is my code
...ANSWER
Answered 2021-Sep-17 at 08:31Updated:
What you can do price can be fetch from script tag which reflect in title
of the page but it is static not dynamic
Code:
QUESTION
I'm struggling with error handling cleanly in Rust. Say I have a function that is propogating multiple error types with Box
. To unwrap and handle the error, I'm doing the following:
ANSWER
Answered 2021-Sep-04 at 18:55As pointed out by @kmdreko, your code fails to compile because, while !
can be coerced to any T
, fn() -> !
cannot be coerced to fn() -> T
.
To work around the above, you can declare fail()
to return Value
, and actually return the "value" of std::process::exit(1)
. Omitting the semicolon coerces the !
to Value
, and you don't have to cheat with a Value::Null
:
QUESTION
I'm a python beginner and I'm hoping that what I'm trying to do isn't too involved. Essentially, I want to extract the text of the minutes (contained in PDF documents) from this municipality's council meetings for the last ~10 years at this website: https://covapp.vancouver.ca/councilMeetingPublic/CouncilMeetings.aspx?SearchType=3
Eventually, I want to analyze/categorise the action items from the meeting minutes. All I've been able to do so far is grab the links leading to the PDFs from the first page. Here is my code:
...ANSWER
Answered 2021-Aug-18 at 08:11Welcome to the exciting world of web scraping!
First of all, great job you were on the good track. There are a few points to discuss though.
You essentially have 2 problems here.
1 - How to retrieve the HTML text for all pages (1, ..., 50)?
In web scraping you have mainly to kind of web pages:
- If you are lucky, the page does not render using javascript and you can use only
requests
to get the page content - You are less lucky, and the page uses JavaScript to render partly or entirely
To get all the pages from 1 to 50, we need to somehow click on the button next at the end of the page.
Why?
If you check what happens in the network tab from the browser developer, console, you see that a new query getting a JS script to generate the page is fetched for each click to the next button.
Unfortunately, we can't render JavaScript using requests
But we have a solution: Headless Browsers (wiki).
In the solution, I use selenium
, which is a library that can use a real browser driver (in our case Chrome) to query a page and render JavaScript.
So we first get the web page with selenium
, we extract the HTML, we click on next and wait a bit for the page to load, we extract the HTML, ... and so on.
2 - How to extract the text from the PDFs after getting them?
After downloading the PDfs, we can load it into a variable then open it with PyPDF2
and extract the text from all pages. I let you look at the solution code.
Here is a working solution. It will iterate over the first n pages you want and return the text from all the PDF you are interested in:
QUESTION
import xml
import bs4
from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup
my_url = 'https://wwwn.cdc.gov/nchs/nhanes/search/datapage.aspx?Component=Laboratory&CycleBeginYear=2003'
uClient = uReq(my_url)
page_html = uClient.read()
uClient.close()
page_soup = soup(page_html,'html.parser').findAll('tr')
print(page_soup[2])
...ANSWER
Answered 2021-Aug-09 at 22:50You'll have to treat the individual table columns differently. For some of them you want just the text, for others you want the hrefs.
QUESTION
ANSWER
Answered 2021-Aug-01 at 19:06Your class filter is not very specific.
The first and second elements are pointing to html nodes which do not contain the link. Thus you are getting error.
A more specific class to check could be: _13oc-S
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