approx | Approximate floating point equality comparisons | Math library
kandi X-RAY | approx Summary
kandi X-RAY | approx Summary
Approximate floating point equality comparisons and assertions for the Rust Programming Language.
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approx Key Features
approx Examples and Code Snippets
public static boolean isApproxEqual(double d1, double d2) {
double epsilon = .001;
if (Math.abs(d1 - d2) < epsilon) {
return true;
}
return false;
}
Community Discussions
Trending Discussions on approx
QUESTION
I'm trying to strip gif images from emails in order to save storage space in Outlook and our document management system.
Say for example you've got an email approx 2MB's in size and the gif is 1MB. I'm expecting the result of the file size of the email to be 1MB.
The first part uses MimeKit to remove the gif. The problem I find with this code is that if you are not debugging it doesn't reduce the file size by what I'd expect. I've found this is because the image is still in the html properties of the MimeMessage.
...ANSWER
Answered 2021-Jun-15 at 01:50You have 2 questions that I'll answer separately.
Why doesn't the size of the message shrink after I remove the gif attachments?
MIME can contain nested multiparts and in your case, it likely does because HTML mail with images are often within a multipart/related which is often within a multipart/alternative, like this:
QUESTION
When running the first "almost MWE" code immediately below, which uses conditional panels and a "renderUI" function in the server section, it only runs correctly when I comment out the 3rd line from the bottom, observeEvent(vector.final(periods(),yield_input()),{yield_vector.R <<- unique(vector.final(periods(),yield_input()))})
. If I run the code with this line activated, it crashes and I get the error message Error in [: subscript out of bounds
which per my research means it is trying to access an array out of its boundary.
ANSWER
Answered 2021-Jun-14 at 22:51Replace the line you commented out with this
QUESTION
I have a vector "x"
I can interpolate it on "n"
points, let's say 20
ANSWER
Answered 2021-Jun-12 at 22:23There are two ways to interpret your question. In your example, the vector x
should be y
since only provided one vector:
QUESTION
The project: for a list of meta-data of wordpress-plugins: - approx 50 plugins are of interest! but the challenge is: i want to fetch meta-data of all the existing plugins. What i subsequently want to filter out after the fetch is - those plugins that have the newest timestamp - that are updated (most) recently. It is all aobut acutality... so the base-url to start is this:
...ANSWER
Answered 2021-Jun-09 at 20:19The page is rather well organized so scraping it should be pretty straight forward. All you need to do is get the plugin card and then simply extract the necessary parts.
Here's my take on it.
QUESTION
I wanted to perform a simple calculation of the covariance within a more complex flask app. Below I created a minimal random example without flask (which is actually working) of the calculation causing the problems (in the flask/waitress setup).
...ANSWER
Answered 2021-Jun-14 at 09:34Updating all packages solved the issue
QUESTION
given a dataframe
...ANSWER
Answered 2021-Jun-13 at 02:32You can use complete
to create the missing sequence of period
and item
and for each combination sum
the quantity
value.
QUESTION
I have this dataframe (57 rows, 9 cols) called "newData" and I'm trying to replace the NA values with the interpolated approximations and plot the graph. I've tried using functions such as na.approx and interp1 but I haven't managed to do it. Any solutions on how I can tackle this?
years city SO2 NO2 O3 PM10 PM2.5 CO Benzen 2012 Tirane 6.30 23.83 55.79 35.44 19.24 0.43 3.95 2013 Tirane NA 27.30 51.03 32.56 16.45 NA NA 2014 Tirane 15.52 35.01 32.64 54.06 NA 0.85 2.76 ...ANSWER
Answered 2021-Jun-12 at 14:12You can use zoo::na.approx
-
QUESTION
I have a large dataframe (approx. 10^8 rows) with some sparse columns. I would like to be able to quickly access the non-null values in a given column, i.e. the values that are actually saved in the array. I figured that this could be achieved by df.[]
. However, I can't see how to access directly, i.e. without any computation. When I try
df..index
it tells me that it's a RangeIndex
, which doesn't help. I can even see when I run
df..values
, but looking through dir(df..values)
I still cant't see a way to access them.
To make clear what I mean, here is a toy example:
In this example is
[0,1,3]
.
EDIT: The answer below by @Piotr Żak is a viable solution, but it requires computation. Is there a way to access directly via an attribute of the column or array?
ANSWER
Answered 2021-Jun-12 at 12:36import pandas as pd
import numpy as np
df = pd.DataFrame(np.array([[1], [np.nan], [4], [np.nan], [9]]),
columns=['a'])
QUESTION
I am very new to postgreSQl and SQL and databases, I hope you guys can help me with this, i want to know which posts have the most amount of comments and which have the least amount of comments and the users need to be specified too.
...ANSWER
Answered 2021-Jun-11 at 11:38Good effort in pasting the whole dataset creation procedure, is what it needs to be included in order to make the example reproducible.
Let's start first with, how to join
several tables: you have your posts
table which contains the user_id
and we can use it to join with users
with the following.
QUESTION
im using Python regex. i have a situation that the text doesnt always return the same text in order to run my regex on. the text can come in 4 different options. i just need to return numerical value including any decimals
if it is the 1st 2 options it straight forward. if its the 3rd/4th option, it matches both. i only need to return the 1st occurrence, regardless if it has a decimal or not, just the first. i have this regex, but it matches both occurrences, i only need 1st occurrence.
what can i add to this regex in order to return the first occurrence (or whats better regex for my issue)
My regex is [approx. |Current ] distance(\d+\.?\d+) miles
ANSWER
Answered 2021-Jun-11 at 06:13There is a re.finditer(pattern, string, flags=0)
in python which:
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Install approx
Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.
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