fiducial | A LFTag and TopoTag implementation in Rust | Learning library

by kingoflolz Rust Version: Current License: MIT

X-Ray Key Features Code Snippets(1)Community Discussions(5)Vulnerabilities Install Support

kandi X-RAY | fiducial Summary

fiducial is a Rust library typically used in Tutorial, Learning, Example Codes applications. fiducial has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Implementation of two visual fiducial algorithms LFTag and Topotag algorithm in rust.

Support

Quality

Security

License

Reuse

Support

fiducial has a low active ecosystem.

It has 7 star(s) with 2 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

There are 1 open issues and 0 have been closed. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of fiducial is current.

Quality

fiducial has 0 bugs and 0 code smells.

Security

fiducial has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

fiducial code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

fiducial is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

fiducial releases are not available. You will need to build from source code and install.

It has 81 lines of code, 2 functions and 3 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

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fiducial Key Features

No Key Features are available at this moment for fiducial.

fiducial Examples and Code Snippets

Searches for farm areas where each area represents the fiducial .

java

Lines of Code : 21

License : Permissive (MIT License)

Copy

public int[][] findFarmland(int[][] land) {
        if (land == null || land.length == 0) {
            return new int[][] {};
        }
        int m = land.length;
        int n = land[0].length;
        for (int i = 0; i < m; i++) {

Community Discussions

Trending Discussions on fiducial

Using AprilTag python library on Windows 10?

BoofCV: Unresolved Compilation Problems

how to avoid mixture of \ and / in file paths when joining paths in Docker containerized Python code

jq merge objects after find in array

1D interpolation optimization on 3D data cube

QUESTION

Using AprilTag python library on Windows 10?

Asked 2022-Mar-15 at 00:11

I'm in need of a fiducial marker for a rover project as its primary control is image processing for steering down a driveway and when it gets to the end i need it to go to a precise location.

I was going to use ArUco tags but my version of OpenCV for the OpenVino framework doesn't support it. Then i tried to use AprilTags but i couldn't get it to install on my Windows 10 machine and later discovered its not supported on that OS. While my robot uses RaspPi i absolutely need my desktop environment for development and debugging.

Anyone get AprilTag library compiled for Windows Python 3? If not does anyone know of an alternate tag library (not ArUco) that is similar? I don't need anything fancy here - just something printed on a 4" x 4" (ish) piece of paper that my image processing pipeline can easily pick out of the image and i can then navigate to it. I don't even need to encode data on it - just need something unique to lock into.

Much appreciated!

...

ANSWER

Answered 2022-Jan-04 at 07:43

Intel® Distribution of OpenVINO™ Toolkit can also be installed through PyPI repository instead of installing the binary package that had compiled OpenCV community version.

Runtime package with the Inference Engine inside.
Developer package that includes the runtime package as a dependency, Model Optimizer, Accuracy Checker and Post-Training Optimization Tool.

Next, you can get the ArUco library that included in the opencv-contrib-python package which you can install via:

Source https://stackoverflow.com/questions/70545451

QUESTION

BoofCV: Unresolved Compilation Problems

Asked 2022-Feb-03 at 23:32

I'm using a Raspberry Pi (4) and hoped I'd be able to implement QR detection through a Rasp Cam. I found BoofCV that could do the job - so I copied the code from the ExampleDetectQrCode repo but its throwing a few errors...

...

ANSWER

Answered 2022-Feb-03 at 23:32

You need to import the "boofcv-swing" artifact to have the built in Swing components.

Source https://stackoverflow.com/questions/70962678

QUESTION

how to avoid mixture of \ and / in file paths when joining paths in Docker containerized Python code

Asked 2021-Oct-18 at 10:21

As far as I'm aware I'm using best practices to define paths (using raw strings) and how I go about joining them (using os.path.join()), e.g.

...

ANSWER

Answered 2021-Oct-15 at 16:32

From the actual behavior I can suppose that the container is based on Unix-like image. Path separator is / in such systems. To build an environment-independent path which works inside and outside of the container you need the following steps:

Mounting of host folder to container directory.
Environment variable inside and outside the container.

I can show an example of how this is achievable via docker-compose tool and its configuration file docker-compose.yml:

Source https://stackoverflow.com/questions/69587170

QUESTION

jq merge objects after find in array

Asked 2021-Jan-10 at 23:54

A generated config file (from ls) results in

...

ANSWER

Answered 2021-Jan-10 at 23:21

For relatively smaller input streams, you can "slurp" the objects and combine them into one array using the add function and the -s command-line option:

Source https://stackoverflow.com/questions/65651244

QUESTION

1D interpolation optimization on 3D data cube

Asked 2020-Jul-28 at 14:11

I would like to make a 1D interpolation on a 3D data cube in Python. I have 18 images taken at fiducial wavelengths. I want to make a 1D interpolation on each pixel to form a new image for 185 given specific wavelengths. My problem is a problem of optimization. I've already seen tricks like scipy.ndimage.map_coordinates but I don't think this can be applied on my problem and result as an optimized solution. The real problem is the size of my data : I'm working with a (18x1024x1024) data cube and want a new data cube in output of size (185x1024x1024). Is there a way to optimize the following code?

...

ANSWER

Answered 2020-Jul-28 at 14:11

I've found a way to avoid the two for loops, I've used directly the formula of the linear interpolation and adapted it for a matrix.

For example if I have my raw data with 18 different wavelengths and then a cube of data called data_cube of size 18x1024x1024, and I want to estimate the image at the k-th wavelength lambda_k which is located between the wavelength located at index_before=15 called W_i and index_before=16 W_j of my original data cube then :

Source https://stackoverflow.com/questions/63131381

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install fiducial

You can download it from GitHub.
Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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